Flux = = B • A = BA cos
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Flux = = B•A = BA cos Area vector = A is constructed normal to surface with a length = to its area π r 2 . B A B
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Flux = = B • A = BA cos . Area vector = A is constructed normal to surface with a length = to its area π r 2. A. B. B. Flux = = B • A = BA cos . Area vector = A is constructed normal to surface with a length = to its area π r 2. A. B. B. Flux = = B • A = BA cos . - PowerPoint PPT Presentation
Transcript of Flux = = B • A = BA cos
Flux = = B•A = BA cosArea vector = A is constructed normal to
surface with a length = to its area π r2.
B
A
B
Flux = = B•A = BA cosArea vector = A is constructed normal to
surface with a length = to its area π r2.
B
A
B
Flux = = B•A = BA cosArea vector = A is constructed normal to
surface with a length = to its area π r2.
B
A
B
B
The AP B Ref Table writes
A loop of wire having an area of 0.25 m2 contains a magnetic field intensity of 16 Teslas as shown. Find the magnetic flux through the loop.
B
The AP B Ref Table writes
A loop of wire having an area of 0.25 m2 has 8 Webers of magnetic flux passing through the loop. Find then strength of the magnetic field inside the loop.
B
The E&M C Ref Tables write……..
A loop of wire having an area of 0.25 m2 has 8 Webers of magnetic flux passing through the loop. Find then strength of the magnetic field inside the loop.
B
The AP B Ref Table writes
A loop of wire having an area of 0.25 m2 has 8 Webers of magnetic flux passing through the loop. If the field collapsed in 4 seconds…….. a) find the EMF the loop would generate.
b) tell which way current would flowto resist the change.
c) What if there were 3 loops?
n
And E&M C says….
Two AP B formulas for induced E
EMF induced by the rate of change in magnetic flux
EMF induced by the speed you move a wire through a
constant B field
Example problem: A 50 cm rod of resistance 2 ohms is moved across a 4 Tesla magnetic field at 2 m/s. Calculate…..
a)…the EMF generated.
b) …the current generated.
The direction of I is defined by the cross
product E = l v x B
The B Ref Table says• Force on a charge moving
through a B field (q v x B)• Force on a wire carrying
current through a B field
(i l x B)The C Ref Table
says
• Force on a charge moving through a B field (q v x B)
• Force on a wire carrying current through a B field
(l i x B)
Find the direction and magnitude of the force on a 20 cm wire that carries 3 Amperes across
a 4 Tesla field.
B Ref Table says
• As you get farther away from the wire its field gets…..
weaker
Find the strength of a magnetic field 2 mm away from a wire carrying 10 amperes of current.
C Ref Table says
and call it Ampere’s Law
