EAST WEST UNIVERSITYDEPARTMENT OF EEE

Course code: EEE 201Course name: Electrical circuit ΙΙ

Lab reportExperiment no: 01

Experiment name: PSpice simulation of simple AC circuits.

Student name: Syed AbothoeId: 2011-1-80-023

Section: 02Group no: 06

Date of performance: Date of submission:

OBJECTIVE: In this experiment, we knew how simulate AC circuits in PSpice and its fundamentals. We also learnt some basic calculations for AC circuits.

DIAGRAM:

Figure- 1

EXPERIMENTAL DATA: (R1) (L1) (C1) ω 9Ω 10mH 1mF 2*3.1416*100

ANSWERS TO THE LAB-QUESTIONS:

1. Calculation:

ω= 2*3.1416*100Xc = -j1.59XL = j6.28

Impedance Z = 9+ j6.28- j1.59 = 10.15<27.52Ω

Impedance Z(from step 6) = Vm/Im<27.79 = 9.645/0.941<27.79 =10.24<27.79Ω

2 .Maximum voltage through the resistance, VR1 = (10<-90*9)/10.15<27.72 = 8.87 V

Maximum voltage through the Inductor,VL1 = (10<-90*j6.28)/10.15<27.52 = 6.18 V

Maximum voltage through the Capacitor,VC = (10<-90*-j1.59)/10.15<5-27.52 = 1.57 V

Maximum current through the resistance, IR1 = 10<-90/27.52 = 0.985 A RMS values of resistance = VR1/√2 = 8.87 /√2 = 6.27 VRMS values of inductor = VL1/√2 = 6.18/√2 = 4.37 VRMS values of capacitor = VC1/√2 = 1.57/√2 = 1.11 VRMS value of resistance (current) = IR1/ √2

= 0.985/√2 = 0.69 V3. Power consumed by the circuit S = ½*Vm*Im*cos (θ)+j*1/2*Vm*Im*sin (θ) = 0.5*9.645*0.941 cos(27.79)+j*0.5*9.645*0.941*sin(27.29) = 4.01 w4. Power consumed by the resistance,P = (Im*Im*R)/2 = (0.941*0.941*9)/2 = 4 w

Comparing between calculated and experimental values:Components Calculated values experimental valuesImpedance, Z 10.15<27.52 10.24<79VR1(rms) 6.27 V 6.2148 VVL1 (rms) 4.37 V 4.3363 VVC1 (rms) 1.11 V 1.127 VIR1 (rms) 0.69 A 0.68 A

Comparing Power valuesS P

4.01 w 4 w

Comments: It’s a bit difference between the calculated and experimental values. But they are very negligible. Because, they are almost same.

DISCUSSION: In this experiment we learnt how to simulate AC circuits and their graphical views also. So, now we can simulate the AC circuits like that.

1. Here I’ve learnt how to calculate the phase angle as well as how to get phase difference between two signals.

2. In theory class we’ve learnt that for capacitor current always leads voltage, for inductor voltage always leads currents as well as for resistance voltage and current always are in same phase. By the same way in lab experiment we got the similarity.

3. In step 5 we multiplied current with 10, for getting a better wave an image.

4. Here we’ve learnt how to get power dissipation.