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solucionario Análisis de circuitos en ingeniería 7ed (hayt, kemmerly), las respuestas pero no el procedimiento

### Transcript of solucionario Anlisis de circuitos en ingenier­a 7ed (hayt, kemmerly)

• 1.CHAPTER 2 ENGINEERING CIRCUIT ANALYSIS SELECTED ANSWERS 1. (a) 12 s (d) 3.5 Gbits (g) 39 pA (b) 750 mJ (e) 6.5 nm (h) 49 k (c) 1.13 k (f) 13.56 MHz (i) 11.73 pA 3. 300 kW; 3.7 m; 25 mm; 71 kJ; 290 fs 5. 131 kW; 1.4 GJ; 1 battery 7. 13 GW; 100 mW 9. 290 kJ; 1.5 kJ 11. 6.2 A; 3.5 A; The current is never negative; 34 C 13. 12 MV; 0; -18.7 MV; -6.2 MV 15. -6.4 mW; -120 W; 60 W; 12 W 17. 73 W; -36 W; 28 W 19. 5 mW, 0, -2 mW; 36 J; 22 J 21. 64 W, 256 W, -640 W, 800 W, -480 W 23. -1 mV 25. 58 W; 4.8 A 27. 5.6 mA, 4.5 mA; 23 mW, 28 mW 29. 43.5 mW; 231 mW; 253 mW 31. Since we know that the total power supplied is equal to the total power absorbed, we may write: Vs I = I2 R1 + I2 R2. Now invoke Ohms law. 33. 500 A, 2.5 mW; -500 A, 2.5 mW; -500 A, 2.5 mW; 500 A, 2.5 mW 35. -2 V (at t = 0.324 s) 37. 2 km. Hmmmm. 39. 1.7 . cm 41. 560 m, 1.3 W 43. 266 m; 514 mA 45. Design. Many possible solutions. Hint: Start with finding resistivity, then choose geometry. Copyright 2007 The McGraw-Hill Companies, Inc. All Rights Reserved.