Lecture 7 Setting and sedimentation: Part...
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Lecture 7
Setting and sedimentation: Part 1
A particl
dum F
dt
Where, m
velocity
accelerat
=rw2 for
force and
F
F
W
respectiv
particles
A
F
=g), (du/
method i
u
e settling in
e D bF F F
m is the m
of the par
tion force, a
settling und
d Fb is the bu
2f
D D
uF C
2
fb e
p
F m a
Where, CD i
vely. AP is p
having diam
2P
P
DA ,
4
or particles
/dt)=0. Putti
is given as:
tp D
2mgu
A C
PA
a fluid expe
mass of the
rticle in the
ae =g for Gr
der Centrifu
uoyancy forc
2
pA
is the drag
projected are
meter (DP), v
P
3Dm
6
settling with
ing the valu
P f
P f
ARTICLE S
eriences follo
particle, u
e fluid, eF
ravitational
ugal action.
ce and they a
coefficient,
ea of the pa
value of AP a
p
h terminal v
ues of differ
SETTLING
owing force
is the settli
ema is
settling and
FD is the dr
are given as:
, ρf and ρp
article and m
and m is give
velocity (ut) u
rent forces,
THEORY
balance:
ing
the
d ae
rag
:
are the de
m is the ma
en as:
under the fo
the termina
ensity of flu
ass of partic
orce of gravi
al velocity (
(3.7.1)
(3.7.2)
uid and par
cle. For sphe
(3.7.3)
itational forc
(ut) by New
(3.7.4)
rticle,
erical
ce (ae
wton’s
pP ft
f D
gDρ -ρ4u =
3 ρ C (for Spherical particle) (3.7.5)
Variation of CD (Drag-coefficient)
In laminar zone, Stoke’s law is applicable
f t PD
f
u D24C ; 0.01 Re 0 .1
Re
(3.7.6)
2p f P
tf
g( )Du
18
(3.7.7)
For transition zone, 0.1 Re 1 000
D n 0.6
a 18.5C
Re Re (3.7.8)
For turbulent zone, CD is independent of Re and CD=0.4
For non-spherical particles, formula for Reynold number and settling velocity calculation are
modified using the shape factor ( ) [1]:
f t P
f
u DRe
(3.7.9)
pP ft
f D
gDρ -ρ4u =
3 ρ C (3.7.10)
Problem 3.7.1: A sand particle has an average diameter of 1 mm and a shape factor of 0.90 and a
specific gravity of 2.1, determine the terminal velocity of the particle settling in water at 20 oC
(kinematic viscosity of water=1.003×10-6 m2/s and specific gravity=1). Drag coefficient can be
computed using the following equation:
D
24 3C 0.34
Re Re
Solution: 6f fKinematic viscosity μ 1.003 10
-6 3 -3fμ =1.003×10 ×10 =1.003×10 kg m s
Settling velocity using stokes law is:
2-32p f P
t -3f
9.81× 2.1-1 ×1000 × 1×10g( )Du 0.597 m/sec
18 18×1.003×10
3 3
f t P3
f
10 0.597 1 10u DRe 0.90 =536.32
1.003 10
Since Re>1, therefore, Newton’s law should be used for finding terminal velocity in
transition zone. For initial assumption of settling velocity, stoke’s law is used. This initially
assumed velocity is used to determine the Reynold number which is further used to find settling
velocity. This iterative procedure is repeated till initial assumed velocity is approximately equal
to settling velocity calculated from Newton’s equation.
Initial drag coefficient is calculated as:
D
24 3C 0.34=0.5142
Re Re
pP ft
f D
gDρ -ρ4u = =0.1763 m s
3 ρ C
Now, iterative procedure is continued:
ut (previous calculated) Re CD ut Difference
0.5977 536.3272 0.5143 0.1763 0.4214
0.1763 158.2037 0.7302 0.1480 0.0283
0.1480 132.7684 0.7811 0.1431 0.0049
0.1431 128.3690 0.7917 0.1421 0.0010
0.1421 127.5052 0.7939 0.1419 0.0002
0.1419 127.3315 0.7943 0.1419 0.0000
Final settling velocity=0.1419 m/s.
REFERENCES
Metcalf & Eddy, Tchobanoglous, G., Burton, F. L., Stensel, H. D. “Wastewater engineering: treatment and reuse/Metcalf & Eddy, Inc.”, Tata McGraw-Hill, 2003.