diket:p = 10 Tl = 1.5 m

Mu = 3.75 Tm37500000 Nmm

1,6 Mu = 60000000 Nmmfy = 400 Mpafc' = 25 Mpa

h = 400 mm

m =

m = 18.8235294118 mmb = 200 mm b = 200 mm

h = 400 mmd' = 30 mmd = 370 mm

Rn

Rn = 2.7392257122

ρ =

= 0.00735755748

=

= 0.0035

ρ 0.00735755748 > 0.0035

ok

= ρ . B . D= 544.459253216

perhitungan tulangan:n =

2 D 19

== 567.057473973

567.057473973 > 544.4593

=

ρ min

ρ min

As perlu

As perlu mm²

As coba n . 1/4 .π D² As coba mm²

As coba As perlu

ok

a =

a = 53.3701151975

Mn = As . Fy (d - a/2)= 77871721.6061 Nmm

Mn MuMn = 77871721.6061 > 60000000

ok

a Cc = 0.85 . Fc' . a . b

d - a/2

MnTs = As . Fy

diket:p = 10 Tl = 1.8 m

Mu = 4.5 Tm45000000 Nmm

1,6 Mu = 72000000 Nmmfy = 400 Mpafc' = 25 Mpa

m =

m = 18.82352941176 mmb = 1000 mmh = 200 mmd' = 30 mmd = 170 mm

Rn

Rn = 3.114186851211

ρ =

= 0.008458908357

=

= 0.0035

ρ 0.008458908357 > 0.0035

ok

= ρ . B . D= 1438.014420716

== 1610

1610 > 1438.014ok

a =

a = 30.30588235294

=

ρ min

ρ min

As perlu

As perlu mm²

As coba

As coba mm²

As coba As perlu

Mn = As . Fy (d - a/2)= 99721505.88235 Nmm

As bagi =Mn Mu =

Mn = 99721505.88235 > 72000000 =ok

pakai tulangan pakai tulangan

Jd = Jd =

= 124.8831862297 mm =

D 16 125 D 10

As terpasang

0,002 . b . h400450

174.5329252

175

diket:= 3728 kg/m

l = 8 mVu = 1/2 . q . L

= 14912 kg149120 N

fy = 240 Mpafc' = 15 Mpab = 200 mmh = 500 mmd' = 30 mmd = 470 mm

Vc =

= 60676.7390906 N

Vc < Vu60676.74 < 149120PERLU TULANGAN GESER

=

=

= 168738.645525 N

= 10 mmAv =

= 157.079632679

s =

= 105.006073215 mmpakai tulangan

Ø 10 - 106

untuk mempermudah pemasangan tulangan :

Ø 10 - 100

qult

Ø Vs Vu - Ø Vc

Vs perlu

Ø tuln . 1/4 . π . D²

mm²

Mu = 300,000,000 Nmmfy = 400 Mpafc' = 25 Mpab = 300 mmh = 700 mmd' = 40 mmd = 660 mm

As1 = 1000

a =

= 62.74509803922

= As . Fy

= 201160784.3137 Nmm

= or Mn2 = As2 . Fy . (d-d')= 123549019.6078

= 123549019.6078 Nmm

=

= 498.1815306768

= As1 + As2= 1498.181530677

perhitungan tulangan:

n =

jadi pakai4 D 22

jadi pakaiAs2=As' = 498.1815306768

2 D 22

201160784.3137 123549019.608

Mu324709803.9216 > 300,000,000

ok

mm²

φMn1

Mn2 perlu

As2 = As'

mm²

As1 totalmm²

φMn1 φMn2

φMn total

Nmm

Mu = 300,000,000 Nmmfy = 400 Mpafc' = 15 Mpabw = 200 mmh = 600 mmhf = 120 mmd' = 30 mmd = 570 mmAs = 1700L = 6000 mm

1/4 L = 1500 mmbw + 16.hf = 2120 mm = 1500 mm

jb = 1800 mm

misal, a = hfCc 1 = 0,85 . Fc' . a . b

= 2295000 N

Ts = As . Fy= 680000 N

Cc 1 Ts2295000 > 680000

maka a < hf, termasuk balok T-persegi, balok tekan tidak perlu seluruhnya, hanya sebagian

maka,

a =

= 35.55555555556

Cc 2 = 0,85 . fc' . a . b= 680000 N

Cc 2 Ts680000 = 680000

ok

= As . Fy

= 300408888.8889 Nmm

Mu300408888.89 > 300,000,000

ok

mm²

b eff

φMn

φMn

perhitungan tulangan:

n =

jadi pakai penulangan4 D 25

maka a < hf, termasuk balok T-persegi, balok tekan tidak perlu seluruhnya, hanya sebagian

Mu = 300,000,000 Nmmfy = 400 Mpafc' = 15 Mpabw = 300 mmh = 500 mmhf = 120 mmd' = 40 mmd = 460 mmAs = 4000L = 5000 mm

1/4 L = 1250 mmbw + 16.hf = 2220 mm = 750 mm

jb = 750 mm

misal, a = hfCc 1 = 0,85 . Fc' . a . b

= 1147500 N

Ts = As . Fy= 1600000 N

Cc 1 Ts1147500 < 1600000

maka a > hf, termasuk balok T-murni, balok tekan masuk sampai di bawah pelat

maka,

a T.murni =

= 238.30065359 mm

Cc 2 = Ts - Cc1= 452500

Cc1 + Cc 2 Ts1600000 = 1600000

ok

=

= 468867581.7 Nmm

Mu468867581.7 > 300,000,000

ok

mm²

b eff

φMn

φMn

perhitungan tulangan:

n =

jadi pakai penulangan5 D 32

maka a > hf, termasuk balok T-murni, balok tekan masuk sampai di bawah pelat