Science w/ Ms. Hendryx 1/17/12. 1.Felectric= 2.PEelectric= 3.C = 4.Power Law: P = 5.Ohm’s Law: V =
Ohm’s Law: V = IR Power dissipated (Joule heating) = P = I ...
Transcript of Ohm’s Law: V = IR Power dissipated (Joule heating) = P = I ...
Kirchoff’s Loop equation:
Kirchoff’s junction rule:
Resistors in series: Req = R1 + R2 + …
Resistors in parallel: Req-1 = R1
-1 + R2-1 +…
Capacitors in series: Ceq-1 = C1
-1 + C2-1 + …
Capacitors in parallel: Ceq = C1 + C2 + …
0iclosed loopVΣ =
/0ientering leaving junction
IΣ =
Group Problems1. R combo – all 100 Ω
a) Find I from the batteryb) Find I through each R2. a) Find equivalent R (in terms of R)
b) Find the batterycurrent if R = 100 Ω
R4
R2R1
R5
R325V
R
R
10V
R
R
Simple RC Series circuit
• Discharging: Q(t) = Qoexp(-t/RC)and I(t) = Ioexp(-t/RC)
0
0.2
0.4
0.6
0.8
1
0 10 20 30 40 50 60
time (ms)
Norm
aliz
ed Q
or
I
When t = RC = 1 time constant, then Q = Qoexp(-1) = 0.37Qo
Microscopic Picture of Electric Current
• E field in wire produces forces on free electrons leading to a net drift velocity: vdrift = aτ, where a is
the acceleration (a = F/m = eE/m = e(V/L)/m where V is the applied voltage across the wire of length L) and τ is the mean-free time between collisions
• Solving for the charge drifting by allows us to compute the current I: I=[(ne2τ/m)(A/L)]V = [1/R]V = GV, where n is the free charge density, e is the electron charge, A is the wire cross-sectional area, R is the wire’s resistance and G is its conductance
• We can also introduce intrinsic parameters: conductivity, σ = ne2τ/m and resistivity, ρ = 1/σto write R = ρL/A
retinal “starburst” cell (red) found in visual processing network, Courtesy of Thomas Euler, Max Planck Institute for Medical Research, Heidelberg
x x + Δ x x + 2Δ x
I n s id e
O u ts id e
cΔ x cΔ x cΔ xgΔ x gΔ x gΔ x
r iΔ x r iΔ x
r oΔ x r oΔ x
I i(x ) I i(x + Δ x ) I i(x + 2Δ x )
Io(x ) Io(x + Δ x ) Io(x + 2Δ x )
Im (x ) Im (x + Δ x ) Im (x + 2Δ x ) V M (x ,t) V M (x + Δ x ,t)
V V V