EMII Ch.10 Notessite.iugaza.edu.ps/masmar/files/notes1.pdf6 In free space, H = 0.1 cos (2 X 10^8 t -...
Transcript of EMII Ch.10 Notessite.iugaza.edu.ps/masmar/files/notes1.pdf6 In free space, H = 0.1 cos (2 X 10^8 t -...
EMII Ch.10 Notes
3
8
8
ω=2×10 rad/sec
f=31.8 MHz
T=3.14 10 sec
8u=c=3×10 m/sec
8
8
ω 2×10β= = =0.67 rad/m
u 3×102
0.67 9.426m
4
8 T=3.14 10 sec
5
9.426m
0.67 rad/m 0.67 rad 1 m
6.28 rad ?? m
6
In free space, H = 0.1 cos (2 X 10^8 t - kx) ay A/m. Calculate(a) k, λ, and T(b) The time t1 it takes the wave to travel λ/8(c) Sketch the wave at time t1.
x
8
8
8
8
8
8
8
8
1
1
propgation direction is +a
(a)
ω=2×10 rad/sec
u=c=3×10 m/sec (free space)
ω 2×10k=β= = =0.67 rad/m
u 3×10
1 2πω=2πf=2×10 , T= = =31.42ns
f 2×10
λu ,λ (3×10 )(31.42ns) 9.426m
(b)
λu
(λ / 8) (9.42 / 83×10
wave
T
T
tt
8
)3.9
3×10ns
7
8 9
y
y
1
(c)
H=0.1cos(2 10 3.9 10 0.67 )
=0.1cos(0.78 0.67 )
for t=0 H=0.1cos(0 ) 0.1cos(0 0.67 )
for t=t H=0.1cos(0.78 ) 0.1cos(0.78 0.67 )
figure at t1 is the same as at t but shifted by 0.78=pi/4
x
x
x x
x x
a
a
9.426m
( , ) sin( )z
o xE t z E zte a
z
2 2
f rad
f u m
t
T
u fT
: attenuation costant (Np/m)or (dB/m)
2
1 12
Wave attenuates in amplitude by a factor e-az
l
1
Anattenuation of 1 neper denotes a reduction to e of the original value whereas an increase
of 1 neper indicates an increase by a facto
neper
r
/
e
s
of
m
How far?This is often formulated ts the question:-
how far does the wave propagate before its magnitude is reduced by e-1?this is called the skin depthe-1 is approximately 0.3
In copper, the wave is down to 36% of its initial strength in the first 6.62mm.i.e. light really doesn't get far into copper!
Perfect dielectric:
σ=0 α=0 δs=∞
Perfect Conductor:
σ=∞ α=∞ δs=0
18
Reflection of a plane wave
(1) Normal Incidence
The proportion of the incident wave that is reflected or transmitteddepends on the constitutive parameters (ε,µ, σ) of the two media involved.
1 i r
1 i r
2 t
2 t
E =E +E
H =H +H
E =E
H =H
19
2 1 r
2 1 i
E= =
E
Reflection coefficient
t2
1 2 i
E2= =
E
Transmission coefficient
(1) =1
(2) 1 1 , 0 | | 1 , 0 2
(3) If 1 total reflection
(4) ( & ) are dimensionless and may be complex.
20
2 1 =0 =1
(No reflection )=(total trasmission)
1
21
1
medium(1):
lossless( =0) 2
medium(2):
perfect conductor( = )
2 45o
2 1 r
2 1 i
E= =
E
t2
1 2 i
E2= =
E
total reflection
Comment: fields in a perfect conductor must vanish.
1 0
1 and =2
2
Compared to 2
22
1
medium(2):
lossless( =0)2
medium(1):
perfect conductor( = )
1 45o
2 1 r
2 1 i
E= =
E
t2
1 2 i
E2= =
E
total reflection with phase shift
2 0
1 and =0
3
23
1 and =0
0 and =1
1 and =2 total reflection
total reflection with phase shift
(No reflection )=(total trasmission)
24
A standing wave
It consists of two traveling waves (Ei and Er) of equal amplitudes but in opposite directions.
1 | | 1= , | |
1 | | 1
SS
S
(1) 0 | | 1 1
(2) SWR:standing wave ratio
(3) S is dimensionless (always expressed in dB)
(4) If S=1 | | 0 & 1 reflected wave(totally transmitted)
(5) If S= | | 1 transmission (totally ref
S
No
No
lected)
25
1 and =0
0 and =1
1 and =2 total reflection
total reflection with phase shift
(No reflection )=(total trasmission)
=S
=1S
=S
26
2 1 r
2 1 i
E= =
E
t2
1 2 i
E2= =
E
1 | |=
1 | |S
271 1 , 1r 1 , 4r r
28
z
x
y
29
z
x
y
2 188.5 4
o
o
1 377
30
1 2
2 1
2 1
2
1 2
(a) 188.5 , 377 4
377 188.5= = 1/3
377 188.5
2 2(377)= = 1.33
188.5 377
o
o
31
8tt
i
8
t
8
1 8
2
8
t
2
2
1/3 , 1.33
EE (1.33) 5cos(10 )
E
E =1.668cos(10 )
1 3 10 rad/s3 10
4 0.667
E =1.668cos(10 0.667 )
z
z
o o
o o
z
t y
t y
t y
a
a
a
32
8
t
toto
2
r
0.667
(note it fro
E =1.668cos(10 )
| E | 1.668|H |
m figur
0.0265377
H 0.0265cos
e) ,
( )( )
, k z E x H
z
E
y
k y
t y
t z
a a a a a a a
a
a
a
33
34
1
2
4 (a) =754
= 95.44 37.570.1
(1 ) 4 (1 )4
o
o
oo
o
o
j j
2 1
2 1
95.44 37.57 754= = 0.8186171.08
95.44 37.57 754
1 | | 1 0.81861 0.23 33.56 , 10.0253
1 | | 1 0.8186
o
o
S
35
8
1
2
22
2
8
2
1
2
2 2 22
2
2
2 2 22
2
5 4 7.5 10
2 2(37.57) 75.14
tan(2 ) tan(75.14) 3.77
(3.77)(4 )(7.5 10 ) 0.1 (as given)
0
1 1 6.021 Np/m 2
1 1 7.822
o o
o
o
65 rad/m
36
rr
i
8
r
oror
1
8
r
5 171.08
5 17
E (b) | E | (0.8186)(50) 41
E
E 41sin(7.5 10 )
E 41H 0.05428
754
H 0.05428sin(7.5 10 )1 ).08 (
y
z
t x
t x
a
a
37
tt
6.02
6
i
8
t
otot
2
8
t
.02
E (c) | E | (0.23)(50) 11.5
E
E 11.5 sin(7.5 10 7.8265 )
E 11.5H 0.1205
95.4
H 0
33.56
3.1205 sin(7.5 10 7.8 3.56 3 .2 5 56 )7 7
x
x
y
z
e
e
t x
t x
a
a