F3006 formulas final

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s x = x - ut 1 - u 2 /c 2 t = t - (u/c 2 )x 1 - u 2 /c 2 v x = v x - u 1 - v x u/c 2 v y = v y 1 - u/c 2 1 - v x u/c 2 Δt = uL/c 2 1 - u 2 /c 2 K = mc 2 1 - v 2 /c 2 - mc 2 p = mv 1 - v 2 /c 2 E = (pc) 2 +(mc 2 ) 2 =2d sin θ v n = kze 2 2π h 1 n E n = - 13,6 n 2 r n = 0 n 2 h 2 πme 2 Z E = hf = hc λ φ = hf - KE L = n~ e/m e =1,7588 × 10 11 C Kg λ - λ 0 = h m e c (1 - cos θ) R =1,097 × 10 7 m -1 a 0 =0,529A E = hf e hf /k B T - 1 h m e c =0,024A p 2 e = p 2 + p 2 - 2pp cos θ E e = hf - hf + m e c 2 p 2 e = hf c 2 + hf c 2 - 2h 2 ff c 2 cos θ p sin θ = p e sin φ f 0 = φ h eV s = hc λ - φ 1 eV =1,602 × 10 -19 J h =6,62 × 10 -34 J · seg e =1,602 · 10 -19 N = U ~ω Φ= P ~ω φ = I ~ω k B =1,38065 · 10 -23 J/K m e =9,10938 · 10 -31 p dav = 2m e q e |ΔV | λ = h mv =2πr = - me 4 8 2 0 h 2 1 n 2 - 1 m 2 μ 0 =4π × 10 -7 N/A 2 σ =5,67 × 10 -8 W/m 2 K 4 u = 931,49MeV/c 2 μ B =9,274 × 10 -24 J/T N A =6,022 × 10 23 mol -1 m p =1,673 × 10 -27 kg ε 0 =8,854 × 10 -12 C 2 /N · m 2 ~ =6,582 × 10 -16 eV · s 1eV =1,602 × 10 -19 J |S| = s(s + 1)~ E = π 2 ~ 2 2mL 2 {n 2 1 + n 2 2 + n 2 3 } Δ = ±1 k = p ~ ΔEΔt ~ 2 Δp x Δx ~ 2 λ max T =2,898 × 10 -3 m · K λ min = hc eV ...

Transcript of F3006 formulas final

Page 1: F3006 formulas final

ss —Draft— THX 1138

s

x′ = x− ut√1− u2/c2

t′ = t− (u/c2)x√1− u2/c2

v′x = vx − u1− vxu/c2 v′y =

vy

√1− u/c2

1− vxu/c2 ∆t′ = uL/c2√1− u2/c2

K = mc2√1− v2/c2

−mc2

p = mv√1− v2/c2

E =√

(pc)2 + (mc2)2 nλ = 2d sin θ

vn = kze22πh

1n

En = −13,6n2 rn = ε0n

2h2

πme2ZE = hf = hc

λφ = hf −KE

L = n~ e/me = 1,7588× 1011[C

Kg

]λ′ − λ0 = h

mec(1− cos θ) R = 1,097× 107m−1 a0 = 0,529A◦ E = hf

ehf/kBT − 1h

mec= 0,024A◦ p2

e = p′2 + p2 − 2pp′ cos θ Ee = hf − hf ′ +mec2 p2

e =(hf ′

c

)2+(hf

c

)2− 2h2ff ′

c2 cos θ

p′ sin θ = pe sinφ f0 = φ

heVs = hc

λ− φ 1 eV = 1,602× 10−19J h = 6,62× 10−34J · seg e = 1,602 · 10−19

N = U

~ωΦ = P

~ωφ = I

kB = 1,38065 · 10−23J/K me = 9,10938 · 10−31 pdav =√

2meqe |∆V | λ = h

mv

nλ = 2πr hν = − me4

8ε20h2

[1n2 −

1m2

]µ0 = 4π × 10−7N/A2 σ = 5,67× 10−8W/m2K4 u = 931,49MeV/c2 µB = 9,274× 10−24J/T NA = 6,022× 1023mol−1

mp = 1,673× 10−27kg ε0 = 8,854× 10−12C2/N ·m2 ~ = 6,582× 10−16eV · s 1eV = 1,602× 10−19J

|S| =√s(s+ 1)~ E = π2~2

2mL2 {n21 + n2

2 + n23} ∆` = ±1

k = p

~∆E∆t ≥ ~

2

∆px∆x ≥ ~2 λmaxT = 2,898× 10−3m ·K λmin = hc

eV...

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