PFD (T1) = λdd * RT + λ * T1/2 · PFD avg (T1) = λ dd * RT + λ du * T1/2 because of RT (avg....

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PFD avg (T1) = λ dd * RT + λ du * T1/2 because of RT (avg. repair time) is << T1 PFD avg = λ du * T1/2 e.g. 2W3A00 AC SIL Pressure I λ du = 69 T(proof) = 10 years PFD avg = (λ du * 10 -9 ) * (10years/2) = (69* * 10 -9 ) * (8760/2) = 3,02220E-03 SIL = SIL2 Type λ du SFF PFD Class PFD Class PFD Class T = 10 Years T = 1 Year T = 3 Month 2W2D00 SIL Pressure 84 81.4% 3,67920E-03 Sil2 3,67920E-04 Sil2 9,19800E-05 Sil2 2W2DO0 SIL Temperature 80 83.2% 3,50400E-03 Sil2 3,50400E-04 Sil2 8,76000E-05 Sil2 2W3A00 AC SIL Pressure I 69 86.5% 3,02220E-03 Sil2 3,02220E-04 Sil2 7,55550E-05 Sil2 2W3A00 AC SIL Temperature 66 87.6% 2,89080E-03 Sil2 2,89080E-04 Sil2 7,22700E-05 Sil2 2W3A00 DC SIL Pressure 69 86.5% 3,02220E-03 Sil2 3,02220E-04 Sil2 7,55550E-05 Sil2 2W3A00 DC SIL Temperature 66 87.6% 2,89080E-03 Sil2 2,89080E-04 Sil2 7,22700E-05 Sil2 2WLP4x SIL Pressure 75 83.6% 3,28500E-03 Sil2 3,28500E-04 Sil2 8,21250E-05 Sil2 2WLP4x SIL Temperature 72 84.9% 3,15360E-03 Sil2 3,15360E-04 Sil2 7,88400E-05 Sil2 4W3A01 SIL Pressure 72 87.5% 3,15360E-03 Sil2 3,15360E-04 Sil2 7,88400E-05 Sil2 4W3A01 SIL Temperature 68 88.4% 2,97840E-03 Sil2 2,97840E-04 Sil2 7,44600E-05 Sil2 8W2D4x SIL Pressure 75 83.6% 3,28500E-03 Sil2 3,28500E-04 Sil2 8,21250E-05 Sil2 8W2D4x SIL Temperature 72 84.9% ` 3,15360E-03 Sil2 3,15360E-04 Sil2 7,88400E-05 Sil2 UE confirms that the „One Series“, described and tested by EXIDA (Contract No.: UE 05/10-35; Report No.: UE 05/10-35 R001) and classified as a Type B component (IEC 61508-1 section 7.4.3.1.3), fulfills the criteria for a calculation of PFD AVG (such as proof test interval) and therefore can be classified as SIL 2 under the rules of inspection and maintenance, described in the user manual.

Transcript of PFD (T1) = λdd * RT + λ * T1/2 · PFD avg (T1) = λ dd * RT + λ du * T1/2 because of RT (avg....

Page 1: PFD (T1) = λdd * RT + λ * T1/2 · PFD avg (T1) = λ dd * RT + λ du * T1/2 because of RT (avg. repair time) is

PFDavg (T1) = λdd * RT + λdu * T1/2

because of RT (avg. repair time) is << T1

PFDavg = λdu * T1/2

e.g. 2W3A00 AC SIL Pressure I

λdu = 69

T(proof) = 10 years

PFDavg = (λdu * 10-9

) * (10years/2) = (69** 10-9

) * (8760/2) = 3,02220E-03

SIL = SIL2

Type λdu SFF PFD Class PFD Class PFD Class

T = 10 Years T = 1 Year T = 3 Month

2W2D00 SIL Pressure 84 81.4% 3,67920E-03 Sil2 3,67920E-04 Sil2 9,19800E-05 Sil2

2W2DO0 SIL Temperature 80 83.2% 3,50400E-03 Sil2 3,50400E-04 Sil2 8,76000E-05 Sil2

2W3A00 AC SIL Pressure I 69 86.5% 3,02220E-03 Sil2 3,02220E-04 Sil2 7,55550E-05 Sil2

2W3A00 AC SIL Temperature 66 87.6% 2,89080E-03 Sil2 2,89080E-04 Sil2 7,22700E-05 Sil2

2W3A00 DC SIL Pressure 69 86.5% 3,02220E-03 Sil2 3,02220E-04 Sil2 7,55550E-05 Sil2

2W3A00 DC SIL Temperature 66 87.6% 2,89080E-03 Sil2 2,89080E-04 Sil2 7,22700E-05 Sil2

2WLP4x SIL Pressure 75 83.6% 3,28500E-03 Sil2 3,28500E-04 Sil2 8,21250E-05 Sil2

2WLP4x SIL Temperature 72 84.9% 3,15360E-03 Sil2 3,15360E-04 Sil2 7,88400E-05 Sil2

4W3A01 SIL Pressure 72 87.5% 3,15360E-03 Sil2 3,15360E-04 Sil2 7,88400E-05 Sil2

4W3A01 SIL Temperature 68 88.4% 2,97840E-03 Sil2 2,97840E-04 Sil2 7,44600E-05 Sil2

8W2D4x SIL Pressure 75 83.6% 3,28500E-03 Sil2 3,28500E-04 Sil2 8,21250E-05 Sil2

8W2D4x SIL Temperature 72 84.9% ` 3,15360E-03 Sil2 3,15360E-04 Sil2 7,88400E-05 Sil2

UE confirms that the „One Series“, described and tested by EXIDA (Contract No.: UE 05/10-35; Report No.: UE 05/10-35 R001) and classified as a Type B component (IEC 61508-1 section 7.4.3.1.3), fulfills the criteria for a calculation of PFDAVG (such as proof test interval) and therefore can be classified as SIL 2 under the rules of inspection and maintenance, described in the user manual.