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### Transcript of Position, Velocity, and Acceleration Conclusion zThe velocity function is found by taking the...

• Position, Velocity, and Position, Velocity, and AccelerationAcceleration

Mr. MiehlMr. Miehl www.tesd.net/miehlwww.tesd.net/miehl miehlm@tesd.netmiehlm@tesd.net

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

Velocity is the rate of change of position with respect to time.

Acceleration is the rate of change of velocity with respect to time.

DVelocity T

Δ = Δ

VAcceleration T

Δ = Δ

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

Warning: Professional driver, do not attempt!

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

squeeeeek!

…and you jam on the brakes…

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

…and you feel the car slowing down…

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

…what you are really feeling…

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

…is actually acceleration.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

I felt that acceleration.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration How do you find a function that describes a physical event?

Steps for Modeling Physical Data

1) Perform an experiment.

2) Collect and graph data.

3) Decide what type of curve fits the data.

4) Use statistics to determine the equation of the curve.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A crab is crawling along the edge of your desk. Its location (in feet) at time t (in seconds) is given by P (t ) = t 2 + t.

a) Where is the crab after 2 seconds?

b) How fast is it moving at that instant (2 seconds)?

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A crab is crawling along the edge of your desk. Its location (in feet) at time t (in seconds) is given by P (t ) = t 2 + t.

a) Where is the crab after 2 seconds?

( ) ( ) ( )22 2 2P = +

( )2 6P = feet

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A crab is crawling along the edge of your desk. Its location (in feet) at time t (in seconds) is given by P (t ) = t 2 + t.

( ) 2= +P t t t ( ) ( )'= =V t P t

feet per second

b) How fast is it moving at that instant (2 seconds)?

2 1+t

( ) ( )' 2 2 2 1= +P ( )' 2 5=P

Velocity function

Velocity is the rate of change of position.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration

A disgruntled calculus student

hurls his calculus book in the air.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration The position of the calculus book:

( ) 216 96p t t t= − + t is in seconds and p(t) is in feet

a) What is the maximum height attained by the book?

b) At what time does the book hit the ground?

c) How fast is the book moving when it hits the ground?

• Position, Velocity & AccelerationPosition, Velocity & Acceleration a) What is the maximum height attained by the book?

( ) 216 96p t t t= − + ( )v t = ( )p t′ = 32 96t− +

Velocity function

0 32 96t= − + 32 96t =

3t = seconds

( ) ( ) ( )23 16 3 96 3p = − + ( )3 144 288p = − + ( )3 144p = feet

The book attains its maximum height when its velocity is 0.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration b) At what time does the book hit the ground?

The book hits the ground when its position is 0.

( ) 216 96p t t t= − + 20 16 96t t= − +

0 16 ( 6)t t= − −

16 0t− = 6 0t − = 0t = 6t =sec. sec.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration c) How fast is the book moving when it hits the ground?

Good guess: 0 ft/sec This is incorrect.

( ) 32 96v t t= − + ( ) ( )6 32 6 96v = − + ( )6 192 96v = − + ( )6 96v = − ft/sec

Downward direction

• Position, Velocity & AccelerationPosition, Velocity & Acceleration the rate of change of velocity with respect to time.

Acceleration:

( ) 32 96v t t= − + ( ) ( ) 32a t v t′= = − ft/sec2

How is the acceleration function related to the position function?

Velocity function

Acceleration function

Acceleration is the second derivative of position.

( ) ( )a t p t′′= Jerk is the rate of change of acceleration with respect to time.

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A red sports car is traveling, and its position P (in miles) at time t (in hours) is given by P (t ) = t 2 – 7t.

a) When is the car 30 miles from where it started?

b) What is the velocity at the very moment the car is 30 miles away?

d) When does the car stop?

c) What is the acceleration at the very moment the car is 30 miles away?

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A red sports car is traveling, and its position P (in miles) at time t (in hours) is given by P (t ) = t 2 – 7t.

a) When is the car 30 miles from where it started?

230 7= −t t

20 7 30= − −t t

( )( )0 10 3= − +t t 10 0− =t 3 0+ =t

10=t 3= −thours

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A red sports car is traveling, and its position P (in miles) at time t (in hours) is given by P (t ) = t 2 – 7t.

b) What is the velocity at the very moment the car is 30 miles away?

( ) ( )' 2 7= = −V t P t t ( ) ( )' 2 7= = −V t P t t

( ) ( )' 10 2 10 7= −P

( )' 10 13=P Miles per hour

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A red sports car is traveling, and its position P (in miles) at time t (in hours) is given by P (t ) = t 2 – 7t.

c) What is the acceleration at the very moment the car is 30 miles away?

( ) ( )' 2 7= = −V t P t t ( ) ( )'' 2= =A t P t Miles per hour2

• Position, Velocity & AccelerationPosition, Velocity & Acceleration A red sports car is traveling, and its position P (in miles) at time t (in hours) is given by P (t ) = t 2 – 7t.

d) When does the car stop?

( ) ( )' 2 7= = −V t P t t 0 2 7= −t

7 2= t

3.5=t hours

• ConclusionConclusion The velocity function is found by taking the derivative The velocity function is found by taking the derivative of the of the positionposition function.function.

In order for an object traveling upward to obtain In order for an object traveling upward to obtain maximum position, its instantaneous velocity must maximum position, its instantaneous velocity must equal equal 00..

As an object hits the ground, its velocity is not 0, its As an object hits the ground, its velocity is not 0, its heightheight is 0.is 0.

The acceleration function is found by taking the The acceleration function is found by taking the derivative of the derivative of the velocityvelocity function.function.

Position, Velocity, and Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Position, Velocity & Acceleration Conclusion