Units of magnec field: Tesla Surface of earth: 0.5×10 T Bar ...ishigami/Teaching/fall102049...nIa...

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Units of magne-c field: Tesla 1 T = 10000 Gauss Surface of earth: 0.5×10 ‐4 T Bar magnet: 1.5 T Strong superconduc-ng magnet: 30 T

Transcript of Units of magnec field: Tesla Surface of earth: 0.5×10 T Bar ...ishigami/Teaching/fall102049...nIa...

  • Units
of
magne-c
field:
Tesla


    1
T
=
10000
Gauss


    Surface
of
earth:
0.5×10‐4
T
Bar
magnet:


1.5
T
Strong
superconduc-ng
magnet:
30
T


  • dB =

    µ0I4π

    dS × r̂r2

    dS

    r

    Current


    Biot‐Savart
Law


    dB

    µ0 = 4π ×10

    −7T im / A

  • Infinite
straight
wire
example


  • Z


    a


  • a
.


    b
.
c
.


    d
.


    e
.


    The
segment
of
wire
(total
length
=
6R)
is
formed
into
the
shape
shown
and
carries
a
current
I.
What
is
the
magnitude
of
the


    resul-ng
magne-c
field
at
the
point
P?


  • a.



    b.


    c.



    d.


    e.


    The
segment
of
wire
(total
length
=
6R)
is
formed
into
the
shape
shown
and
carries
a
current
I.
What
is
the
magnitude
of
the


    resul-ng
magne-c
field
at
the
point
P?


  • Ques-on
1:
Equal
currents
of
magnitude
I
travel
into
the
page
in
wires
M
and
N.
Eight
direc-ons
are
indicated
by
leYers
A


    through
H.



    The
direc-on
of
the
magne-c

field
at
point
P
is


    a. 
B.
b. 
C.
c.  D.
d.  E.
e. 
F.


  • Solenoid


  • Z


    a


    B =µ0I2

    a2

    a2 + z2( )32

    Approximate
solenoid
as
bunch
of
separate
loops


  • Magne-c
field
at
the
center
of
the
solenoid


    L/2


    L
:
length
of
solenoid
n:
coil
density
(#/m)
a:
radius
of
the
coil


    Looks
like
integra-on
is
required
again,
but
how?


    a


  • Z


    dz
 Current
through
each
coil:
I
Number
of
coils
in
dz:
ndz


    dB = nµ0I2

    a2dz

    a2 + z2( )32

    B =µ0nI2

    a2dz

    a2 + z2( )32

    −L /2

    L /2

    B =µ0nIa

    2

    2L / 2

    a2 a2 + L4

    2⎛⎝⎜

    ⎞⎠⎟

    12

    −−L / 2

    a2 a2 + L4

    2⎛⎝⎜

    ⎞⎠⎟

    12

    ⎢⎢⎢⎢⎢⎢

    ⎥⎥⎥⎥⎥⎥

  • Z


    dz
Current
through
each
coil:
I
Number
of
coils
in
dz:
ndz


    B =µ0nIa

    2

    2L / 2

    a2 a2 + L4

    2⎛⎝⎜

    ⎞⎠⎟

    12

    −−L / 2

    a2 a2 + L4

    2⎛⎝⎜

    ⎞⎠⎟

    12

    ⎢⎢⎢⎢⎢⎢

    ⎥⎥⎥⎥⎥⎥

    B =µ0nIa

    2

    2L

    a2 a2 + L4

    2⎛⎝⎜

    ⎞⎠⎟

    12

    If
L>>a


    B ~ µ0nIa2

    2L

    a2 L4

    2⎛⎝⎜

    ⎞⎠⎟

    12

    =µ0nI2

    LL / 2

    = µ0nI

  • Z


    dz
What
about
the
field
at
the
very
end?


    B =µ0nI2

    a2dz

    a2 + z2( )32

    0

    L

    B =µ0nIa

    2

    2L

    a2 a2 + L2( )12

    −0

    a2 a2( )12

    ⎢⎢⎢

    ⎥⎥⎥

    B =µ0nIa

    2

    2L

    a2 (a2 + L2 )1/2

    If
L>>a


    B ~ µ0nIa2

    2L

    a2 L2( )12

    =µ0nI2

    LL=µ0nI2

  • B
µ0nI

  • Ampere’s
Law


    Current


    Amperian
Loop


    B ⋅dS = µ0∫ I

    Integral
evaluated
around
any
closed
path
where
I
is
the
total
current
passing
through

any
surface
defined
by
the
path


  • Example
1:
Inside
and
outside
of
a
wire


  • Example
2:
Solenoid


    d


  • Magne-c
Flux


    ΦB =

    B ⋅dA∫

  • From
last
Thursday:
Torque
on
current
loop
in
magne-c
field


    µ = IA

    µ
:
magne-c
moment


    Magne-c
field
applies
torque
on
magne-c
moment


  • Example:
Torque
on
magne-c
moment


    µ B

    Clicker
ques-on
#3:
Which
way
will
the
magne-c
field
try
to
orient
the
moment?


    a.  Clockwise
b.  Counter
clockwise
c.  Out
of
the
board
d.  Into
the
board