Steady Load Failure Theories (Distortion Energy Theory)
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Transcript of Steady Load Failure Theories (Distortion Energy Theory)
Steady Load Failure TheoriesSteady Load Failure Theories(Distortion Energy Theory)(Distortion Energy Theory)
Lecture 6Lecture 6
Engineering 473Engineering 473Machine DesignMachine Design
DistortionDistortion--Energy TheoryEnergy Theory
Postulate: Yielding will occur when the distortion-energy per unit volume equals the distortion-energy per unit volume in a uniaxial tension specimen stressed to its yield strength.
Strain EnergyStrain Energy
σ
ε
iσ
iε
U332211 εσ21εσ
21εσ
21U ++=
[ ] [ ] [ ] [ ]32 ininlb
inin
inlbU −=⋅=
UnitsThe strain energy in a tensile test specimen is the area under the stress-strain curve.
The strain energy per unit volume is given by the equation
Strain EnergyStrain Energy
Strain EnergyStrain Energy(Elastic Stress(Elastic Stress--Strain Relationship)Strain Relationship)
( )
( )
( )2133
3122
3211
νσνσσE1ε
νσνσσE1ε
νσνσσE1ε
−−=
−−=
−−=
��
��
�
��
��
�
���
���
�
−−−−−−
=��
��
�
��
��
�
3
2
1
3
2
1
σσσ
1ννν1ννν1
E1
εεε
Algebraic Format Matrix Format
An expression for the strain energy per unit volume in terms of stress only can be obtained by making use of the stress-strain relationship
Strain EnergyStrain Energy(Stress Form of Equation)(Stress Form of Equation)
( )
( )
( )���
��� −−+
���
��� −−+
���
��� −−=
++=
2133
3122
3211
332211
νσνσσE1σ
21
νσνσσE1σ
21
νσνσσE1σ
21
εσ21εσ
21εσ
21U
( )[ ]13322123
22
21 σσσσσσ2νσσσ
2E1U ++−++=
Distortion and Hydrostatic Distortion and Hydrostatic Contributions to Stress StateContributions to Stress State
1σ
2σ
3σ
Principal Stresses Principal Stresses Acting on Principal Acting on Principal
PlanesPlanes
hσ
hσ
hσ
h1 σσ −
h2 σσ −
h3 σσ −
3σσσσ 321
h++=
Hydrostatic StressHydrostatic StressDistortional StressesDistortional Stresses
= +
The distortional stress components are often called the deviatoric stress components.
Physical SignificancePhysical Significance(Hydrostatic Component)(Hydrostatic Component)
hσ
hσ
hσ
3σσσσ 321
h++=
The hydrostatic stress causes a change in the volume.
strain volumetriceModulusBulk K
Keσh
≡≡=
The cube gets bigger in tension,smaller in compression.
Physical SignificancePhysical Significance(Distortional Stresses)(Distortional Stresses)
h1 σσ −
h2 σσ −
h3 σσ −
These unequal stresses act to deform or distort the material element.
There is no change in volume, but there is a change in shape.
These stresses try to elongate or compress the material more in one direction than in another.
Strain Energy Associated with the Strain Energy Associated with the Hydrostatic StressHydrostatic Stress
( )[ ]( )[ ]
[ ]( ) 2
hh
2h
2h
hhhhhh2h
2h
2hh
13322123
22
21
σE2ν-1
23U
σ6νσ32E1
σσσσσσ2νσσσ2E1U
σσσσσσ2νσσσ2E1U
=
⋅−=
++−++=
++−++=
This term is equal to the strain energy per unit volume from the hydrostatic stress components.
Distortional Strain EnergyDistortional Strain Energy
( )[ ]( ) ( )
( )[ ]
( )����
�
�
����
�
�
+++
+++
++−−
++−++=
++−−
++−++=
−=
323123
322122
312121
13322123
22
21
2321
13322123
22
21
hd
σσσσσ
σσσσσ
σσσσσ
3E2ν1
21
σσσσσσ2νσσσ2E1
9σσσ
E2ν1
23
σσσσσσ2νσσσ2E1
UUU
The distortional strain energy is equal to the difference between the total strain energy and the hydrostatic strain energy.
Distortional Strain EnergyDistortional Strain Energy(Continued)(Continued)
[ ]13322123
22
21d σσσσσσσσσ
3Eν1U −−−+++=
( )[ ]( ) ( )( )133221
23
22
21
13322123
22
21
hd
σσσσσσ2σσσ3E
2ν121
σσσσσσ2νσσσ2E1
UUU
+++++−−
++−++=
−=
Distortional Strain Energy in Tension Distortional Strain Energy in Tension Test SpecimenTest Specimen
[ ]2yd
13322123
22
21d
S3Eν1U
σσσσσσσσσ3Eν1U
+=
−−−+++=
Hamrock, Fig. 3.1
Postulate: Yielding will occur when the distortion-energy per unit volume equals the distortion-energy per unit volume in a uniaxial tension specimen stressed to its yield strength.
Distortion Energy Failure TheoryDistortion Energy Failure Theory
[ ]
13322123
22
21eff
yeff
13322123
22
21
2y
2y
13322123
22
21d
σσσσσσσσσσ
Sσ
σσσσσσσσσS
S3Eν1
σσσσσσσσσ3Eν1U
−−−++=
=
−−−++=
+=
−−−+++=
Equating the distortional strain energy at the point under consideration to the distortional strain energy in the tensile test specimen at the yield point yields
Alternate Forms of Effective StressAlternate Forms of Effective Stress
( ) ( ) ( )2
σσσσσσσ
σσσσσσσσσσ
213
232
221
eff
13322123
22
21eff
−+−+−=
−−−++=
theory. the todcontribute whoMises von R. Dr.after stress, Mises von theas to
referredcommonly is stress effective The
Form 1
Form 2
Plane Stress ConditionPlane Stress Condition
( )2
σσσσσ
σσσσσ
21
22
221
eff
2122
21eff
++−=
−+=
0σ3 =
yS
yS
yS-
yS-
1σ
2σ
� As long as the stress state falls within the shaded area, the material will not yield.
� The surface, blue line, at which the material just begins to yield is called the yield surface.
Pure Shear ConditionPure Shear Condition
Mohr�s Circle for Pure Shear
1σ2σ
3σ
1,3τ
13 σσ −=
yS
yS
yS-
yS-
1σ
3σ
ysymax
y2max
21
3123
21eff
SS0.577τ
S3τσ3
σσσσσ
=⋅=
===
−+=
°45
This is an important result.This is an important result.
Yield Surface in 3Yield Surface in 3--D Stress StateD Stress State
Hamrock, Fig. 6.9
Other Names for Distortion Other Names for Distortion Energy TheoryEnergy Theory
( ) ( ) ( )2
σσσσσσσ2
132
322
21eff
−+−+−=
�Shear Energy Theory�Von Mises-Hencky Theory�Octahedral-Shear-Stress Theory
People came up with the same equation using different starting
points.1σ2σ3σ σ
τ1/3τ
1/2τ2/3τ
321 σσσ >>
AssignmentAssignment� Show that the two forms of the equation for the effective stress
are equal.� Show that the effective stress for a hydrostatic stress state is
zero.� Compute the effective stress at the critical location in the
stepped shaft loaded in tension (previous assignment). The yield strength of the material is 30 ksi. Will the material yield at the critical location?
( ) ( ) ( )2
σσσσσσσ
σσσσσσσσσσ
213
232
221
eff
13322123
22
21eff
−+−+−=
−−−++=
AssignmentAssignment(Continued)(Continued)
In the rear wheel suspension of the Volkswagen �Beetle� the spring motion was provided by a torsion bar fastened to an arm on which the wheel was mounted. See the figure for more details. The torque in the torsion bar was created by a 2500-N force acting on the wheel from the ground through a 300-mm lever arm. Because of space limitations, the bearing holding the torsion bar was situated 100-mm from the wheel shaft. The diameter of the torsion bar was 28-mm. Find the von Mises stress in the torsion bar at the bearing.
Hamrock, Fig. 6.12