Lecture 4

34
Italian Physical Society International School of Physics “Enrico Fermi”

description

Italian Physical Society International School of Physics “Enrico Fermi”. Lecture 4. Lecture 4 Life times Regeneration Discovery of CP violation How can we measure the phase? Final state interaction phase Watson’s theorem Other possibilities Hyperon decays - PowerPoint PPT Presentation

Transcript of Lecture 4

Page 1: Lecture 4

Italian Physical Society International School of Physics

“Enrico Fermi”

Page 2: Lecture 4

Lecture 4•Life times•Regeneration•Discovery of CP violation•How can we measure the phase?•Final state interaction phase•Watson’s theorem•Other possibilities•Hyperon decays

In this section, we refrain from deriving the expression for ε and ε' etc.

Page 3: Lecture 4

C =

P =

CP| ππ >=+| ππ >

and LONG SHORTK K

CP K K

K K K

K K K

CP K K

CP K K

| |

| | |

| | |

| |

| |

112

212

1 1

2 2

K

K1

2

2

3

500

3 420Km MeV

m MeV

K K

K KS

L

1

2

Page 4: Lecture 4

0 01

2LK K K

0 0i ie K e K 0 0( ) ( )i i i iS Le e K e e K

reappears when the beam comes

out of the matterialSK

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0 0

0 0

( ) ( ) ( )

( ) ( ) ( )

K t f t g K f t g K

K t f t g K f t g K

1( ) ( )

2L LS S imt timt tf t e e

12

0 0 2 2

- ( ) *

( ( ) ) | | | |

+2e Re( )

1( )

2

L S

L S K

t t

t i M t

I K t K e g e g

e g g

g g g

Page 6: Lecture 4

3102)(

)(

S

L

K

K 3102)(

)(

S

L

K

K

Page 7: Lecture 4

A very good year 1964 (Pais)

The Higgs mechanism The quark modelThe first storage ring for e+e- collisions was built in Frascati. Ω- baryon was found at Brookhaven National Laboratory. CP violation was discovered at the same lab.

Page 8: Lecture 4

†H=ch+c*h † †CP h CP h=

† †CP H CP =ch +c*h

Page 9: Lecture 4
Page 10: Lecture 4

M M12 12

12 12

*

*

| ( ) ( )| ( )|

( )

( )

( )

( )

* *

t a t K b t K

id

dt

a t

b tHa t

b t

H Mi M M

M M

i i

i i

211 2 11 12 2 12

12 2 12 22 2 22

Within our formalism

*

| ( ) ( ) | ( ) |

( ) ( )

( ) ( )

t a t K b t K

a t a tdi H

b t b tdt

MH

M

001

002

*

| | |

| | |

K p K q K

K p K q K

qp

Page 11: Lecture 4

KL

( )

( )| |

K

KL

S

2 610

A tiny violation

00

2 0

( )( ) ( ) 1

( )

q A KA K pA K

p A K

0

0

220

2

( )1

( )

( ) ( ) 1

1 2

A KA K

qK pA K

p

qp

002| | |K p K q K

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Page 13: Lecture 4

P F1A (P F)®

2A (P F)®2 2

1 2

2 2 *1 2 1 2

A(P F) A (P F)+A (P F)

A A 2Re(A A )

® = ® ®

= + +

2 2 *1 2 1 2 1 2A A 2| A A | cos( )ff= + + -

Page 14: Lecture 4

† †CP H CP =ch +c*hRemember CP transf ormation: c c*

-ff

Þ

Þ

2 22 *1 2 1 2 1 2

2 22 *1 2 1 2 1 2

| ( )| A A 2| A A | cos( )

| ( )| A A 2| A A | cos( )

A P f

A P f

ff

ff

® = + + -

® = + + - +

Page 15: Lecture 4

1 2Note that A and A have strong phase

i i

i i

A | A |

A | A |

i i

i i

i i

i i

e e

e e

f d

f d-

=

=

Page 16: Lecture 4

P F1A (P F)®

2A (P F)®2 2

1 2

2 2 *1 2 1 2 1 1 2 2

A(P F) A (P F)+A (P F)

A A 2| A A | cos( )f d f d

® = ® ®

= + + + - -

2 2

1 2

2 2 *1 2 1 2 1 1 2 2

A(P F) A (P F)+A (P F)

A A 2| A A | cos( )f d f d

® = ® ®

= + + - + + -

Page 17: Lecture 4

( all) ( all)P P

Br(P F)-Br(P F)Br(P F)+Br(P F)

® ®® ®

1 2 1 2 1 22 2 *

1 2 1 2 1 2 1 2

Br(P F)-Br(P F) 2| A A |sin( )sin( )Br(P F)+Br(P F) A A 2| A A | cos( )cos( )

ff d d

ff d d

® ® - -=

® ® + + - -

Page 18: Lecture 4

1 2 1 2 1 22 2 *

1 2 1 2 1 2 1 2

Br(P F)-Br(P F) 2| A A |sin( )sin( )Br(P F)+Br(P F) A A 2| A A | cos( )cos( )

ff d d

ff d d

® ® - -=

® ® + + - -

Page 19: Lecture 4

K π

π

π

πWie f ie d

( ) | | W Ii ioutI IH K A e ef dpp =

† 1( ) ( ) *out outI IH K T THT T Kpp pp -=

1( ) ( ) *

= ( ) *

out inI I

inI

H K THT K

H K

pp pp

pp

-=

( ) ( ) * *out in out outI I

nH K n n H Kpp pp=å

( ) , (3 )out out outn pp p= 2 3p p®

Page 20: Lecture 4

3 3

0 0C

1

C

C

ff

p p h

= +

= + Þ = +

*1 1 1

2 2 2

3 3 3

C CC

ff f

f h f h f

ff f

æ ö æ ö æ ö÷ ÷ ÷ç ç ç÷ ÷ ÷ç ç ç÷ ÷ ÷ç ç ç÷= ÷ = ÷ç ç ç÷ ÷ ÷ç ç ç÷ ÷ ÷ç ç ç÷ ÷ ÷÷ ÷ ÷ç ç çç ç çè ø è ø è ø1 2 1 2

C i i

C

ff ff

p p±

= + ±

= + m

m

0 C

not eigenstate of C

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1 2 1 2; , , , , , , ;n mS out p p p q q q in

¶- ××× = ×××

¶××× = - - ×××- -

h 1 2 3 4 1 2 3 4

1 2 3 4 1 2 3 4

, , , , ; , , , , ;

, , , , ; , , , , ;

i T p p p p out HT p p p p outt

T p p p p out p p p p in

®±¥

é ù¶××× = ×××ê ú

ê ú¶ë ûѶ

××× =- ××× ®- ¥¶

Ѷ××× =- ××× ® +¥

å

å

h

h h

h h

1 2 3 4 1 2 3 4

22

1 2 3 4 1 2 3 4

22

1 2 3 4 1 2 3 4

lim , , , , , , , ,

, , , , ; , , , , ; 2

, , , , ; , , , , ; 2

t

i

i

i

i

i p p p p H p p p pt

i p p p p in p p p p in tt m

i p p p p out p p p p out tt m

- -¶××× = ×××

¶h 1 1

1 2 3 4 1 2 3 4, , , , ; , , , , ;Ti T T p p p p out THT T p p p p outt

Page 22: Lecture 4

( ) ( ) ( ) * ( ) *out in out outI I I IH K H Kpp pp pp pp=

2( ) ( ) ( ) Iiout inI I IS e dpp pp pp= =

isospin I phase shiftId pp=

Iie d Iie d-2 Iie d

Page 23: Lecture 4

2( ) ( ) ( ) Iiout inI I IS e dpp pp pp= =

What happens to 2 state at

500MeV?

I t can not go to 3 state,

not enough energy to go to 4 .

pp pp =( ) ( ) 1out inI I

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Page 25: Lecture 4

P

Peiδ ( )A P f

( )A P f

f

1.Mixing exists2.Common final state exists3.There is large δ

Page 26: Lecture 4

1 1 2 2

1 1 2 2

0 11 22

0 11 22

| ( ) | |

| ( ) | |

imt t imt t

imt t imt t

P t e P e P

P t e P e P

0 0 0 01

0 012

0

2

0

| ( ) ( ) | (

| ( ) ( )

| ( ) (| | ) (| |

)

| ( |

)

|

)

L L

L L L LS S S S

S S

imt t imt timt t

imt timt t

imt t

P t

P t e P P e P P

P t e e P e

f t

e

f t P P

P

Page 27: Lecture 4

Within our formalism

*

| ( ) ( ) | ( ) |

( ) ( )

( ) ( )

t a t P b t P

a t a tdi H

b t b tdt

MH

M

001

002

*

| | |

| | |

P p P q P

P p P q P

qp

0 0

0

0

2

0

0

1

| ( ) (

| ( ) ( ) | ( )

)| ( ) |

| ( ) ( )| ( ) |

|L L L LS S S Simt t imt timt t imt t

P t pf t P qf t P

P t pf t P

P t e e P e e P

qf t P

Page 28: Lecture 4

22

22

( ( ) ) ( ) ( ) ( ) ( )

( ( ) ) ( ) ( ) ( ) ( )

qP t f pA P ff t ff t

p

qP t f pA P ff t ff t

p

22

22

( ( ) ) ( ) ( ) ( ) 2Re sin ( )

( ( ) ) ( ) ( ) ( ) 2Re sin ( )

q qP t ff t ff t i Mt f

p p

q qP t ff t ff t i Mt f

p p

**12

*12

tbtd

tbtd

V Vq Mp M V V

t bd

d

B BW W

tsV

tdV

tb

tbV

tdV

Page 29: Lecture 4
Page 30: Lecture 4

NConsider (s ) N(p ,s ) NpLL ®

1/ 2 3/ 21/ 2 3/ 2

* *1/ 2 3/ 21/ 2 3/ 2

1/ 2 3/ 21/ 2 3/ 2

* *1/ 2 3/ 21/ 2 3/ 2

Using

( ) ( )

CPT

( ) ( )

S Si iS SS

P

S Si iS S

Pi iP PP

P Pi

S

iP PP

A

A A e A e

A A e A

A e A e

A A e A e

e

5

5

( , )( ) ( , )

( , )( ) ( , )

N N S P

S PN N

P H u p s A A u p s

P H v p s A A v p s

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† 1,0 ,0

,0

*

,0 ,0 ,0

( ) , ; , ( ) , ; , *

( ) , ; , *

( ) , ; ( ) , ' ; ( ) , ' ; , *

I P I P

I P

I P I P I P

P s out H s P s out T THT T s

P s in H s

P s in P s out P s out H s

p p

p

p p p

-L L

L

L

L = L

= - L -

= - L -å

T symmetry implies

,I m 0S PIA

2 SIie

1/ 21/ 2 ( , ) ( , )

SiSN NA e u p s u p s

* * *1/ 21/ 2 ( , ) ( , )

SiSN NA e u p s u p s

Page 32: Lecture 4

'2 ( )', ; , I m ( ) * ( )I IS PiI I

P S P P PP s out H s A A e s s pd dp --L L

é ùL =×××- ´ ×ê úë û

r r r

Correlation can arise not only from CP violation,but also from strong interaction

N N N N

N, N,when

p (s s ) p (s s )

p -p, s -sL L

L L

® ®

´ ® - ´r rr

r r r r

r

r rg g

Page 33: Lecture 4

arg 6.5 3.5PP P

S

AA

† 1,0 ,0

,0

*

,0 ,0 ,0

( ) , ; , ( ) , ; , *

( ) , ; , *

( ) , ; ( ) , ' ; ( ) , ' ;

, *

I P I P

I P

I P I P I P

P s out H s P s out T THT T s

P s in H s

P s in P s out P s out H s

p p

p

p p p

-L L

L

L

L = L

= - L -

= - L -

Page 34: Lecture 4

'2 ( )', ; , I m( ) * ( )I IS PiI I

P S P P PP s out H s A A e s s pd dp -+L L

é ùL =×××- ´ ×ê úë û

r r r

'2 ( )', ; , I m ( ) * ( )I IS PiI I

P S P P PP s out H s A A e s s pd dp --L L

é ùL =×××- ´ ×ê úë û

r r r