INT 506/706: Total Quality Management

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INT 506/706: Total Quality Management Lec #6, Process Capability

description

INT 506/706: Total Quality Management. Lec #6, Process Capability. Outline. Individual values vs. averages Control limits vs. Specs 6 σ spread versus specs Calculating Process Capability Indices. Process Capability. Individual vs. averages. Individual vs. averages. - PowerPoint PPT Presentation

Transcript of INT 506/706: Total Quality Management

Page 1: INT 506/706: Total Quality Management

INT 506/706: Total Quality ManagementLec #6, Process Capability

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Outline

• Individual values vs. averages• Control limits vs. Specs• 6σ spread versus specs• Calculating Process Capability Indices

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Process Capability

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Individual vs. averages

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Individual vs. averages

nX

The ability of X-bar to approximate μ is measured by the following equation:

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Individual vs. averages

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ˆor ˆdR

cs

IF the process can be assumed to be normal, the population standard deviation can be estimated from either

the sample standard deviation (s) or the range (R).

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Control limits vs Specifications

A process under control exhibits:1. 2/3 of points near center 2. Few points close to the center3. Points around centerline4. Points balanced on both sides5. No points beyond control limits6. No patterns or trends

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Control limits vs Specifications

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6σ Spread versus Specs

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ˆor ˆdR

cs

3 Possible CASES1) 6σ < USL – LSL2) 6σ = USL – LSL3) 6σ > USL - LSL

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CASE #1 6σ < USL – LSL

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CASE #2 6σ = USL – LSL

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CASE #3 6σ > USL – LSL

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Calculating 6σ

Assuming process is STABLE and IN CONTROL

1. 20 subgroups of n=42. Calculate sample std dev, si, for each sample3. Calculate average sample std dev,

4. Calculate pop std dev5. Multiply pop std dev *6

m

ss

m

ii

1

4

ˆcs

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Example

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Example

126.0)021.0(6ˆ6

021.09400.002.0ˆ

02.021414.0

21015.0...029.0031.0

4

1

cs

m

ss

m

ii

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Capability Index Cp

6Cp

LSLUSL

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Capability Index Cp

794.0126.0

95.1105.12ˆ6

Cp

LSLUSL

EXAMPLE

INTERPRETATION:Process NOT capable (case 3)

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Capability Ratio, Cr

LSLUSL

6Cr

Inverse of Cp so larger the ratio, the LESS capable the process is of meeting specifications

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Cpk

3(min)Cpk

Z

Cp and Cr do not take into account the centering of the process

ˆ)(

ˆ)(Z

LSLXLSLZ

or

XUSLUSL

Where Z(min)=

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Cpk

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Cpk

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Review

• Review pdf file in blackboard – “CapabilityCaseStudy”– Put into Minitab and run capability modules to see

what you come up with• Is it the same as the case study?• Do you understand the interpretation of the case study?