MAT01A1: Complex Roots & Intro to Logic - Andrew Craig · 2020. 2. 21. · MAT01A1: Complex Roots &...
Transcript of MAT01A1: Complex Roots & Intro to Logic - Andrew Craig · 2020. 2. 21. · MAT01A1: Complex Roots &...
MAT01A1: Complex Roots & Intro to Logic
Dr Craig
18 February 2020
From powers to roots in CSuppose we want to find the n-th root of
z = r(cos θ + i sin θ). That is, we want the
complex number w = s(cosϕ + i sinϕ) such
that wn = z. From De Moivre’s Theorem we
want
sn(cosnϕ + i sinnϕ) = r(cos θ + i sin θ)
To get this, we need
sn = r and cosnϕ = cos θ and sinnϕ = sin θ
Thus nϕ = θ + 2kπ.
Roots of a complex number: n-th roots
Let z = r(cos θ + i sin θ) and let n be any
positive integer.
Then z has n distinct n-th roots. That is,
for k = 0, 1, 2, . . . , n− 1 the roots are
wk = r1/n
[cos
(θ + 2kπ
n
)+ i sin
(θ + 2kπ
n
)]All of the roots of z lie on the circle of radius
r1/n in the complex plane.
It often helps to think of the argument of a
complex root in the following way:
θ + 2kπ
n=θ
n+ k
(2π
n
)The argument of the first root will simply beθn (because k = 0). Each root after that has
the same modulus (r1/n) but is rotated
anti-clockwise by 2πn . You only need to
calculate solutions up to k = n− 1. If you let
k = n then you will have the same complex
number as w0 but with a different argument.
Example of roots of a complex number
Find the cube roots of z = i.
Note that a = 0 and b = 1. Thus we get
r = 1 and arg(z) = θ =π
2
Solutions to 3√i
w0 =3√1(cos(π6
)+ i sin
(π6
))w1 =
3√1
(cos
(π
6+
2π
3
)+ i sin
(π
6+
2π
3
))w2 =
3√1
(cos
(π
6+
4π
3
)+ i sin
(π
6+
4π
3
))Exercise: convert each solution to the form
a+ bi. You will see that w2 is a solution that
you might have found by inspection.
Another exercise:
Take w0, w1 and w2 and cube each of them
using the rectangular form (a + bi). Check
that in each case you get i as the solution.
Also, look at Example 7 on page A62 of the
textbook.
LOGIC
Notes for this section have been uploaded to
Blackboard as a pdf under “Course content”.
Please take the time to read these printed
notes.
Introduction
Mathematics is about reasoning. In this course weprove certain facts about real numbers, aboutfunctions, about differentiation, etc.
In order to prove mathematical statements we needa system of reasoning. The next few lectures onlogic provide a mathematical foundation for thesystem of reasoning that we will use.
Instead of using numbers, our newelements/variables are propositions. Instead ofoperations like +,−,×,÷, we use logical operationswhich operate on our propositions.
Introduction continued...
Language is very important in logic. We are
translating statements from English into a
mathematical language.
Our mathematical language will be very
precise, therefore we also have to be very
precise about our use of the English
language.
Please ask if there is something that doesn’t
make sense.
Logic at UJ:
Dr Wilmari Morton, Dr Claudette Robinson
& Dr Craig.
We conduct research into non-classical and
multivalued logics.
We collaborate with researchers from the
Netherlands, Sweden, Italy, Slovakia.
In 2016 we hosted LATD (an international
logic conference) in Phalaborwa.
Some famous logicians:
I George Boole (Boolean logics/circuits)
I Kurt Godel (completeness of first-order
logic and incompleteness theorem)
I Bertrand Russell (Russell’s paradox)
I Alfred Tarski (pea and the sun paradox)
Propositions
Definition: A proposition is a statement that iseither true or false, but not both.
Examples:
I UJ is in Johannesburg.
I Durban is the capital of South Africa.
I 3 plus 3 equals 6.
I 3 plus 3 equals 5.
Note: a proposition does not have to be true. Butit can’t be both false and true, and it can’t beneither true nor false.
Definition: A proposition is a statement that iseither true or false, but not both.
The following are not propositions:
I Are you tired? (Not a statement.)
I She is a college student.(The truth value depends on who ‘she’ is.)
I x is a rational number.(The truth value depends on what x is.)
I This statement is false.(If it is true, then it must also be false, acontradiction. If it is false, then it must be true.Again, a contradiction.)
Logical connectives
not negation ¬and conjunction ∧or disjunction ∨if ... then ... implication →if and only if biconditional ↔
Suppose p is the primitive proposition “2 is a primenumber” and q is the proposition “The sun is hot”.Then¬p “2 is not a prime number”
p ∧ q “2 is a prime number and the sun is hot”
q → p “If the sun is hot, then 2 is a prime number”
Truth values for logical connectives
For negation:
p ¬pT FF T
For conjunction:
p q p ∧ qT T T
T F FF T FF F F
For disjunction:
p q p ∨ qT T TT F TF T TF F F
In ordinary language ‘or’ is often used in anexclusive sense, e.g. in ‘I will win or I will lose’. Informal logic ‘or’ is used in an inclusive sense, thus‘It will rain or it will be cold’ will still be true if it isboth rainy and cold.
In CompSci you might have seen this difference withthe logical command XOR (exclusive OR).
For implication (here we call p the “antecedent”and q the “consequent”):
p q p→ q
T T TT F FF T TF F T
For the biconditional:
p q p↔ q
T T TT F FF T FF F T
Computing truth values for propositionsThe truth value of a compound proposition dependson the truth values of its primitive propositions.Suppose we have:
I “Dineo is clever” is true
I “Dineo is lazy” is false
I “Dineo likes mathematics” is true
We can now calculate whether the followingsentence is true or false:
“Dineo is not clever, or, if she likes mathematics,then she is clever and is not lazy”
¬p ∨ (r → (p ∧ ¬q))
BODMAS for logical connectives
The order of priority is as follows:
1. ¬2. ∧ and ∨3. →4. ↔
For example:
¬p→ q = (¬p)→ q
p ∧ q → r = (p ∧ q)→ r
p ∨ q ↔ r = (p ∨ q)↔ r
p→ q ↔ r = (p→ q)↔ r