Find the surface area of each. S = (Pℓ)/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2...
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Find the surface area of each. (Pℓ)/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2 (Pℓ)/2 + B (10×6)(14)/2 + (8.7)(10×6)/2 679.8 ft 2 8.7 S = (Pℓ)/2 + B = 2π(8)(√(15 2 +8 2 )/2 + π( = 200π ft 2 S = (Pℓ)/2 + B = 2π(√(8 2 -6 2 )(8)/2 + π(6 = 70.3π m 2
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Transcript of Find the surface area of each. S = (Pℓ)/2 + B = (20×3)(15)/2 + 20√(10 2 +20 2 )/2 = 623.2 in 2...
Find the surface area of each.
S = (Pℓ)/2 + B = (20×3)(15)/2 + 20√(102+202)/2 = 623.2 in2
S = (Pℓ)/2 + B = (10×6)(14)/2 + (8.7)(10×6)/2 = 679.8 ft2
8.7
S = (Pℓ)/2 + B = 2π(8)(√(152+82)/2 + π(82) = 200π ft2
S = (Pℓ)/2 + B = 2π(√(82-62)(8)/2 + π(6.92) = 70.3π m2
Ch 12.5Volumes of
Pyramids & Cones
Standard 9.0Students compute the volumes of pyramids and cones and commit to memory the formulas for
pyramids.
Learning Target:I will be able to solve problems involving the volume of pyramids and cones.
Theorem 12-11
Volume of a Pyramid
Find the volume of the square pyramid.
Answer: The volume of the pyramid is 21 cubic inches.
Volume of a pyramid
Multiply. 21
s 3, h 7
Brad is building a model pyramid for a social studies project. The model is a square pyramid with a base edge of 8 feet and a height of 6.5 feet. Find the volume of the pyramid.
A. 416 ft3
B.
C.
D.
Volume of a pyramid
B = s2 , s = 8 , h = 6.5
Multiply.
= (64)(6.5)
= 138.7
V = Bh1313
Theorem 12-12
Volume of a Cone
A. Find the volume of the oblique cone in terms of π.
Simplify
B = π r2
r = 9.1, h = 25
= 690π
Volume of a coneV = Bh13
Volume of a Cone
B. Find the volume of the cone in terms of π.
Simplify.
Volume of a cone
r = 5, h = 12
= 100π
B = π r2
V = Bh13
A. 141π m3
B. 8746π m3
C. 112π m3
D. 2915π m3
A. Find the volume of the oblique cone in terms of π.
Volume of a cone
B = π r2 , r = 20.6 , h = 20.6
Multiply.
= π(424.36)(20.6)
= 2915π
V = Bh1313
A. 960π m3
B. 40π m3
C. 320π m3
D. 880π m3
B. Find the volume of the cone in terms of π.
Volume of a cone
B = π r2 , r = 8 , h = 15
Multiply.
= π(64)(15)
= 320π
V = Bh1313
Find Real-World Volumes
SCULPTURE At the top of a stone tower is a pyramidion in the shape of a square pyramid. This pyramid has a height of 52.5 centimeters and the base edges are 36 centimeters. What is the volume of the pyramidion? Round to the nearest tenth.
Volume of a pyramid
B = 36 ● 36, h = 52.5
Simplify.
= s2 h13
B = s2
A. 18,775 cm3
B. 19,500 cm3
C. 20,050 cm3
D. 21,000 cm3
SCULPTURE In a botanical garden is a silver pyramidion in the shape of a square pyramid. This pyramid has a height of 65 centimeters and the base edges are 30 centimeters. What is the volume of the pyramidion? Round to the nearest tenth.
Volume of a pyramid
B = s2 , s = 30 , h = 65
Multiply.
= π(900)(65)
= 19500
V = Bh1313
