Field Effect Transistor (FETs) Homework Problems

JFET (Self-Biased) - Corrected 03-19-2017

VDD = +12 VRG = 470 KΩRS = 750 Ω RD = 3300 ΩIDSS = 12 mA VGS(off) = -1.73 VVGS = -1.12 V

Calculate:

IDQ

VDSQ

JFET (Voltage Divider)

VDD = -15 VR1 = 750 KΩ R2 = 120KΩ RD = 1500 Ω RS = 1200 Ω IDSS = -10 mA VGS(off) = 3.33 V VGS = 1.57 V

Calculate:

IDQ

VDSQ

FET Biasing Homework Solutions - corrected 03-19-2017

1. N Channel Self-Biased

IDQ

= 1.5 mA

VDSQ

= 6.0 V

2. P Channel Voltage Divider Biased

DQI = -3 mA

DS

VQ = -6.8 V