Klp 2

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  • Kelompok 2 NIM Fadriani 1111097000009

    Nur Nabila Azhar 1111097000033

    Ryan Rizaldy 1111097000017

    A 0,200296

    L(awal) 2

    F L Stress Strain

    0 0 0 0

    1000 0,001 5000 0,0005

    3000 0,003 15000 0,0015

    5000 0,005 25000 0,0025

    7000 0,007 35000 0,0035

    7500 0,03 37500 0,015

    7900 0,08 39500 0,04

    8000 0,12 40000 0,06

    7950 0,16 39750 0,08

    7600 0,205 38000 0,1025

    0

    5000

    10000

    15000

    20000

    25000

    30000

    35000

    40000

    45000

    0 0,01 0,02 0,03 0,04 0,05 0,06 0,07 0,08 0,09 0,1 0,11

    STR

    ESS

    STRAIN

    KURVA STRESS VS STRAIN

    Deformasi plastis

    Deformasi Plastis

    Failure O Titik Luluh


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ù ÿ ü ù ÿ úÿùÿ úÿ .2 1 1 . 1 # 012)$ 2 0 20# .2 #/020!)2 2 ...

ùùÿ þ þüÿ þ ü ù ÿ úÿ 2 2. . 1$#!)20! ü#!+ !) 2& 2 + .2 0 ...

ùùÿ þ þüÿ þ ü ù ÿ úÿ 2 2. . 1$#!)20! ü#!+ !) 2& 2 + .2 0 ...

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~{EN}Catalog Optical Glass Collection Datasheets Inquiry Glass english … · B 1 »2 »2 - C 1 B 2 »2 »2 - C 2 B 3 »2 »2 - C 3 the refractive indices for any wavelength within

~{EN}Catalog Optical Glass Collection Datasheets Inquiry Glass english … · B 1 »2 »2 - C 1 B 2 »2 »2 - C 2 B 3 »2 »2 - C 3 the refractive indices for any wavelength within

+ 0 & 0 2 ! . · 2012-11-30 · + 0 & 0 2 ! . 294 0 2 ! & $ 0 2 ! 0 " / $ 2 ) # " # 2 2 . 1 0 . 1 0 2 ... + 0 & 0 2 ! . 295 1 ! 2 ! 1 ) 2 2 . " ( - +- ) ù / * 2 ! & . $ # / * 0 #

+ 0 & 0 2 ! . · 2012-11-30 · + 0 & 0 2 ! . 294 0 2 ! & $ 0 2 ! 0 " / $ 2 ) # " # 2 2 . 1 0 . 1 0 2 ... + 0 & 0 2 ! . 295 1 ! 2 ! 1 ) 2 2 . " ( - +- ) ù / * 2 ! & . $ # / * 0 #

BBBBBBBBBBBBBB /2*2 SURJUDPPLHUHQ

BBBBBBBBBBBBBB /2*2 SURJUDPPLHUHQ

!0 .2 #- + ù # ) ! $ . 2 3&.12!. + 12 · .2.1 .!.$ 0 . )2.1.! 3 ..#2 +. #3. 02. )2 $ # .2. . 0 .2.12. 0 12 ! . ! 3. +" * . 20 * !) . . 12 ) . 2 2! 3 .

!0 .2 #- + ù # ) ! $ . 2 3&.12!. + 12 · .2.1 .!.$ 0 . )2.1.! 3 ..#2 +. #3. 02. )2 $ # .2. . 0 .2.12. 0 12 ! . ! 3. +" * . 20 * !) . . 12 ) . 2 2! 3 .

Phy b11 2-2

Phy b11 2-2

5 A 4 I @ 0 G ; 0 @ C 4 0 · 2016-06-16 · í ñ * $ . # 2 . ! # 1 2 1 + . . " 1 2 1 2 # . " 1 2 0 2 1 2 " ) / . "

5 A 4 I @ 0 G ; 0 @ C 4 0 · 2016-06-16 · í ñ * $ . # 2 . ! # 1 2 1 + . . " 1 2 1 2 # . " 1 2 0 2 1 2 " ) / . "

0 + ! . ! . $ · 1 2 ! . ü . ! . $ " þ ! 1 . & " ) / ! 1 " & . 2 0 $ + . 2 1 2 + / & ù # 1 2 # 2 1 2 * 0 ! 2 " 1 2 " 0 1 . # 0 # "

0 + ! . ! . $ · 1 2 ! . ü . ! . $ " þ ! 1 . & " ) / ! 1 " & . 2 0 $ + . 2 1 2 + / & ù # 1 2 # 2 1 2 * 0 ! 2 " 1 2 " 0 1 . # 0 # "

03 . 12 . /!) 1 · 2016-06-08 · ù #1 # 02. 2& 0$ + ü3.! "0! 2+10& 89 03 . 12 . /!) 1 * % þ 12 . /!) 1 0!0# 2 !. ). 2 01 . ."0 .!2 " .2 ! " 02. 2 ". .3 ! 0 2 /! 1 + . 0 !2 2&

03 . 12 . /!) 1 · 2016-06-08 · ù #1 # 02. 2& 0$ + ü3.! "0! 2+10& 89 03 . 12 . /!) 1 * % þ 12 . /!) 1 0!0# 2 !. ). 2 01 . ."0 .!2 " .2 ! " 02. 2 ". .3 ! 0 2 /! 1 + . 0 !2 2&

Statistics Assignment 2-2

Statistics Assignment 2-2

ü ü .! ÿ ÿ 7 ÿ ù! 70 1 · 2018-08-03 · (i) 1 2 # 1 ) . 2 . ! + # 0 . (ii) 1 2 ) 2 2 . . / . 2 0 ! . 2 . ! 1 2 . 2 0 # ) 0 . 2 # .

ü ü .! ÿ ÿ 7 ÿ ù! 70 1 · 2018-08-03 · (i) 1 2 # 1 ) . 2 . ! + # 0 . (ii) 1 2 ) 2 2 . . / . 2 0 ! . 2 . ! 1 2 . 2 0 # ) 0 . 2 # .

แคดเมียมในปัสสาวะของผู้ป่วยโรคเบาหวานชนิดที2 ค่ลินิกโรค ... · /:+2:+&

แคดเมียมในปัสสาวะของผู้ป่วยโรคเบาหวานชนิดที2 ค่ลินิกโรค ... · /:+2:+&

2.omada3διαφημιση (2)

2.omada3διαφημιση (2)

1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 ...

1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 1 ...

h = ca. 44) Preview - OCP | OCP · 12$0 (2 ,7 & & & b b b 2 3 2 3 2 3 2 2 2 2 2 2 16 L ight from light, 1. S on of God. C hrist our light.

h = ca. 44) Preview - OCP | OCP · 12$0 (2 ,7 & & & b b b 2 3 2 3 2 3 2 2 2 2 2 2 16 L ight from light, 1. S on of God. C hrist our light.

2. Predavanja URBANIZAM 2

2. Predavanja URBANIZAM 2

Find the surface area of each. S = (Pℓ)/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2 S = (Pℓ)/2 + B = (10×6)(14)/2 + (8.7)(10×6)/2 = 679.8 ft.

Find the surface area of each. S = (Pℓ)/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2 S = (Pℓ)/2 + B = (10×6)(14)/2 + (8.7)(10×6)/2 = 679.8 ft.

0 +10 .2.1 0# · 2019. 1. 14. · 4 *! $.!. 2 ! 12 ) 2 #" 2 0 % .12 )2 2." 12 / . )!3&1 2 # 1+ .2 " .2 2. # . 2 $!) . 2. .2+20!0". 1 2 . 20$ 2! . ))2 2. 12 ü 12 0 $ õ &" .!2#! 0"2

0 +10 .2.1 0# · 2019. 1. 14. · 4 *! $.!. 2 ! 12 ) 2 #" 2 0 % .12 )2 2." 12 / . )!3&1 2 # 1+ .2 " .2 2. # . 2 $!) . 2. .2+20!0". 1 2 . 20$ 2! . ))2 2. 12 ü 12 0 $ õ &" .!2#! 0"2