Post on 07-Apr-2016
description
3.1 Hasil PengamatanLangkah 1
a. Dik :1. A = Erl 2. A = Erl 3. A =
ErlangP(>0) = P(>0) = P(>0) =No A Tw/tm P(>0) Twq/tm t/tm P(>t) N Ω123
b. Dik :1. A = Erl 2. A = Erl
P(>0) = P(>0) =
Langkah 2a. Dik :
1. A = Erl 2. A = Erlt/tm = 0/3 t/tm = 0/3
No A t/tm P(>t) tw/tm P(>0) twq/tm N Ω123456
b. Dik :1. A = Erl 2. A = Erl
P(>t) ≤ P(>t) ≤No A P(>t) t/tm P(>0) twq/tm N tw/tm Ω
1
L ≥ i
L=i P ( L ≥ i ) P (L = i ) L ≥ i
L=i P ( L ≥ i ) P (L = i )
2
c. Dik :1. A = Erl 2. A = Erl
P(>t) ≤ P(>t) ≤t/tm = t/tm =
Langkah 3a. Dik :
1. A = Erl 2. A = Erlt/tm = t/tm =
No A t/tm N tm/tw P(>0) twq/tm P(>t) Ω 1 2
L ≥ i
L=i P ( L ≥ i ) P (L = i ) L ≥ i
L=i P ( L ≥ i ) P (L = i )
3 4 5 6 7 8 9
10
b. Dik :1. A = Erl 2. A = Erl
N = Server N = Server
No A N t/tm tw/tm P(>0) twq/tm P(>t) Ω1 2 3 4 5 6 7 8 9
10
c. Dik :A = 2 Erl A = ErlN = 5 Server N = Servert/tm = t/tm =
L ≥ i
L=i P ( L ≥ i ) P (L = i ) L ≥ i
L=i P ( L ≥ i ) P (L = i )
Langkah 4a. Dik :1. N = Server 2. N = Server 3. A =
P(>0) = P(>0) = P(>0) =
No A tw/tm P(>0) twq/tm t/tm P(>t) Ω123
b. Dik :1. N = Server 2. A = Server
P(>0) = P(>0) =
Langkah 5a. Dik :
1. N = Server 2. N = Servert/tm = 0/3 t/tm = 0/3
No N t/tm P(>t) A tw/tm P(>0) twq/tm P(>t) Ω123456
L ≥ i
L=i P ( L ≥ i ) P (L = i ) L ≥ i
L=i P ( L ≥ i ) P (L = i )
b. Dik :1. N = Server 2. N = Server
P(>t) ≤ P(>t) ≤
No N P(>t) t/tm tm/tw P(>0) twq/tm P(>t) Ω
c. Dik :1. N = Server 2. A = Server
P(>t) = P(>t) =t/tm = t/tm =
L ≥ i
L=i P ( L ≥ i ) P (L = i ) L ≥ i
L=i P ( L ≥ i ) P (L = i )