Mathcad - c12 4a - WERKTUIGBOUW.NL Design of a circular aerostatic thrust bearing with inherent...

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T 293 K := ρ 0 1.208 kg m 3 := κ 1.4 := 1) Load capacity: 2 ) Flow rate: 3) Dimensions orifice restrictor: 4 ) Axial bearing stiffness Load capacity: F 46.196N = Dimensionless load capacity: F 1 0.0919 = Ae_A 0.153 = S 12.3210 6 N m = Axial bearing stiffness: Pressure after the restrictor: p r p s 0.68 = Flow : M 4.167 10 7 - × kg s = Q 0.021 liter min = Diameter inherent orifice: d a 0.167mm = C12_4a Design of a circular aerostatic thrust bearing with inherent orifice restrictor. Problem: Aerostatic thrust bearing shown in Fig.12.13a. MPa 10 6 Pa := Diameter bearing: D 0 40 mm := R 0 0.5 D 0 := R 0 20mm = Dimameter orifice: D 1 0.167 mm := R 1 0.5 D 1 := R 1 0.084mm = Film thickness: h 0 5 10 6 - m := Supply pressure: p s 0.5 MPa := Ambient pressure: p a 0.1 MPa := Pressure factor: β 0 0.6 := Coefficient of discharge: C D 0.7 := Gas properties: η 18 10 6 - Pa s := R 287 m 2 s 2 K :=

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T 293 K⋅:=

ρ0 1.208kg

m3

⋅:= κ 1.4:=

1) Load capacity:

2 ) Flow rate:

3) Dimensions orifice restrictor:

4 ) Axial bearing stiffness

Load capacity: F 46.196N=

Dimensionless load capacity: F1 0.0919= Ae_A 0.153=

S 12.32106 N

m⋅=

Axial bearing stiffness:

Pressure after the restrictor:pr

ps

0.68=

Flow : M 4.167 107−

×kg

s= Q 0.021

liter

min=

Diameter inherent orifice: da 0.167mm=

C12_4aDesign of a circular aerostatic thrust bearing with inherent orifice restrictor.

Problem: Aerostatic thrust bearing shown in Fig.12.13a.MPa 10

6Pa⋅:=

Diameter bearing: D0 40 mm⋅:= R0 0.5 D0⋅:= R0 20mm=

Dimameter orifice: D1 0.167 mm⋅:= R1 0.5 D1⋅:= R1 0.084mm=

Film thickness: h0 5 106−

⋅ m⋅:=

Supply pressure: ps 0.5 MPa⋅:=

Ambient pressure: pa 0.1 MPa⋅:=

Pressure factor: β0 0.6:=

Coefficient of discharge: CD 0.7:=

Gas properties: η 18 106−

⋅ Pa⋅ s⋅:= R 287m2

s2K⋅

⋅:=