Chapter8 InhomogeneousSolutions -...

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Chapter 8 Inhomogeneous Solutions We have shown that, in vacuum,Maxwell’s equations reduce to the wave equation 2 E =μ o ε o 2 E ∂t 2 (8.1) which needs to be solved subject to ∇· E = 0 (8.2) Such a solution is E = E o cos(k · r - ωt) (8.3) where E o · k =0; substitution into the wave equation gives -k 2 E = -μ o ε o ω 2 E (8.4) or k 2 = μ o ε o ω 2 (8.5) which determines the magnitude of k (that is, the wavelength, since k = 2π/λ). This is called the ’dispersion relation’, relating the wave vector to the frequecy. From this, we can get the velocity; v = k ω = 1 ε o μ o = c (8.6) Once E is known, the other fields can be easily obtained. For example, ∇× E = - B ∂t (8.7) 43

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Page 1: Chapter8 InhomogeneousSolutions - mpalffy.lci.kent.edumpalffy.lci.kent.edu/Optics/Chapters/Ch8_Inhomogeneous Solutions.pdf · Chapter8 InhomogeneousSolutions We have shown that, in

Chapter 8

Inhomogeneous Solutions

We have shown that, in vacuum,Maxwell’s equations reduce to the wave

equation

∇2E =µoεo∂2E

∂t2(8.1)

which needs to be solved subject to

∇ · E = 0 (8.2)

Such a solution isE = Eo cos(k · r− ωt) (8.3)

where Eo · k = 0; substitution into the wave equation gives

−k2E = −µoεoω2E (8.4)

ork2 = µoεoω

2 (8.5)

which determines the magnitude of k (that is, the wavelength, since k =2π/λ). This is called the ’dispersion relation’, relating the wave vector to thefrequecy. From this, we can get the velocity;

v =k

ω=

1√εoµo

= c (8.6)

Once E is known, the other fields can be easily obtained. For example,

∇× E = −∂B∂t

(8.7)

43

Page 2: Chapter8 InhomogeneousSolutions - mpalffy.lci.kent.edumpalffy.lci.kent.edu/Optics/Chapters/Ch8_Inhomogeneous Solutions.pdf · Chapter8 InhomogeneousSolutions We have shown that, in

44 CHAPTER 8. INHOMOGENEOUS SOLUTIONS

gives

−k× Eo sin(k · r− ωt)= −µo

∂H

∂t(8.8)

or

H =1

Zok̂×E (8.9)

If we choose the z-axis to be along k and the x-axis along Eo, the solutionbecomes

E =Eox̂ cos(kz − ωt) (8.10)

withk2 = µoεoω

2 (8.11)

and

v =k

ω=

1√εoµo

= c (8.12)

In addition to this simple plane wave solution, consider a solution of theform

E =Eoe−αyx̂ cos(kz − ωt) (8.13)

then

∇2E =µoεoω2∂

2E

∂t2(8.14)

gives(α2 − k2)E = −µoεoω

2E (8.15)

ork2 − α2 = µoεoω

2 (8.16)

Now we see that, for a given frequency, a range of k values are allowed (anddifferent wavelengths can occur) depending on α. These solutions, whichvary exponentially in the direction perpendicular to k, are called inhomo-geneous solutions. Note that, if α �= 0, the wavelength is shorter than in aplane wave (α = 0) at the same frequency. These solutions occur in nature,they are usually called ’evanescent waves’, and we will encounter them againwhen we discuss total internal reflection.