Selected HW #3 Answers - Auburn Universitydmbevly/mech3140/hw3_sol.pdfSelected HW #3 Answers 4.4 2 1...

Selected HW #3 Answers 4.4 2 1 2 3 2 2 2 1 L L k L k k e + = 4.5 k k e 36 29 = 4.6 2 1 2 1 k k k k k e + = , i i i L EA k = 4.13 0 2 1 2 = + x R R k x m 4.14 0 ) cos( ) sin( 2 2 2 1 = + θ θ θ kD mD 4.15 0 ) sin( ) ( 2 = + + θ θ mgD mD I CG 4.16 0 ) ( 2 2 1 = + + x kR x R m I 4.17 1 2 2 2 2 2 2 2 1 2 1 1 1 ) ( x k f x k x m x k x k k x m + = + = + + 4.22 ) ( ) ( ) ( 1 2 1 s k k Is k s s + + = φ θ 4.23 ky kx x R I m = + + 2 4.24 1 2 2 3 2 2 2 2 2 1 2 1 1 1 ) ( ) ( x k x k k x m x k x k k x m = + + = + + 4.25 1 2 2 2 3 2 2 2 2 2 1 2 1 1 1 ) ( ) ( θ θ θ θ θ θ k T k k I k k k I + = + + = + + 4.26

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Transcript of Selected HW #3 Answers - Auburn Universitydmbevly/mech3140/hw3_sol.pdfSelected HW #3 Answers 4.4 2 1...

Selected HW #3 Answers

4.4 21

232

221

LLkLk

ke+

4.5 kke 3629

4.6 21

kkkkke +

= , i

ii L

EAk =

4.13 02

2 =

+ x

RRkxm

4.14 0)cos()sin(2

1 =+ θθθ kDmD 4.15 0)sin()( 2 =++ θθ mgDmDICG

4.16 0)( 22

1 =++ xkRxRmI

4.17 122222

2212111 )(xkfxkxm

xkxkkxm+=+=++

4.22 )()(

)(

skkIsk

++=

φθ

4.23 kykxxRIm =+

4.24 1223222

2212111

)()(

xkxkkxmxkxkkxm

=++=++

4.25 12223222

2212111

)(

θθθ

kTkkI

kkkI

+=++

=++

4.26

Page 2: Selected HW #3 Answers - Auburn Universitydmbevly/mech3140/hw3_sol.pdfSelected HW #3 Answers 4.4 2 1 2 2 3 2 1 2 L k L k e + = 4.5 k e k 36 29 = 4.6 1 2 1 2 k k k k k e + = , i i i

4.30 0)( 212 =++

+ xkkx

RIm

4.32 044 221 =+

++ kxx

RImm

4.56 pTdTdd

TpTpTpp

ccI

kkcI

θθθ

φθθθ

+=++

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