Trabajo de caminos

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Ejemplo 1 R= 280 E= 6.20 PI = 0+580 E= r(sec (α/2) -1) 6.2/280=sec(d/2)-1 0.02217+1 = sec(α/2) 1.02214=(1/cos(α/2) α/2= arcos(0 .98) α=23.89=23°53°38.29° Lc= 2πrα/360 Lc=( π*280*23.89)/180 Lc= 116.749 Subtang E = Rtang (α/2) Subtang E =280tang(11.95) Subtang E =59.21m M= R(1-cos(α/2)) M=280(1-cos11.95)) M=6.07m
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    30-Jul-2015
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1. Ejemplo 1 R= 280 E= 6.20 PI = 0+580 E= r(sec (/2) -1) 6.2/280=sec(d/2)-1 0.02217+1 = sec(/2) 1.02214=(1/cos(/2) /2= arcos(0 .98) =23.89=235338.29 Lc= 2r/360 Lc=( *280*23.89)/180 Lc= 116.749 Subtang E = Rtang (/2) Subtang E =280tang(11.95) Subtang E =59.21m M= R(1-cos(/2)) M=280(1-cos11.95)) M=6.07m Pc=0+580.63-59.21 =0+521.42 Pt=0+521.42+116.75= 638.17 2. L parc L Acumula Parc Acumula Pc 0+521.42 540 18.58 18.58 1544.63 1544.63 560 20 38.58 2247.73 35652.36 580 20 58.58 2247.73 55940.09 600 20 78.58 2247.73 8227.82 620 20 98.58 2247.73 10515.55 638.17 18.17 116.75 15133.59 111049.14 Ejemplo 2 E=7.2m M=6.8m Pi= 6+310.08 M= R(1-cos(/2)) E= r(sec (/2) -1) M/(1-cos(/2))= E/(sec (/2) -1) M/E= Cos(/2) 6.8/7.2= cos (/2) =2*19.88 =382234.58 Subtang E = Rtang (/2) Subtang E =122.4 *tg19.188 Subtang E =42.60m Lc= 2r/360= 382234.58*122.4*= 81.98 Cp=22rsen(/2) Cp=2*122.4sen(382234.58/2) Cp=80.46m 3. L parc L Acumula Parc Acumula Pc 6+267.48 6+280 12.52 12.52 25549.5 25549.5 6+300 20 32.52 44052.23 73641.73 6+320 20 52.52 44052.23 121733.96 6+340 20 72.52 44052.23 165826.19 6+349.46 9.46 81.98 21251.1 191117.29