Mathcad_-_ej5
1
q 16 := Continuidad me ms = m = Wc 500 := Energía o 1ra ley Entrada Salida Ps 1000 := m he ⋅ Wc + Q − m hs ⋅ = Pe 100 := Te 22 273.15 + := he w + q − hs = Te 295.15 = Caudale 150 60 := R 0.287 := Caudale 2.5 = ρe Pe R Te ⋅ := ρe 1.181 = me ρe Caudale ⋅ := Q me q ⋅ := Q 47.221 = me 2.951 = he 295 := hs me he ⋅ Wc + Q − me := hs 448.416 = Ts 447 :=
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Transcript of Mathcad_-_ej5
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q 16:=Continuidad me ms= m=Wc 500:=
Energa o 1ra ley Entrada Salida Ps 1000:=m he Wc+ Q m hs= Pe 100:=
Te 22 273.15+:=he w+ q hs= Te 295.15=Caudale
15060
:=R 0.287:= Caudale 2.5=
ePe
R Te:=e 1.181=
me e Caudale:=Q me q:= Q 47.221= me 2.951=
he 295:=hs me he Wc+ Qme
:= hs 448.416=Ts 447:=
