Hollow Block Slab Design Rev 2
Transcript of Hollow Block Slab Design Rev 2
design of two way hollow block slab
Fcu = 350 kg\cm2
Fy = 4600 kg\cm2
Ts = 0.07 m L.L. = 0.2 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
m = 1 m\ = 1
L = 8.705 Ls = 8.705
* steps of design
0.32 cm
2) Get the loads on the slab Wrib = 0.692 t \ 1 X s m2
3) Calculate the load factors ά , β r = 1
ά= FALSE ά=
β= FALSE β=
Weight of one Block =
Input Data
1) choose t = ts + h =
( L.L LESS THAN 0.5 t\m2
PLEASE ENTER ά&β )
0.396
0.396
4) take strips at load directions
ά direction M 1 = 2.595666
β direction M2 = 2.595666
5) Design The Ribs. (Dimensions & RFT.)
Short Direction
d = 0.29 m B= 0.5 m
C1 = 7.529959 c/d = 0.05038 J= 0.826
A sά 2.355662 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 1Ø12+1Ø14 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
Long Direction
d = 0.28 m B= 0.5 m
C1 = 7.270305 c/d = 0.054126 J= 0.826
A sά 2.439793 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 1Ø12+1Ø14 \mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
Fcu = 250 kg\cm2
Fy = 3600 kg\cm2
Ts = 0.06 m L.L. = 0.2 t\m2
F.C. = 0.15 t\m2
e = 0.4 m b = 0.15 m h = 0.2 m
γc = 2.5 t \ m2
S = 0.55 m 0.02 ton
L = 8 Ls = 5
* steps of design
0.26 cm
2) Get the loads on the slab Wrib u.l. = 0.708 t \ 1 X s m2
3) take strips at load directions
M = 2.2125
4) Design The Ribs. (Dimensions & RFT.)
d = 0.23 m B= 0.55 m
C1 = 5.7337341 c/d = 0.08825 J= 0.826
A s = 3.2349896 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 1Ø14+1Ø16 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam
W rib = 0.708 t \ 1 X s m2
l rib = 5 m
S = 0.55 m
W b =( W rib x l rib )/2S = 3.21818 t\m\
Weight of one Block =
Input Data
1) choose t = ts + h =
DESIGNED BY: Eng ehab abd el moniem
design of one way hollow block slab
SLAB NO:
GROUND SLAB
villa
1
PROJECT NAME:
BULDING NAME:
النعيرية مسجد
FLOOR NO:
Fcu = 350 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.3 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
m = 0.76 m\ = 0.76
L = 10 Ls = 10
* steps of design
0.35 cm
2) Get the loads on the slab Wrib = 0.7825 t \ 1 X s m2
3) Calculate the load factors ά , β r = 1
ά= FALSE ά=
β= FALSE β=
4) take strips at load directions
ά direction M 1 = 3.873375
β direction M2 = 3.873375
5) Design The Ribs. (Dimensions & RFT.)
Short Direction
d = 0.32 m B= 0.5 m
C1 = 6.801806 c/d = 0.062039 J= 0.826
A sά 3.489074 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 1Ø14+1Ø16 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
Long Direction
d = 0.31 m B= 0.5 m
C1 = 6.589249 c/d = 0.06622 J= 0.826
A sβ 3.601625 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 2Ø16 \mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
6 ) Design of The Long Beam
W ribά = 0.30987 t \ 1 X s m2
l rib = 10 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.0987 t\m\
6 ) Design of The Short Beam
W ribβ = 0.30987 t \ 1 X s m2
l rib = 10 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.0987 t\m\
0.396 ( L.L LESS THAN 0.5 t\m2
PLEASE ENTER ά&β )0.396
1
design of two way hollow block slab
SLAB NO:
Input Data
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
BULDING NAME: MOSQUE
Fcu = 350 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.3 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.15 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.55 m 0.02 ton
L = 20 Ls = 9.55
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.88175 t \ 1 X s m2
3) take strips at load directions
M = 10.05223
4) Design The Ribs. (Dimensions & RFT.)
d = 0.31 m B= 0.55 m
C1 = 4.2898879 c/d = 0.162679 J= 0.813
A s = 9.4964371 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use الديزاين عيد فضلك من mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 2
W rib = 0.88175 t \ 1 X s m2
l rib = 9.55 m
S = 0.55 m
W b =( W rib x l rib )/2S = 7.655193 t\m\
O.W OF BEAM 3.92
W WALL 1.4
TOTAL LOAD BEAM 12.97519
BULDING NAME: villa
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 2
design of one way hollow block slab
Input Data
Fcu = 350 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.3 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
m = 0.87 m\ = 0.87
L = 10 Ls = 10
* steps of design
0.35 cm
2) Get the loads on the slab Wrib = 0.7825 t \ 1 X s m2
3) Calculate the load factors ά , β r = 1
ά= FALSE ά=
β= FALSE β=
4) take strips at load directions
ά direction M 1 = 3.873375
β direction M2 = 3.873375
5) Design The Ribs. (Dimensions & RFT.)
Short Direction
d = 0.32 m B= 0.5 m
C1 = 6.8018058 c/d = 0.062039 J= 0.826
A sά 3.4890744 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 1Ø14+1Ø16 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
Long Direction
d = 0.31 m B= 0.5 m
C1 = 6.5892494 c/d = 0.06622 J= 0.826
A sβ 3.6016252 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 2Ø16 \mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
6 ) Design of The Long Beam
W ribά = 0.30987 t \ 1 X s m2
l rib = 10 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.0987 t\m\
6 ) Design of The Short Beam
W ribβ = 0.30987 t \ 1 X s m2
l rib = 10 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.0987 t\m\
3
design of two way hollow block slab
Input Data
BULDING NAME: MOSQUE
PROJECT NAME: النعيرية مسجد
1) choose t = ts + h =
0.396 ( L.L LESS THAN 0.5 t\m2
PLEASE ENTER ά&β )0.396
DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
FLOOR NO: GROUND SLAB
SLAB NO:
Fcu = 350 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.3 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.15 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.55 m 0.02 ton
L = 30 Ls = 5.4
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.88175 t \ 1 X s m2
3) take strips at load directions
M = 3.213979
4) Design The Ribs. (Dimensions & RFT.)
d = 0.31 m B= 0.55 m
C1 = 7.5867463 c/d = 0.049613 J= 0.826
A s = 2.9884911 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 2Ø14 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 1
W rib = 0.88175 t \ 1 X s m2
l rib = 5.4 m
S = 0.55 m
W b =( W rib x l rib )/2S = 4.328591 t\m\
O.W OF BEAM
W WALL 0.5
TOTAL LOAD BEAM 4.828591
BULDING NAME: villa
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 4
design of one way hollow block slab
Input Data
Fcu = 300 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.2 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
L = 10 Ls = 5.8
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2
3) take strips at load directions
M = 2.954013
4) Design The Ribs. (Dimensions & RFT.)
d = 0.32 m B= 0.5 m
C1 = 7.2108995 c/d = 0.055042 J= 0.826
A s = 2.6609273 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 1Ø12+1Ø14 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 5
W rib = 0.7025 t \ 1 X s m2
l rib = 5.8 m
S = 0.5 m
W b =( W rib x l rib )/2S = 4.0745 t\m\
BULDING NAME: villa
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 5
design of one way hollow block slab
Input Data
Fcu = 300 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.2 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
L = 8.65 Ls = 5.25
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2
3) take strips at load directions
M = 2.420332
4) Design The Ribs. (Dimensions & RFT.)
d = 0.32 m B= 0.5 m
C1 = 7.9663271 c/d = 0.044912 J= 0.826
A s = 2.1801965 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 2Ø12 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 6
W rib = 0.7025 t \ 1 X s m2
l rib = 5.25 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.688125 t\m\
BULDING NAME: villa
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 6
design of one way hollow block slab
Input Data
Fcu = 300 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.2 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
L = 5.25 Ls = 5.25
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2
3) take strips at load directions
M = 2.420332
4) Design The Ribs. (Dimensions & RFT.)
d = 0.32 m B= 0.5 m
C1 = 7.9663271 c/d = 0.044912 J= 0.826
A s = 2.1801965 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 2Ø12 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 7
W rib = 0.7025 t \ 1 X s m2
l rib = 5.25 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.688125 t\m\
BULDING NAME: villa
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 7
design of one way hollow block slab
Input Data
Fcu = 300 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.2 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
L = 8.4 Ls = 5.25
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.7025 t \ 1 X s m2
3) take strips at load directions
M = 2.420332
4) Design The Ribs. (Dimensions & RFT.)
d = 0.32 m B= 0.5 m
C1 = 7.9663271 c/d = 0.044912 J= 0.826
A s = 2.1801965 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
use 2Ø12 mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 7
W rib = 0.7025 t \ 1 X s m2
l rib = 5.25 m
S = 0.5 m
W b =( W rib x l rib )/2S = 3.688125 t\m\
BULDING NAME: villa
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniem
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 8
design of one way hollow block slab
Input Data
Fcu = 350 kg\cm2
Ts = 0.1 m L.L. = 0.3 t\m2
e = 0.4 m b = 0.1 m
γc = 2.5 t \ m2
S = 0.5 m
L = 15 Ls = 10.6
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.7825 t \ 1 X s m2
3) take strips at load directions
M = 10.99021
4) Design The Ribs. (Dimensions & RFT.)
d = 0.32 m B= 0.5 m
C1 = 4.037997 c/d = 0.185412 J= 0.806
A s = 10.14546 cm2
2Ø12
use الديزاين عيد فضلك من mm 2Ø14
2Ø16
2Ø18
5 ) Design of The Beam 7
W rib = 0.7825 t \ 1 X s m2
l rib = 10.6 m
S = 0.5 m
W b =( W rib x l rib )/2S =8.2945 t\m\
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 9
design of one way hollow block slabInput Data
PROJECT NAME: النعيرية مسجد DESIGNED BY:
BULDING NAME: villa
Fy = 4200 kg\cm2
F.C. = 0.2 t\m2
h = 0.25 m
0.02 ton
= 2.26 1Ø12+1Ø14 = 2.67
= 3.08 1Ø14+1Ø16 = 3.55
= 4.02 1Ø16+1Ø18 = 4.55
= 5.09
Weight of one Block =
design of one way hollow block slab
DESIGNED BY: Eng ehab abd el moniem
Fcu = 350 kg\cm2
Fy = 4200 kg\cm2
Ts = 0.1 m L.L. = 0.3 t\m2
F.C. = 0.2 t\m2
e = 0.4 m b = 0.1 m h = 0.25 m
γc = 2.5 t \ m2
S = 0.5 m 0.02 ton
L = 8.4 Ls = 8.5
* steps of design
0.35 cm
2) Get the loads on the slab Wrib u.l. = 0.7825 t \ 1 X s m2
3) take strips at load directions
M = 7.066953
4) Design The Ribs. (Dimensions & RFT.)
d = 0.32 m B= 0.5 m
C1 = 5.035619 c/d = 0.11574 J= 0.826
A s = 6.365799 cm2
2Ø12 = 2.26 1Ø12+1Ø14 = 2.67
Weight of one Block =
1) choose t = ts + h =
FLOOR NO: GROUND SLAB
SLAB NO: 10
design of one way hollow block slabInput Data
PROJECT NAME: النعيرية مسجد DESIGNED BY: Eng ehab abd el moniemBULDING NAME: villa
use الديزاين عيد فضلك من mm 2Ø14 = 3.08 1Ø14+1Ø16 = 3.55
2Ø16 = 4.02 1Ø16+1Ø18 = 4.55
2Ø18 = 5.09
5 ) Design of The Beam 7
W rib = 0.7825 t \ 1 X s m2
l rib = 8.5 m
S = 0.5 m
W b =( W rib x l rib )/2S =6.65125 t\m\