Test 1 skema q&a

UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING BTI10202 COMPUTER PROGRAMMING

TEST 1-MONDAY

The output should be similar to:

Write a program to calculate mass of the liquid in a tank. Allow the user to input the

volume either in cm or meter, and prompt the user to recalculate if desire.

Note that:

Oil density (ρ)= 850 kg/m3

Mass=ρV


#include<stdio.h>

#include<conio.h>

#include<math.h>

main(){

float oildensity, tankvolume,mass=0;

char oilunit,again;

printf("This program calculate the mass of oil in a tank");

start:

printf("\n\nEnter oil density: ");scanf("%f",&oildensity);

printf("Enter tank volume: ");scanf("%f",&tankvolume);

printf("\nEnter volume unit(m=meter, c=centimeter): ");scanf("%s",&oilunit);

recalculate:

switch (oilunit){

case 'c':

mass= oildensity*((pow(tankvolume,3))/pow(100,3)); break;

case 'm':

mass= oildensity*(pow(tankvolume,3)); break;

default:

printf("You have entered a wrong type of unit");

printf("\n\nEnter oil density unit(g for gram/k for kg): ");scanf("%s",&oilunit);

goto recalculate; }

printf("\n\n\tThe Mass of oil is %.4fkg",mass);

printf("\n\nDo you want to re-calculate: ");scanf("%s",&again);

if(again=='y' || again=='Y')

goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

#include<math.h>

main(){


char oilunit,again;


start:




recalculate:

if (oilunit== 'c'){

mass= oildensity*((pow(tankvolume,3))/pow(100,3)); }

else if (oilunit== 'm'){

mass= oildensity*(pow(tankvolume,3));}

else{



goto recalculate; }


printf("\n\nDo you want to re-calculate(enter y for yes): ");scanf("%s",&again);


goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


char oilunit,again;


start:




recalculate:

switch (oilunit){

case 'c':

mass= oildensity*(tankvolume/100); break;

case 'm':

mass= oildensity*tankvolume; break;

default:



goto recalculate;

}


printf("\n\nDo you want to re-calculate: ");scanf("%s",&again);


goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


char oilunit,again;


start:




recalculate:

if (oilunit== 'c'){

mass= oildensity*(tankvolume/100); }

else if (oilunit== 'm'){

mass= oildensity*tankvolume;}

else{



goto recalculate;

}




goto start;

getch();

}


TEST 1-TUESDAY

Base on the table develop a simple program on how long should a

man/woman should exercise to burn calories off either by jogging or

bicycling. The user must be able to keep calculating until the key end

otherwise.

Example: A 65kg woman needs to burn of 800 calories by jogging, how

long does she need to jog in order to burn of all of the calories.

The output should be similar to :

Energy output: 𝑤𝑒𝑖𝑔ℎ𝑡 𝑥 𝑎𝑐𝑡𝑖𝑣𝑖𝑡𝑦 𝑐𝑎𝑙𝑜𝑟𝑖𝑒𝑠

68𝑘𝑔 Δ 64 x

540

68

Duration: 𝑡𝑜𝑡𝑎𝑙 𝑐𝑎𝑙𝑜𝑟𝑖𝑒𝑠

𝐸𝑛𝑒𝑟𝑔𝑦 𝑜𝑢𝑡𝑝𝑢𝑡 Δ

800

516.17


#include<stdio.h>

#include<conio.h>

main(){

float calorin,weight,totalhour=0;

int type;

char again;

printf("\t\t\t\4\4\4Exercise Calculator\4\4\4\n\n");

start:

printf("\nEnter calories intake: ");scanf("%f",&calorin);

printf("Enter your weight: ");scanf("%f",&weight);

choose:

printf("\nPlease choose type of exercise \n1. Jogging\n2. Bicycling\nPlease enter type: ");scanf("%d",&type);

switch(type){

case 1:

totalhour=calorin/(weight*(540/68));

printf("\n\tIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour);break;

case 2:


printf("\n\tIn order to burn %.f of calories you need to cycle for %.1fhr",calorin,totalhour);break;

default:

goto choose;break;

}


goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("\nPlease choose type of exercise \n1. Jogging\n2. Bicycling\nPlease enter type: ");scanf("%d",&type);

if (type==1){


printf("\n\tIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour); }

else if (type==2){


printf("\n\tIn order to burn %.f of calories you need to cycle for %.1fhr",calorin,totalhour); }

else { goto choose;}


goto start;

getch();

}


TEST 1-TUESDAY


man/woman should exercise to burn calories off either by jogging or

playing tennis. The user must be able to keep calculating until the key

end otherwise.





68𝑘𝑔 Δ 64 x

540

68



800

508.23


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("\nPlease choose type of exercise \n1. Jogging\n2. Tennis\nPlease enter type: ");scanf("%d",&type);

switch(type){

case 1:


printf("\n\tIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour);break;

case 2:


printf("\n\tIn order to burn %.f of calories you need to play intense tennis for %.1fhr", calorin,totalhour); break;

default:

goto choose; break; }



goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("\nPlease choose type of exercise \n1. Jogging\n2. Tennis\nPlease enter type: ");scanf("%d",&type);

if(type==1){


printf("\n\tIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour);}

else if(type==2){


printf("\n\tIn order to burn %.f of calories you need to play intense tennis for %.1fhr",calorin,totalhour); }

else{

goto choose; }



goto start;

getch();

}


TEST 1-TUESDAY


man/woman should exercise to burn calories off either by fast swimming

or bicycling. The user must be able to keep calculating until the key end

otherwise.





68𝑘𝑔 Δ 64 x

540

68



800

508.23


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("\nPlease choose type of exercise \n1. Fast Swimming\n2. Bicycling\nPlease enter type: ");scanf("%d",&type);

switch(type){

case 1:


printf("\n\tIn order to burn %.f of calories you need to fast swimming for %.1fhr",calorin,totalhour);break;

case 2:


printf("\n\tIn order to burn %.f of calories you need to cycle for %.1fhr",calorin,totalhour);

break;

default:

goto choose;break;

}


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("\nPlease choose type of exercise \n1. Fast Swimming\n2. Bicycling\nPlease enter type: ");scanf("%d",&type);

if(type==1){


printf("\n\tIn order to burn %.f of calories you need to fast swimming for %.1fhr", calorin,totalhour);}

else if (type==2){


printf("\n\tIn order to burn %.f of calories you need to cycle for %.1fhr",calorin,totalhour); }

else{

goto choose; }


goto start;

getch();

}


TEST 1-WEDNESDAY


The user must be able to keep calculating until the key end otherwise.

Develop a simple program to calculate

radius of a circle. The user need to

choose whether to input area or

circumference of the circle.

Note that:

area= πxrad2

and circumference = 2xπxrad


#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,again;

float radius,circumference,area;

printf("\t\4\4\4This program calculate radius of a circle\4\4\4");

start:

printf("\n\na:area\nc:circumference\n\nEnter the information that you have:");

scanf("%s",&type);

cal:

switch(type){

case 'a':

printf("\nEnter area of a circle:");scanf("%f",&area);

radius = sqrt(area/PI);

printf("\nThe area of a circle is %.2f while the radius is %.4f",area,radius); break;

case 'c':

printf("\nEnter circumference of a circle:");scanf("%f",&circumference);

radius= circumference/(PI*2);

printf("\nThe circumference of a circle is %.2f while the radius is %.4f",circumference,radius);break;

default:

printf("\na:area\nc:circumference\n\nPlease re-enter selection:");

scanf("%s",&type); goto cal; }

if(again=='y' || again=='Y') { goto start;}

getch();

}


#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,again;


printf("\t\4\4\4This program calculate radius of a circle\4\4\4");

start:

printf("\n\na:area\nc:circumference\n\nEnter the information that you have:");

scanf("%s",&type);

cal:

if (type=='a'){

printf("\nEnter area of a circle:");scanf("%f",&area);

radius = sqrt(area/PI);

printf("\nThe area of a circle is %.2f while the radius is %.4f",area,radius);}

else if(type== 'c'){

printf("\nEnter circumference of a circle:");scanf("%f",&circumference);

radius=circumference/(PI*2);

printf("\nThe circumference of a circle is %.2f while the radius is %.4f",circumference,radius);}

else{


scanf("%s",&type); goto cal;}


goto start;

getch();

}


TEST 1-WEDNESDAY



Develop a simple program to calculate

either an area or perimeters of a semi

circle. The program must prompt the

user to input radius.

Note that:

area= πxrad2


20.7075


#include<stdio.h>

#include<conio.h>

#define PI 3.1415

main(){

char type,again;

float radius,circumference,area,perimeters;

printf("\t\4\4\4SEMI-CIRCLE CALCULATOR\4\4\4");

start:

printf("\na:area\np:perimeters\n\nEnter selection:");

scanf("%s",&type);

printf("\nEnter radius of the semi-circle:");

scanf("%f",&radius);

cal:

switch(type){

case 'a':

area= 0.5*(PI*pow(radius,2));

printf("\nThe area of a semi-circle for %.2f radius is %.4f",radius,area); break;

case 'p':

circumference= 2*PI*radius;

perimeters= (2 *radius)+ (circumference/2);

printf("\nThe perimeters of a semi-circle for %.2f of radius is %.4f",radius,perimeters);break;

default:

printf("wrong selection");

printf("\na:area\np:Perimeters\n\nPlease re-enter selection:");



goto start;

getch(); }


#include<stdio.h>

#include<conio.h>

#define PI 3.1415

main(){

char type,again;

float radius,circumference,area,perimeters;

printf("\t\4\4\4SEMI-CIRCLE CALCULATOR\4\4\4");

start:

printf("\na:area\np:perimeters\n\nEnter selection:");

scanf("%s",&type);

printf("\nEnter radius of the semi-circle:");


cal:

if(type=='a'){

area= 0.5*(PI*pow(radius,2));

printf("\nThe area of a semi-circle for %.2f radius is %.4f",radius,area);}

else if(type=='p'){


perimeters= (2 *radius)+ (circumference/2);

printf("\nThe perimeters of a semi-circle for %.2f of radius is %.4f",radius,perimeters);}

else{ printf("wrong selection");

printf("\na:area\np:Perimeters\n\nPlease re-enter selection:");

scanf("%s",&type); goto cal;

}


goto start;

getch();

}


TEST 1-THURSDAY


Write a program to prove the theory of prefix and postfix in C Program slybuss. Allow the

user to keep testing until ‘n’ is keyed in by the user

Note that:

Postfix : a++,a—

Prefix :++a,--a


#include<stdio.h>

#include<conio.h>

main(){

int a,prepost;

char b;

printf("\tThis program is use to proof theory of postfix and prefix");

sekalilagi:

printf("\n\nEnter value a: "); scanf("%d",&a);

choose:

printf("\nPlease choose\n1. postfix\n2. Prefix\nPlease enter your choice: "); scanf("%d",&prepost);

switch (prepost){

case 1:

printf("\npostfix/a++ for a is %d at the end a =%d", a++,a);

printf("\nand a after ; is %d",a);

printf("\n\npostfix/a-- for a is %d at the end a =%d", a--,a);

printf("\nand a after ; is %d",a); break;

case 2:

printf("\nprefix/++a for a = %d at the end a =%d", ++a,a);


printf("\n\nprefix/--a for a = %d at the end a =%d", --a,a);

printf("\nand a after ; is %d",a); break;

default: goto choose; }

printf("\n\nEnter n to stop re-trying: "); scanf("%s",&b);

if (b!='n'){ goto sekalilagi;}

getch();

}


#include<stdio.h>

#include<conio.h>

main(){

int a,prepost;

char b;

printf("\tThis program is use to proof theory of postfix and prefix");

sekalilagi:

printf("\n\nEnter value a: "); scanf("%d",&a);

choose:

printf("\nPlease choose\n1. postfix\n2. Prefix\nPlease enter your choice: "); scanf("%d",&prepost);

if (prepost==1){

printf("\npostfix/a++ for a is %d at the end a =%d", a++,a);


printf("\n\npostfix/a-- for a is %d at the end a =%d", a--,a);

printf("\nand a after ; is %d",a); }

else if (prepost==2){

printf("\nprefix/++a for a = %d at the end a =%d", ++a,a);


printf("\n\nprefix/--a for a = %d at the end a =%d", --a,a);

printf("\nand a after ; is %d",a);}

else { goto choose;}


if (b!='n'){ goto sekalilagi;}

getch();

}


TEST 1-FRIDAY


Write a program to segregat number of students according to :

GRADE E: 0 <= mark <=49

GRADE D: 50 <=mark <=59

GRADE C: 60 <= mark <=69

GRADE B: 70 <= mark <=79

GRADE A: 80 <= mark <=100


#include<stdio.h>

#include<conio.h>

int main(){

int noofstudent=0,mark=0, gradeA=0,gradeB=0,gradeC=0,gradeD=0,gradeE=0;

int i=1;

printf("\4\4The Program segregrate the number of students according to grade\4\4\ ");

printf("\n\nEnter Number of student: "); scanf ("%d",&noofstudent);

loop:

printf("%d student mark: ",i); scanf ("%d",&mark);

if (mark>=0 && mark <=49)

{ gradeE++; }

else if (mark>=50 && mark <=59)

{ gradeD++; }


{ gradeC++; }


{ gradeB++; }


{ gradeA++; }

i++;

if (i<noofstudent)

goto loop;


printf("\n______________________________________________\n ");

printf("\nThere is %d students receive grade A ",gradeA);

printf("\nThere is %d students receive grade B ",gradeB);

printf("\nThere is %d students receive grade C ",gradeC);

printf("\nThere is %d students receive grade D ",gradeD);

printf("\nThere is %d students receive grade E ",gradeE);

getch();

return 0;

}


TEST 1-FRIDAY



Develelope a simple program which

receive radius of a circle from user and

allowed user to choose between

calculating area of a circle or

circumferense of a circle,:

Note that:

area= πxrad2



#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,b;


printf("This program calculate Area or Circumference of a circle");

again:

printf("\na:area\nc:circumference\n\nEnter selection:");scanf("%s",&type);

printf("\nEnter radius of a circle:"); scanf("%f",&radius);

cal:

switch(type){

case 'a':

area= PI*pow(radius,2);

printf("\nThe area of a circle for %.2fcm radius is %.4f",radius,area); break;

case 'c':


printf("\nThe circumference of a circle for %.2fcm radius is %.4f",radius,circumference);break;

default:





if (b!='n'){ goto again;}

getch();

}


#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,b;


printf("This program calculate Area or Circumference of a circle");

again:

printf("\na:area\nc:circumference\n\nEnter selection:");

scanf("%s",&type);

printf("\nEnter radius of a circle:");


cal:

if (type=='a'){

area= PI*pow(radius,2);

printf("\nThe area of a circle for %.2fcm radius is %.4f",radius,area); }

else if (type=='c') {


printf("\nThe circumference of a circle for %.2fcm radius is %.4f",radius,circumference);}

else {





if (b!='n'){ goto again;}

getch(); }

Test 1 skema q&a

Technology

Transcript of Test 1 skema q&a