Moon River
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How Tides Affect the Volumetric Flow of the Columbia River
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Moon River. How Tides Affect the Volumetric Flow of the Columbia River. Volumetric Flow. Q = A*C The volume of fluid = Q A circle = πr 2 C = Velocity of the water. Volumetric Flow Through a Pipe. Plugging in the data… Given: Pipe – 2 m, Velocity = 4m/s Equations: Q = A*C - PowerPoint PPT Presentation
Transcript of Moon River
How Tides Affect the Volumetric Flow of the Columbia River
Q = A*CThe volume of fluid = QAcircle = πr2
C = Velocity of the water
Plugging in the data…Given: Pipe – 2 m, Velocity = 4m/sEquations: Q = A*C Acircle = πr2 =
A = 3 * (2)2. Area = 12 m2
C = Velocity of the water
C = 4 m/s
Q = (12 m2) * (4 m/s)
Q = 48 m3/s
What would the volumetric flow be if we slowed the water flowing into the pipe, and the pipe was only ½ filled with water?
Q = 48 m3/s / 2
Q = 24 m3/s
Given:Depth of the Columbia River: 12.5 mVelocity (C) at 7 m = 2.25 m/s
Equations: Q = A*C Acircle = πr2
The river can be thought of as a ½ pipe, so the surface area should be halved.
Given:Depth of the Columbia River: 12.5 mVelocity (C) at 7 m = 2.5 m/s
Equations: Q = A*C Acircle = πr2
(3)(12.5)2 = 469 m2. Because the river is like a ½ pipe…469/2 = 234.5 m2.
Given:Depth of the Columbia River: 12.5 mVelocity (C) at 7 m = 2.25 m/s
Equations: Q = A*C Acircle = 234.5 m2.
C = 2.25 m/sQ = (234.5 m2)(2.25 m/s) Q = 527.6 m3/s
