|AB|sin θ21

= |A0 A|sin β

β = sin−1[|A0 A||AB|

. sin θ21] β = f (θ21)

|A0B|2 = |A0 A|2 + |AB|2 - 2.|A0 A|.|AB|. cosα (1)

|AB|2 = |A0 A|2 + |A0B|2 - 2.|A0 A|.|A0B|. cosθ21 (2)

|A0 A|2 = |AB|2 + |A0B|2 - 2.|AB|.|A0B|. cosβ (3)

(2) denkleminden (3) denklemini çıkaralım.

|AB|2 - |A0 A|2 = |A0 A|2 + |A0B|2 - 2.|A0 A|.|A0B|. cosθ21 - |AB|2 - |A0B|2 + 2.|AB|.|A0B|. cosβ

2|AB|2 - 2|A0 A|2 = 2|A0B|.[|AB|.cos β−|A0 A|.cos θ21 ]

|A0B|=|AB|2−|A0 A|

2

|AB|.cos β−|A0 A|.cos θ21

|A0B|=f (θ21)

(1) denkleminden "α" çekilirse;

α = cos-1 (|A0 A|2+ |AB|2

- |A0 B|2

2.|A0 A| . |AB| ) α = f (θ21)

x = |A0 A| . sinθ21

y = h - x

sin γ = y

|AD| , γ=¿ sin-1 y

|AD| γ = f (θ21)

θ21=2π=360 °

β = sin−1[|A0 A||AB|

. sin θ21] = sin−1[2055

. sin 360]β = 0°

|A0B|=|AB|2−|A0 A|

2

|AB|.cos β−|A0 A|.cos θ21

= 552−202

55 .cos0−20 .cos 0

|A0B|=75cm

α = cos−1 (|A0 A|2+ |AB|2

- |A0 B|2

2.|A0 A| . |AB| )=cos−1( 202+552−752

2.20 .55 )α = 180°

x = |A0 A| . sinθ21 = 20 . sin0

x = 0y = h - x → y = h = 43 cm

γ=¿ sin-1 y

|AD| = sin-1 4377

γ=34 °