UTS Kindin Radi Poda Situmorang 1306447133
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Soal 1 NPM = 1306447133 Angka VI NPM : 4 (θ = 60 0 ) Angka VII NPM : 7 (ω = 10 rad/sec) Angka VIII NPM : 1 (arah ω CW) Angka IX NPM : 3 (α = 4 rad/sec 2 ) Angka X NPM : 3 (arah α CCW)
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Transcript of UTS Kindin Radi Poda Situmorang 1306447133
Soal 1
NPM = 1306447133
Angka VI NPM : 4 (θ = 600)Angka VII NPM : 7 (ω = 10 rad/sec)Angka VIII NPM : 1 (arah ω CW)Angka IX NPM : 3 (α = 4 rad/sec2)Angka X NPM : 3 (arah α CCW)
Soal 1
E
FBD
A
B
C
D
ω
α
E
Soal 1
NPM = 1306447133
Angka VI NPM : 4 (θ = 600)Angka VII NPM : 7 (ω = 10 rad/sec)Angka VIII NPM : 1 (arah ω CW)Angka IX NPM : 3 (α = 4 rad/sec2)Angka X NPM : 3 (arah α CCW)
A
B
C
D
E
Data :Rb = 1,65 cm Rc = 1,23 cm Rd = 4,49 cmRbc = 1,49 cm Rdc = 5,02 cm Rea = 6,66
Skala 1 cm = 0,3 m
Rb = 0,49 m Rc = 0,37 m Rd = 1,35 mRbc = 0,45 m Rdc = 1,52 m Rea = 1,98 m
θ
Vc
Vd
Skala 1 m/s = 0,5 cm
Panjang vektor sesuai skala :
Vc = ω x r = 10 rad/s x 0,49 m = 4,19 m/s = 2,09 cm
Vbc = 0,78 cm = 1,56 m/sVb = Vc + VbcVb = 2,87 cm = 5,75 m/s
rbc = 0,78 cm = 0,23 mωbc = Vbc/rbc = 1,56/0,23 = 6,78 rad/s
Vdc = 7,85 cm = 15,7 m/sVd = Vc + VdcVd = 9,94 cm = 19,89 m/s
Ve = Va + ω x Rea + Vea(xyz)Ve = 1,44 cm = 2,88 m/s
Vea(xyz) = 0,98 cm = 1,96 m/sVea(rotasi) = 1,12 cm = 2,24 m/s
ω = Vea(rotasi)/Rea = 2,24/6,64 = 0,34 rad/s2
Vb
Vbc
Vdc
Vea (xyz)
Vea
Vba
Ve
Vea (rotasi)
Kecepatan
Ac = Acn + Act
Acn = Ω2rc =102 x 0,37 = 37 m/s2 = 7,4 cmAct = αrc = 4 x 0,37 = 1,48 m/s2 = 0,29 cmAc = 7,4 cm = 14.8 m/s2
Ab = Ac + A(bc)t + A(bc)n
Ab = Ac + αrbc + Ω2rbc
Wbc = 6,78 rad/sA(bc)n = Ω2rbc = 6,782 x 0,45 = 20,7 m/s2 = 10,35 cmAb = 14,8 + (4x0,45) + 20,7Ab = 37,3 m/s2 =18,6 cm
Wb = Vb/rb = 5,75/0,49 = 11,7 rad/sAbn = Ωb
2rb = 11,72 x 0,49 = 67,4 m/s2 = 33,7 cm
Ad = Ac + A(dc)t + A(dc)n
Ad = Ac + αrdc + Ω2rdc
Wdc = Vdc/rdc = 15,7/1,52= 10 rad/s
A(dc)n = Ωd2rdc = 102 x 1,52= 152 m/s2 = 30,4
cmAd = 14,8 + (4x0,52) + 30,4Ad = 47,28 m/s2 = 23,6 cm
Wd = Vd/rd = 19,89/1,35 = 14,7 rad/sAdn = Ωd
2rd = 102 x 1,35 = 135 m/s2 = 67,5 cm
Ae = Aa + (Ω’ x rea ) + Ω x (Ω x rea) + 2Ω x Vea(xyz) + Aea(xyz)
Aen = Ve2/re = 2,882 /1,98 = 4,2 m/s2 = 2,1 cm
Ae = 16,19 cm = 32,38 m/s2
Aet = Ω x Vea(xyz) = 10 x 0,34) = 3,4 m/s2
Percepatan
Skala1 cm = 2 m/s2
Acn
Act
Ac
Abn Abt
Ab
Ad
Adt
Adn
Ab
Ae = 16,19 cm = 32,38 m/s2
Ae
Percepatan
Soal 2
NPM = 1306447133
Angka VI NPM : 4 (θ = 250)Angka VII NPM : 7 (ω = 10 rad/sec)Angka VIII NPM : 1 (arah ω CW)Angka IX NPM : 3 (α = 4 rad/sec2)Angka X NPM : 3 (arah α CCW)
= 10 rad/s = 4 rad/s2
C
O
B
AO’
E
FBD
= 10 rad/s = 4 rad/s2
C
O
B
AO’
E
Kecepatan
C
OB
A
O’
E
VB = VO + VBOVB = VBO = ω x r = 10 x 3,43 = 34,3 m/sVB = 3,43 cm
VA = VO + VAOVA = VAO = ω x r = 10 x 1,72 = 17,2 m/sVA = 1,72 cm
VBA = 3,03 cmVBA = 30,3 m/s
VE = VB + VEBVE = 2,57 cm = 25,7 m/s
VBE = 2,89 cm = 28,9 m/sωBE = 28,9 : 1,27 = 22,7 rad/s
VC = VE + VCEVC = 8,32 cm = 83,2 m/s
VCE = 5,79 cm = 57,9 m/sωCE = 57,9 : 5,78 = 10 rad/s
VCG = 41,6 m/s (Perbandingan V, R)
𝛼
Kecepatan
C
OB
A
O’
E 𝛼
Vb
Va
Vba
Ve
Vbe
Vcg
VceVc
aA = aAon + aAo
t aA = (ω2 x r) + (α x r)aA = (102 x 1,72) + (4 x 1,72)aA = 178,8 m/s2
aA = 1,79 cm
aB = aBon + aBo
t aB = (ω2 x r) + (α x r)aB = (102 x 3,43) + (4 x 3,43)aB = 356,72 m/s2
aB = 3,57 cm
aE = aB + aEBn + aEB
t aEB
n = vEB2 : rEB
aEBn = 28,92 : 1,27 = 657,65 m/s2
aEBn = 6,57 cm
aE0n = vE0
2 : Re0
aE0n = 25,72 : 2,57 = 257 m/s2
aE0n = 2,57 cm
aEn + aE
t = aB + aEBn + aEB
t 257 m/s2 + (α x rC0C) = 356,72 m/s2 + 657,65 m/s2 + (α x rCB)
aE = 0,8 cmaE = 0,8 x 50= 40 m/s2
aC = aE + aCEn + aCE
t aCE
n = vCE2 : rCE
aCEn = 83,22 : 5,78 = 1197,6 m/s2
aCEn = 11,97 cm
aC0n = vC
2 : rC0 aC0
n = 83,22 : 8,17 = 847,27 m/s2
aC0n = 8,47 cm
aCn + aC
t = aE + aCEn + aCE
t 847,27 m/s2 + (α x rE0C) = 40 m/s2 + 1197,6 m/s2 + (α x rEB)
PercepatanSkala 1cm = 50 m/s2
Percepatan
C
OB
A
O’
E 𝛼
Skala 1cm = 50 m/s2
AbAbt Abn
Aa
Aat
Aan
AaAe
Ae = 0,8 cm = 40 m/s2
