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Exact Solutions > Linear Partial Differential Equations >Second-Order Elliptic Partial Differential Equations > Helmholtz Equation
3.3. Helmholtz Equation ∆w + λw = –Φ(x)
Many problems related to steady-state oscillations (mechanical, acoustical, thermal, electromag-netic) lead to the two-dimensional Helmholtz equation. Forλ < 0, this equation describes masstransfer processes with volume chemical reactions of the first order.
The two-dimensional Helmholtz equation has the following form:
∂2w
∂x2 +∂2w
∂y2 + λw = −Φ(x,y) in the Cartesian coordinate system,
1r
∂
∂r
(r∂w
∂r
)+
1r2
∂2w
∂ϕ2 + λw = −Φ(r,ϕ) in the polar coordinate system.
3.3-1. Particular solutions of the homogeneous Helmholtz equation withΦ ≡ 0.
1. Particular solutions of the homogeneous Helmholtz equation in the Cartesian coordinate system:
w = (A cosµ1x + B sinµ1x)(C cosµ2y + D sinµ2y), λ = µ21 + µ2
2,
w = (A cosµ1x + B sinµ1x)(C coshµ2y + D sinhµ2y), λ = µ21 − µ2
2,
w = (A coshµ1x + B sinhµ1x)(C cosµ2y + D sinµ2y), λ = −µ21 + µ2
2,
w = (A coshµ1x + B sinhµ1x)(C coshµ2y + D sinhµ2y), λ = −µ21 − µ2
2,
whereA, B, C, andD are arbitrary constants.
2. Particular solutions of the homogeneous Helmholtz equation in the polar coordinate system:
w = [AJm(µr) + BYm(µr)](C cosmϕ + D sinmϕ), λ = µ2,
w = [AIm(µr) + BKm(µr)](C cosmϕ + D sinmϕ), λ = −µ2,
wherem = 1, 2, . . . ; A, B, C, D are arbitrary constants; theJm(µ) andYm(µ) are the Besselfunctions; and theIm(µ) andKm(µ) are the modified Bessel functions.
3.3-2. Domain: –∞ < x < ∞, –∞ < y < ∞.
1. Solution forλ = −s2 < 0:
w(x,y) =1
2π
∫ ∞
−∞
∫ ∞
−∞Φ(ξ,η)K0(s%) dξ dη, % =
√(x − ξ)2 + (y − η)2.
2. Solution forλ = k2 > 0:
w(x,y) = −i
4
∫ ∞
−∞
∫ ∞
−∞Φ(ξ,η)H (2)
0 (k%) dξ dη, % =√
(x − ξ)2 + (y − η)2,
whereH (2)0 (z) is the Hankel function of the second kind of order0. The radiation conditions
(Sommerfeld conditions) at infinity were used to obtain this solution.
3.3-3. Domain: –∞ < x < ∞, 0 ≤ y < ∞. First boundary value problem.
A half-plane is considered. A boundary condition is prescribed:
w = f (x) at y = 0.
1
2 HELMHOLTZ EQUATION
Solution:
w(x,y) =∫ ∞
−∞f (ξ)
[∂
∂ηG(x,y, ξ,η)
]
η=0dξ +
∫ ∞
0
∫ ∞
−∞Φ(ξ,η)G(x,y, ξ,η) dξ dη.
1. The Green’s function forλ = −s2 < 0:
G(x,y, ξ,η) =1
2π
[K0(s%1) − K0(s%2)
],
%1 =√
(x − ξ)2 + (y − η)2, %2 =√
(x − ξ)2 + (y + η)2.
2. The Green’s function forλ = k2 > 0:
G(x,y, ξ,η) = −i
4[H (2)
0 (k%1) − H (2)0 (k%2)
].
3.3-4. Domain: 0≤ x ≤ a, 0 ≤ y ≤ b. First boundary value problem.
A rectangle is considered. Boundary conditions are prescribed:
w = f1(y) at x = 0, w = f2(y) at x = a,
w = f3(x) at y = 0, w = f4(x) at y = b.
1. Eigenvalues of the homogeneous problem withΦ ≡ 0 (it is convenient to label them with adouble subscript):
λnm = π2(
n2
a2 +m2
b2
); n = 1, 2, . . . ; m = 1, 2, . . .
Eigenfunctions and the norm squared:
wnm = sin
(nπx
a
)sin
(mπy
b
), ‖wnm‖2 =
ab
4.
2. Solution forλ ≠ λnm:
w(x,y) =∫ a
0
∫ b
0Φ(ξ,η)G(x,y, ξ,η) dη dξ
+∫ b
0f1(η)
[∂
∂ξG(x,y, ξ,η)
]
ξ=0dη −
∫ b
0f2(η)
[∂
∂ξG(x,y, ξ,η)
]
ξ=a
dη
+∫ a
0f3(ξ)
[∂
∂ηG(x,y, ξ,η)
]
η=0dξ −
∫ a
0f4(ξ)
[∂
∂ηG(x,y, ξ,η)
]
η=b
dξ.
Two forms of representation of the Green’s function:
G(x,y, ξ,η) =2a
∞∑
n=1
sin(pnx) sin(pnξ)βn sinh(βnb)
Hn(y,η) =2b
∞∑
m=1
sin(qmy) sin(qmη)µm sinh(µma)
Qm(x, ξ),
where
pn =πn
a, βn =
√p2
n − λ, Hn(y,η) =
sinh(βnη) sinh[βn(b − y)] for b ≥ y > η ≥ 0,
sinh(βny) sinh[βn(b − η)] for b ≥ η > y ≥ 0,
qm =πm
b, µm =
√q2m − λ, Qm(x, ξ) =
sinh(µmξ) sinh[µm(a − x)] for a ≥ x > ξ ≥ 0,
sinh(µmx) sinh[µm(a − ξ)] for a ≥ ξ > x ≥ 0.
ReferencesBudak, B. M., Samarskii, A. A., and Tikhonov, A. N., Collection of Problems on Mathematical Physics[in Russian],
Nauka, Moscow, 1980.Tikhonov, A. N. and Samarskii, A. A., Equations of Mathematical Physics, Dover Publ., New York, 1990.Polyanin, A. D., Handbook of Linear Partial Differential Equations for Engineers and Scientists, Chapman & Hall/CRC,
2002.
Helmholtz Equation
Copyright c© 2004 Andrei D. Polyanin http://eqworld.ipmnet.ru/en/solutions/lpde/lpde303.pdf