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Surface Area of Circular Solids Lesson 12.3
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Transcript of Surface Area of Circular Solids Lesson 12.3
Surface Area of Circular SolidsLesson 12.3
cylinder
cone
sphere
Cylinder: Contains 2 congruent parallel bases that are circles.Right circular cylinder perpendicular line from center to each base.
Net:h
r
Theorem 113: The lateral area of a cylinder is equal to the product of the height and the circumference of the base.
LAcyl = Ch = 2πrh(C = circumference, h= height)
h
r
The total area of a cylinder is the sum of the cylinder’s lateral area and the areas of the two bases.T.A. = 2πr2 + 2πrh
Find the surface area (total) of the following cylinder:
10cm
7cmTA = 2πr2 + 2πrhTA = 2π(72) + 2π(7)(10)TA = 98π + 140πTA = 238π cm2
Cone: base is a circleSlant height and lateral height are the same.
l
Cone will mean a right cone where the altitude passes through the center of the circular base.
Net:
Theorem 114: The lateral area of a cone is equal to1/2 the product of the slant height and the circumference of the base.
LA = ½Cl = πrlC = Circumference & l = slant height
Find the surface area of the cone.The diameter is 6 & the slant height is 8.
TA = πr2 + πrl = π(3)2 + π3(8) = 9π + 24π = 33π units2
The total surface area of a cone is the sum of the lateral area and the area of the base. TA = πr2 + πrl
Sphere: has NO lateral edges & No lateral areaPostulate: TA = 4πr2 r = radius of the sphere
Find the total area of the sphere:
TA = 4πr2
= 4π52
= 100π units2
As a team, find the surface area of the following shape. Only find the area of the parts you can see.
16cm
10cm
17cm
1. Lateral area of a cone,2. Plus the lateral area of the cylinder,
3. Plus the surface of the hemisphere.
πrl = π8(17) = 136π
2πrh = 2π(8)(10) = 160π
4πr2 = (1/2)4π(82) = 128π
4. Add them up: 136π + 160π + 128π = 424π units2