Ejemplo 1

R= 280

E= 6.20

PI = 0+580

E= r(sec (α/2) -1)

6.2/280=sec(d/2)-1

0.02217+1 = sec(α/2)

1.02214=(1/cos(α/2)

α/2= arcos(0 .98)

α=23.89=23°53°38.29°

Lc= 2πrα/360

Lc=( π*280*23.89)/180

Lc= 116.749

Subtang E = Rtang (α/2)

Subtang E =280tang(11.95)

Subtang E =59.21m

M= R(1-cos(α/2))

M=280(1-cos11.95))

M=6.07m

Pc=0+580.63-59.21 =0+521.42

Pt=0+521.42+116.75= 638.17

Ϫ О L parc L Acumula α Parc α AcumulaPc 0+521.42 540 18.58 18.58 1°54°4.63° 1°54°4.63° 560 20 38.58 2°2°47.73° 3°56°52.36° 580 20 58.58 2°2°47.73° 5°59°40.09° 600 20 78.58 2°2°47.73° 8°2°27.82° 620 20 98.58 2°2°47.73° 10°5°15.55° 638.17 18.17 116.75 1°51°33.59° 11°10°49.14°

Ejemplo 2

E=7.2m

M=6.8m

Pi= 6+310.08

M= R(1-cos(α/2))

E= r(sec (α/2) -1)

M/(1-cos(α/2))= E/(sec (α/2) -1)

M/E= Cos(α/2)

6.8/7.2= cos (α/2)

α=2*19.88

α=38°22°34.58°

Subtang E = Rtang (α/2)

Subtang E =122.4 *tg19.188

Subtang E =42.60m

Lc= 2πrα/360= 38°22°34.58°*122.4*π= 81.98

Cp=22rsen(α/2)

Cp=2*122.4sen(38°22°34.58°/2)

Cp=80.46m

Ϫ О L parc L Acumula α Parc α Acumula

Pc 6+267.48

6+280 12.52 12.52 2°55°49.5° 2°55°49.5°

6+300 20 32.52 4°40°52.23° 7°36°41.73

6+320 20 52.52 4°40°52.23° 12°17°33.96

6+340 20 72.52 4°40°52.23° 16°58°26.19

6+349.46 9.46 81.98 2°12°51.1° 19°11°17.29