Real Analysis I Assignment 1, due September 30 · Real Analysis I Assignment 1, due September 30...

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Real Analysis I Assignment 1, due September 30 Problem 1 of 5. Let E be a collection of n subsets of a set X . Prove that M(E ) is finite. What is the maximal number of elements of M(E )? Problem 2 of 5. Let M be an infinite σ-algebra. Show that ... 1. M contains an infinite sequence of disjoint non-empty sets; 2. M is uncountable. Problem 3 of 5. Let (X, M) be a measure space, and consider a sequence {E j } j 1 in M. Define lim inf E j = [ k1 \ j =k E i , lim sup E j = \ k1 [ j =k E i . 1. Show that lim inf E j = {x : x E j for all but finitely many j } , lim sup E j = {x : x E j for infinitely many j } . Conclude that lim inf E j lim sup E j . 2. Give an example of a sequence {E j } where lim inf E j 6= lim sup E j . 3. If the limits supremum and infimum are equal, then their common value is called the limit of the sequence of sets E j . Prove that the limit of a sequence of sets E j exists if and only if the sequence of characteristic functions of the E j has a limit. 4. Show that μ(lim inf E j ) lim inf μ(E j ). If μ( S j =1 E j ) < , then also μ(lim sup E j ) lim sup μ(E j ). Problem 4 of 5 (The Borel-Cantelli lemma). Let (X, M) be a measure space. Suppose (E j ) j 1 is a sequence of measurable sets with the property that X j =1 μ(E j ) < . Show that μ(lim sup E j ) = 0, i.e. for μ-a.e. x n(x): j>n(x),x/ E j .

Transcript of Real Analysis I Assignment 1, due September 30 · Real Analysis I Assignment 1, due September 30...

Real Analysis IAssignment 1, due September 30

Problem 1 of 5.

Let E be a collection of n subsets of a set X. Prove thatM(E) is finite. What is the maximalnumber of elements of M(E)?

Problem 2 of 5.

Let M be an infinite σ-algebra. Show that ...

1. M contains an infinite sequence of disjoint non-empty sets;

2. M is uncountable.

Problem 3 of 5.

Let (X,M, µ) be a measure space, and consider a sequence {Ej}j≥1 in M. Define

lim inf Ej =∞⋃k≥1

∞⋂j=k

Ei , lim supEj =∞⋂k≥1

∞⋃j=k

Ei .

1. Show that

lim inf Ej = {x : x ∈ Ej for all but finitely many j} ,lim supEj = {x : x ∈ Ej for infinitely many j} .

Conclude that lim inf Ej ⊂ lim supEj.

2. Give an example of a sequence {Ej} where lim inf Ej 6= lim supEj.

3. If the limits supremum and infimum are equal, then their common value is called thelimit of the sequence of sets Ej. Prove that the limit of a sequence of sets Ej exists ifand only if the sequence of characteristic functions of the Ej has a limit.

4. Show that µ(lim inf Ej) ≤ lim inf µ(Ej).If µ(

⋃∞j=1Ej) <∞, then also µ(lim supEj) ≥ lim supµ(Ej).

Problem 4 of 5 (The Borel-Cantelli lemma).

Let (X,M, µ) be a measure space. Suppose (Ej)j≥1 is a sequence of measurable sets withthe property that

∞∑j=1

µ(Ej) <∞ .

Show that µ(lim supEj) = 0, i.e. for µ-a.e. x ∃n(x): ∀j > n(x), x /∈ Ej.

Problem 5 of 5.

Let µ∗ be an outer measure on X induced from a premeasure µ0, and let µ be the restrictionof µ∗ to the σ-algebra M of µ∗-measurable sets.

1. Prove that µ∗(A) = infE∈M:E⊃A

µ(E) for all A ⊂ X.

2. If µ0(X) <∞, define the inner measure of a set A ⊂ X byµ∗(A) = µ0(X)− µ∗(Ac). Prove that A is measurable, if and only if µ∗(A) = µ∗(A).

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