Μαθηματικά Κατεύθυνσης Απαντήσεις Θέματων...

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Μαθηματικά Κατεύθυνσης Απαντήσεις Θέματων Πανελληνίων 2013

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  • 2013

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    | | 2013 | |

    |

    1. 2. 3. 4. / / / /

    |

    1. 0=-2|2-z|+|2-z|2=|2-z|+|2-z|2=|2-z|+)2-z2)(-z(2=|2-z|+2)-z2)(-z( 22 ()

    |z 2| = 1 (2,0) = 1

    pi , pipi |z|

    3

    2. O z1, z2 w2+w+ = 0 Im(z1) = - Im(z2) pi 1=)zIm(1=|)zIm(|2=|)zIm(2|2=|)Im(z-)zIm(| 11121 Rmi,-m=z,i+m=z 21

    z1 |z 2| =1 2=m1=1+)2-m(1=|i+2)-(m|1=|2-i+m|1=|2-z| 221 Rmi,-2=z,i+2=z 21 Vieta -=z+z=S 21 -4=

    5==zz=P 21

    ,

    2=|)Im(z-)zIm(| 21 z1, z2 ( pi ) pi (z1), B(z2) 2 = 2 (=1)

    1)0,2(K

    30

  • 2013

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    3. o1

    22

    3 a-va-v-a=v

    3+|v|3+|v|3|a|+|va|+|va||a-va-v-a|=|v| 2o122o1223 pi

    1-3+|v|3+|v|3|v|3+|v|3+|v|3|v| 2323 -1 -1 1-)1+|v|+|v(|3|v| 23

    -1

    1+|v|+|v|1

    -31+|v|+|v|

    |v|22

    3

    )-1)(

    1+|v|+|v|1

    -31+|v|+|v|

    1+|v|+|v||v(|22

    2

    -1|v1+|v|+|v|

    1-3| 2

  • 2013

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    H K(x) = (0, )+ () = ( )x(Klim

    0x)x(Klim

    +x) = (-2, + )

    0 )+-2,( (x) = 0 = (0, )+

    pi f(g(x)) = 1

    3.

    04pi

    -x

    dt)t(fx=)x(h [0, pi/4), pi (0, pi/4)

    )4pi

    -f(xx-dt)t(fx=)x(h 04pi

    -x

    h(0) = h(pi/4) = 0 pi .Rolle pi )

    4pi

    ,0(x o 0=)x(h o

    0=)4pi

    -f(xx-dt)t(fx oo0

    4pi

    -x

    o

    o

    )4pi-f(xx=dt)t(fx oo04pi

    -x

    o

    o

    )

    4pi

    -f(xx

    x=dt)t(f o

    o

    o0

    4pi

    -xo

    )4pi-f(xx=dt)t(f oo04pi

    -xo

    |

    1.

    0=h

    h)-f(1-f(1)+f(1)-5h)+f(1lim0=

    hh)-f(1-5h)+f(1

    lim0h0h

    0(1)f0(1)f60(1)f(-1)-(1)f5

    ===0=)h

    f(1)-h)-f(1-

    hf(1)-5h)+f(1(lim

    0h

    :

    )x(f a=h

    )f(x-)ah+x(flim o

    oo

    0h

    )x(f

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    2.

    0>1-x

    1-)x(f=)x(g * x > 1 g (1, + )

    * .1.

    1+xx

    du)u(g=)x(h , x > 1 g(x)-)1+x(g=)x(h > 0 h (1,+ )

    : < + 1 g

    g() < g(+1)

    g(+1) g() > 0

    )5+x2(h>)5+x8(h 42 1>5+x2,1>5+x8 42 h

    (1,+

    ) (0,2)(-2,0)x0>)x->x-x4>x2-x8x2>x85+x2>5+x8 242424242 (4x00 2

    3.

    f [1, x] pi )x,1(

    1-x1-)x(f

    =

    1-xf(1)-)x(f

    =)(f

    pi 01)-(f(x)-1)-(x)(xf1)-(x)(xf1-f(x) >