1

1

X

Y

Z

3850

FEM model

Fcos(t)=(m ・ a)cos(t)

A: Amplitudeδst: Static deformationζ: Damping ratio(2%)ωn: Natural frequency (Support tube)ω: Frequency

If =n, A=25

2

Estimation of Acc.

Data: Vertical @ATF(17:00 Feb. 10, 2004)

€∏fi é¸îgêî (0.1 1 10

1E-6

1E-7

1E-8

1E-9

Linear Spectrum

2x10-7m/s2

Input Acc. = 2x10-7m/s2

Mass=90tons/9.8[m/s2]

Self weight

3

1

X

Y

Z

Fcos(t)=(m ・ a)cos(t)

Calculation(1)

QC-L:Tungsten(100mm)

QC-R:Tungsten(100mm)

CFRP(3mm,5mm,10mm)

Get amplitude difference between QC-L and QC-R.

0 – 1000Hz

QC-L: Tungsten 100mmQC-R: Tungsten 100mmCFRP: 3mm, 5mm, 10mmf= 0Hz

4

1

X

Y

Z

JUN 18 200416:14:22

DISPLACEMENT

STEP=1SUB =1FREQ=76.006DMX =.181E-06

1

X

Y

Z

JUN 18 200416:25:34

DISPLACEMENT

STEP=1SUB =1FREQ=81.396DMX =.117E-06

1st mode 2nd mode

Same phase Opposite phase

Difference: QC-L and QC-R

Amplitude: QC-L and QC-R

100mm 100mm5mm

In case of 100mm-5mm(CFRP)-100mm, f=0Hz

5

Amplitude: CFRP=3mm

Amplitude: CFRP=10mm

Amplitude Difference

f= 0Hz

6

1

X

Y

Z

Fcos(t)=(m ・ a)cos(t)

Calculation(2)

QC-L:Tungsten(100mm)

QC-R:Tungsten(100mm) EQC-R=0.97xEQC-L

CFRP(3mm,5mm,10mm)

Get amplitude difference between QC-L and QC-R.

0 – 1000Hz

QC-L: Tungsten 100mmQC-R: Tungsten 100mm EQC-R=0.97xEQC-L

CFRP: 3mm, 5mm, 10mmf= 1Hz

7

1st mode 2nd mode

Same phase Opposite phase

Difference: QC-L and QC-R

Amplitude: QC-L and QC-R

In case of 5mm(CFRP), f=1Hz

1

X

Y

Z

JUN 18 200415:47:17

DISPLACEMENT

STEP=1SUB =1FREQ=75.272DMX =1.197

1

X

Y

Z

JUN 18 200415:47:38

DISPLACEMENT

STEP=1SUB =2FREQ=78.24DMX =.895538

8

Amplitude: CFRP=3mm

Amplitude: CFRP=10mm

Amplitude Difference

f= 1Hz

9

1

X

Y

Z

Fcos(t)=(m ・ a)cos(t)

Calculation(3)

QC-L:Tungsten(100mm)

QC-R:Tungsten(100mm) EQC-R=0.922xEQC-L

CFRP(3mm,5mm,10mm)

Get amplitude difference between QC-L and QC-R.

0 – 1000Hz

QC-L: Tungsten 100mmQC-R: Tungsten 100mm EQC-R=0.922xEQC-L

CFRP: 3mm, 5mm, 10mmf= 3Hz

10

1st mode 2nd mode

Same phase Opposite phase

Difference: QC-L and QC-R

Amplitude: QC-L and QC-R

In case of 5mm(CFRP), f=3Hz

1

X

Y

Z

JUN 18 200415:36:43

DISPLACEMENT

STEP=1SUB =1FREQ=73.738DMX =1.222

1

X

Y

Z

JUN 18 200415:37:02

DISPLACEMENT

STEP=1SUB =2FREQ=77.816DMX =1.05

11

Amplitude: CFRP=3mm

Amplitude: CFRP=10mm

Amplitude Difference

f= 3Hz

12

1

X

Y

Z

Fcos(t)=(m ・ a)cos(t)

Calculation(4)

QC-L:Tungsten(100mm)

QC-R:Tungsten(100mm) EQC-R=0.870xEQC-L

CFRP(3mm,5mm,10mm)

Get amplitude difference between QC-L and QC-R.

0 – 1000Hz

QC-L: Tungsten 100mmQC-R: Tungsten 100mm EQC-R=0.872xEQC-L

CFRP: 3mm, 5mm, 10mmf= 5Hz

13

1st mode 2nd mode

Same phase Opposite phase

Difference: QC-L and QC-R

Amplitude: QC-L and QC-R

In case of 5mm(CFRP), f=3Hz

1

X

Y

Z

JUN 18 200413:24:17

DISPLACEMENT

STEP=1SUB =1FREQ=71.548DMX =1.228

1

X

Y

Z

JUN 18 200413:25:45

DISPLACEMENT

STEP=1SUB =2FREQ=76.786DMX =1.154

14

Amplitude: CFRP=3mm

Amplitude: CFRP=10mm

Amplitude Difference

f= 5Hz