MATEMATICA II.pdf

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  UNIVERSIDAD NACIONAL DEL CALLAO MATERIA: MATEMATICA II DOCENTE: NILTON SARAVIA ALUMNA: CHAUCA SANCHEZ ANALIZ TATIANA TEMA: EJERCICIOS

Transcript of MATEMATICA II.pdf

  • UNIVERSIDAD NACIONAL DEL CALLAO

    MATERIA: MATEMATICA II

    DOCENTE: NILTON SARAVIA

    ALUMNA: CHAUCA SANCHEZ ANALIZ TATIANA

    TEMA: EJERCICIOS

  • CICLO VERANO

    2015

    45) L: y=2 ; : y= 0 , x= 0 , y=2

    Y

    Y=lnx

    y=2

    1 x

    V= 2 02 (y-2) (ey-0) dy

    V= 202(y.ey-2ey)dy

    V=2[y-ey-ey-2ey]02

    V=2[y-ey-3ey]02

    V= 2[2e2-3e1+3e0]

    V=2[3-e2]

  • 46) L: x= e3 , : y=lnx , y=0 , x=0 , y=2

    Y

    y=lnx

    2 y=0

    0 1 x

    V=02[ey-e3]dy

    V= 02[e2y-2e3-ey+e6]dy

    V= [e2y/2 2e3e4+e6y]02

    V=[e4/2-2e3.e2+e6.2-1/2 +2e3]

    V= [e4/2 -2e3+2e6+2e3 1/2]

  • 47)

    4

    Y=4-x2

    -2 0 2

    V=2 -22(x+2)(4-x3)dx

    V= 2-22(4x-x3+8-2x2)dx

    V=2[2x2-x4/4 +8x-2/3x3]-22

    V=2[2(22-(-2)2)-(24-(-2)4/4)+8(2+2)-2/3(23-(-2)3)]

    V=2[64/3]

    V=128/3 3

  • 48) y x=y

    Y=

    X=2

    0 4 x

    = [10 2] ( 2) ]

    = [4 ( 4 4)]

    = [4 4 4]

    = [4 ]

    = [42

    3

    2]4

    0

  • = [8

    3 4

    ] =

    40

    3

    49) y

    X=1 x=y

    1 4 x

    Y=-2

    V= [(

    2 ]

    = [( 1

    2 4 (

    1

    4]

    = [ 2 1

    4

    4

    4]

    = [

    2

    8

    3 8 2 ]

  • = [4 1

    2 4 4

    8

    3 (4

    1

    )

    8

    3(4 1)

    2(4 1 ]

    = [(1

    2 4

    8

    3) (4

    1

    ) 8(2 1 2 3]

    = ( 4 14

    6)

    y

    50) x=yseny

    0 15

    x

    = 2 ( 2 (

    6 )

    = 2 [

    6

    2

    6 2 ]

  • = 2 [

    6

    2 2 2

    3

    2( ]

    60

    = 2 [

    12 2 2

    3

    2 ]

    60

    = [

    432

    36 3

    2

    2

    6

    6 2

    6

    3(

    3) 2

    6

    2

    6

    6 2 0]

    = 2 [

    432

    3

    2

    6

    23

    2

    2 (

    1

    2)

    3

    3

    2

    2]

    = 2 [

    432 (

    3

    2

    1

    ) (

    1

    6

    3

    6) 1 3]

  • 51)

    0

    = (

    )

    =

    = (1

    )

    = [ ( ]

    40

  • = [

    4

    [ (

    4

    4) ( ]]

    = [2

    2 [

    2

    2 1] ( ]

  • 52)

    Y

    x=1

    y=(x+1)cx

    0 1 x

    = ( 1

    = ( 2 2

    = [( 2 1

    2

    (2 2

    4

    2

    8

    ]1

    0

  • = [4

    2

    4

    4

    4

    (1

    2

    2

    4

    1

    4)]

    = [

    4 (

    1

    2

    1

    2

    1

    4)]

    =

    53) L: X=0

    y

    x

    = 2

    = 2

    2

    1

    0

    = 1

    0

    = [ ]

  • = [ 1]

    54) x=1 x=3

    V=213(7-x)(x.e2x)dx

    V=213 [7xe2x-x2e2x]dx

    V=2[ (xe2x/2 e2x/4)-(x2e2x/2 -2xe2x/4 +2e2x/8)]13

    V= 2[ xe2x/2 7e2x/4 x2.e2x/2 +x.e2x/2-e2x/4 ]13

    V=2[(21/2e6-7/4.e6- 9/2e6+3/2e6-e6/4)-(7/2e2-7/4e2-

    1/2e2+1/2e2-e2/4)]

    V=2[11/2 e6-3/2e2]

    V=[11e6-3e2]

  • 55) y=-1 y=lnx y=0 ,x=e

    X=e

    Y=lnx

    1 e

    = ([ 1] [0 1]

    = [ 2 1]

    = [ 2 2( ]

    1 ( 1

    = [ 2 2 2 ]

    1 ( 1

    = [ ]

    1 ( 1

  • = [ 1 1 1 1]

    = [ (1 1(0 ]

    =