Mass Transport Tafel plot: reduction of Mn(IV) to Mn(III ...aroudgar/Tutorials/lecture18-20.pdf ·...
Transcript of Mass Transport Tafel plot: reduction of Mn(IV) to Mn(III ...aroudgar/Tutorials/lecture18-20.pdf ·...
CHEM465/865, 2006-3, Lecture 18, Oct. 16, 2006
Mass Transport
Tafel plot: reduction of Mn(IV) to Mn(III) at Pt in 7.5 M H2SO4 at 298 K, various concentrations.
E [V] vs. SHE
log 1
0[ j/
(A c
m-2
) ]
-η = E0 - E
E0
0
Corresponds to the following reaction scheme (cathodic
process, reduction), 0η < :
We have seen, how the rate of the reaction is influenced by E and by surface concentrations of involved species. Consider expression for the encountered current:
( ) ( )CCC C,0 s
ox
01exp
F E EIj nFk cA RT
α⎛ ⎞− −⎜ ⎟− = = − −⎜ ⎟⎝ ⎠
Note: sign of current and 0 0E E− <
Tafel-plot: electroanalytical tool to determine
(cathode) exchange current density C,0j
Tafel-slope ( )C
2.31
RTbFα
=−
(cathode) transfer coefficient Cα . Current depends exponentially on E. However, current cannot grow unlimitedly with E. Progress of a reaction is accompanied by concentration variations toward
interior of solution → affects a region that grows in
thickness with time!
Three forms of mass transport: diffusion: nonuniform concentrations + entropic “forces”, acting to smooth the uneven distributions
convection: action of a force on the solution (pump, gas flow in pressure gradient, hydraulic permeation, gravity, etc.). E.g. convection under laminar flow conditions:
ox oxx
c cvt x
∂ ∂= −
∂ ∂
migration: electrostatic effect, voltage variation in solution, difficult to calculate for real solutions due to ion solvation effects – try to avoid migration by adding supporting, inert electrolyte which levels potential variations in solution. Current density in solution with conductivity σ :
S
Ohmjxϕσ ∂
= −∂
Overall: Flux of electrical current at electrode involves electrode kinetics, and 3-dimensional diffusion, convection and migration – consistent treatment of all these effects within one system is impossible, in experiment as well as in theory!
⇒ understand conditions and electrode geometries under which mass transport limitations can be avoided Diffusion-limitations Transport of matter by random molecular motion (maximum entropy → striving for uniform distributions). Two limiting cases (as usual, realistic situations are between these limits):
rate of reaction >> rate of diffusion rate of reaction << rate of diffusion
Which case did we consider so far???
Now: Let’s focus on diffusion Diffusion normal to electrode surface (x-direction)
Fick’s first law (1855): ox
diffcJ Dx
∂= −
∂
Fick’s second law (1855): ox ox
2
2
c cDt x
∂ ∂=
∂ ∂
Fick’s second law: permits prediction of variation of concentration of different species as a function of position and time (need initial and boundary conditions) Important analogy: heat conduction Can be solved with all sorts of boundary and initial condition. Usually, the solution involves Laplace transforms. (for details: see J. Crank, The Mathematics
of Diffusion, 2nd Edition, 1975, Oxford University Press and H.S. Carslaw, J.C. Jaeger, Conduction of Heat in Solids, Oxford University Press 1959).
Evaluate: How does diffusion affect current measured at an electrode?
Semiempirical treatment Comparison with full analytical solution Potential sweep experiment
Potential step experiment (using potentiostat)
E0
t0
E
1. Current limited entirely by diffusion
surface concentration: sox 0c ≈
oxc
x/µm10 20 30 Every reactant molecule that arrives at interface reacts immediately In which region of the Tafel-plot are we now? Region, where current does not depend on E any more!
oxc
x/µm10 20 30
δ
How deep does the disturbance penetrate into the solution? ⇒ mean free path or diffusion layer thickness:
Dtδ π≈
e.g. oxygen in solution: 2cm
s52.55 10D −≈ ⋅
⇒ µm90δ ≈ after 1s
What are the currents that diffusion can sustain?
s b box ox ox ox
diffc c c cj nFD nFD nFDx δ δ
∂ −= − ≈ − =
∂
Insert δ: b
diff oxDj nFctπ
= Cottrell-equation
boxc (no current)0E E≈
oxc
x/µm
δ10-3s
10-2s
10-1s
b (diffusion limited current)0E E−
10 20 30
0E E b− >>
Diffusion-limited current decreases with time! The longer a measurement takes, the more severe are the diffusion limitations. Reactant supplied from more distant regions.
How do concentration profiles and ( )diffj t look like?
box
2
0 2
,C mol,
mol l, cm s,
, A cm
5
5
1964851
2.55 100.510
nFc
D
jα
−
−
==
=
= ⋅=
=
0.0 0.5 1.00
1
2
3
j diff /
A c
m-2
t/s
bdiff ox
Dj nFctπ
=
2. Kinetic limitations and mass transport: MIXED KINETICS!
Finite surface concentration 0c >sox and balance of fluxes
⇒ boundary condition at electrode surface:
bs soxox ox and
00
00
exp
1 exp
E Ecc j nFk c
bE EtkD bπ
⎛ ⎞−⎜ ⎟= =⎜ ⎟⎛ ⎞− ⎝ ⎠⎜ ⎟+
⎜ ⎟⎝ ⎠
( )
Cdiff
Csox
rate of consumption (kinetics) = rate of supply (transport)
=
0
01
exp
j j
F E EnFk c
RTα⎛ ⎞− −
⎜ ⎟⎜ ⎟⎝ ⎠
ox
b ss ox oxox
sox
=
=
again use simple semiempirical treatment
insert
0
00
0
-
exp
exp
x
cnFD
x
E E c ck c D
b
Ek c
δ
δ
=
∂∂
⎛ ⎞− −⎜ ⎟⎜ ⎟⎝ ⎠
− ( )b sox ox
sox
=
and solve f
or
0E Dc cb t
c
π
⎛ ⎞⎜ ⎟ −⎜ ⎟⎝ ⎠
and, thus
C box, wher e
0
0* 0* 00
0
exp
1 exp
E Eb
j j j nFk cE Etk
D bπ
⎛ ⎞−⎜ ⎟⎜ ⎟⎝ ⎠= =
⎛ ⎞−⎜ ⎟+⎜ ⎟⎝ ⎠
With definitions of diffj and 0*j this can be rewritten
C bdiff ox
*diff
with (Cottrell)
E Eb Dj j j nFc
tE Ejj b
⎛ ⎞−⎜ ⎟⎜ ⎟⎝ ⎠= =
⎛ ⎞−⎜ ⎟+⎜ ⎟⎝ ⎠
0
0* *00*
exp
1 ex
,
pπ
Be aware that diffj is a function of time!
Two important limiting cases are reproduced
Kinetic limitations more severe, diffj j<<0* * :
C 0
0* expE E
j jb
⎛ ⎞−⎜ ⎟=⎜ ⎟⎝ ⎠
Tafel-equation
Diffusion limitations more severe, diffj j>>0* * :
C box Dj nFc
tπ= Cottrell-equation
Two handles to steer between the limiting cases: t and E
Show results for
box
2
0* 2
0
, C mol,
mol l, cm s,
, A cm cm s
mV (298 K)
5
5
7
1964851
2.55 100.51010 ,
25.7
nFc
D
jk
RTbF
α
−
−
−
==
=
= ⋅=
=
=
⎛ ⎞= =⎜ ⎟⎝ ⎠
Reactant distribution and ( )Cj t for fixed V0 0.7E E− = .
0.000 0.002 0.0040.0000
0.0005
0.001010-1s10-3s 10-2s10-4s
c
x/cm 0.00 0.05 0.100
2
4
6
8 jt=0
j / A
cm
-2
t/s
η = 0.7 V
Consider: measurement of current-voltage relationship (potential-step experiment). How do you perform the measurement?
|E-E0|
0
t/s0
1
2
3
4
5
t3t2t1
After which time do you record the current? Assume: each point a new step from equilibrium. The measurement time is a property of the equipment (How many charges do you have to collect to reach appropriate accuracy current measurement).
Tafel-plots recorded with distinct measurement times:
0.0 0.5 1.0
-4
-2
0t = 1 st = 10-1 st = 10-2 st = 10-3 st = 10-4 s
2b
log 10
(j / A
cm-2)
|η|/V
kinetics diffusion
less sensitiveequipment
|E-E0| / V
Compare with full solution
ox ox
box ox
b s oxox ox ox
Diffusion equation:
Initial condition (t = 0): everywhere
Boundary conditi
ons:
a
nd
2
2
00
0
e: x0 : p -x
x x
c cD
t xc c
E E cc c k c D
b x=
∂ ∂=
∂ ∂=
⎛ ⎞− ∂⎜→ ∞ ⎟= =⎜
⎠=
⎟ ∂⎝
soxox
wh ere 00
0
- exp,x
E Ec kKc Kx D b
=
⎛ ⎞−∂ ⎜ ⎟⇒ = =⎜ ⎟∂ ⎝ ⎠
Solution: straightforward mathematics (use Laplace transform) can be found in H.S. Carslaw, J.C. Jaeger, Conduction
of Heat in Solids, Oxford University Press 1959.
( ) ( )
( ) ( ) ( )
( ) ( )
oxbox
oxbox
Variation of concentration with and
Concentration at x = 0
x t
erfc erfc
erfc
er
:
Current density:
fc
2
2
00* 2
,1 exp ,
4 4
0,exp
exp exp
c x t x xKx K Dt K Dtc Dt Dt
c x tK Dt K Dt
c
E Ej j K Dt K Dt
b
⎛ ⎞ ⎛ ⎞= − + + +⎜ ⎟ ⎜ ⎟
⎝ ⎠ ⎝ ⎠
==
⎛ ⎞−⎜ ⎟=⎜ ⎟⎝ ⎠
Compare the two solutions: good correspondence!
0.000 0.002 0.0040.0000
0.0005
0.001010-3s 10-1s10-2s10-4s
c / m
ol c
m-3
x / cm
Approximate solution is sufficient for a basic understanding. The semiempirical approximation works pretty well.
0.00 0.05 0.100
2
4
6
8
approximation
exact
jt=0j /
A c
m-2
t/s
Consider potential sweep experiment: 0E E At− =
0.0 0.5 1.00.00
0.05
0.10
onset ofreduction
diffusion
sweep rate
|E-E0| = 100 mV/s * t
j / A
cm-2
|E-E0| / V
How to confine concentration variations to a thin region and not let them become limiting?
Control transport: vigorous stirring (e.g. rotating disc electrode) and supporting electrolyte
⇒ good transport due to convection and migration
Control electrode geometry: microelectrodes
Diffusion Overpotential
In a voltammetric experiment, the electrode potential E is controlled with a potentiostat (chronoamperometric measurement). The current density j is determined by the following relation
C
*diff
( current through ce ) ll
E Eb
j j j jE Ej
j b
⎛ ⎞−⎜ ⎟⎜ ⎟⎝ ⎠= ≡
⎛ ⎞−⎜ ⎟+⎜ ⎟⎝ ⎠
0
0*00*
,
exp
1 exp
.
This can be easily rewritten as (j-η relation)
*diff
bj j
jj b
⎛ ⎞⎜ ⎟⎝ ⎠=
⎛ ⎞+ ⎜ ⎟
⎝ ⎠
00
exp
1 exp
η
η .
Now assume that the experiment is performed under current control (chronopotentiometric measurement).
What is the value of η corresponding to a fixed value of j ?
Solve for |η| …
*diff
j jj j b b⎛ ⎞⎛ ⎞ ⎛ ⎞
+ =⎜ ⎟⎜ ⎟ ⎜ ⎟⎜ ⎟⎝ ⎠ ⎝ ⎠⎝ ⎠
0
0 1 exp expη η
*diff
j jj j b
⎛ ⎞⎛ ⎞= − ⎜ ⎟⎜ ⎟⎝ ⎠ ⎝ ⎠
0 1 expη
Take ln on both sides and collect all j-dependent terms on right hand side:
K diff*diff
j jb bj j
⎛ ⎞⎛ ⎞= − − = +⎜ ⎟⎜ ⎟
⎝ ⎠ ⎝ ⎠0ln ln 1η η η
First term: usual Tafel-equation in absence of mass
transport limitations – reaction overpotential: Kη
Second term: overpotential due to mass transport
limitations – diffusion overpotyential: diffη
0.0 0.2 0.4 0.6 0.8 1.00.7
0.8
0.9
Ecell =1
.23
V -
|ηk|-
|ηdi
ff| / V
j / Acm-2
0.0 0.5 1.00.0
0.2
0.4
jdiff = 1.1 Acm-2
j0 = 10-7 Acm-2
diffusion, ηdiff
kinetics, ηk
over
pote
ntia
ls
j / Acm-2