ACOUSTIC RESONATORS, WAVEGUIDES, AND...

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ACOUSTIC RESONATORS, WAVEGUIDES, AND ANTENNAS TEM Resonances: TEM 0 TEM 1 TEM 2 TEM 3 Current I(z,t): Voltage V(z,t): 0 0 0 TEM Resonators: ω o = 2πf o = 2πc/λ o λ o = 2d u (z,t) I(z,t): p(z,t) V(z,t): ω o = πc/d ω o = πc/d ω o = πc/2d 0 0 0 Acoustic Resonators: A 001 A 001 A 001 Boundary Conditions: u = 0 at closed end (of course); p 0 p 0 at open end (abrupt opening for narrow pipe reduces p) L21-1

Transcript of ACOUSTIC RESONATORS, WAVEGUIDES, AND...

  • ACOUSTIC RESONATORS, WAVEGUIDES, AND ANTENNAS

    TEM Resonances: TEM0 TEM1 TEM2 TEM3

    Current I(z,t): Voltage V(z,t): 0 0 0

    TEM Resonators:

    ωo = 2πfo = 2πc/λo λo = 2d

    u(z,t) I(z,t): p(z,t) V(z,t):

    ωo = πc/d ωo = πc/d ωo = πc/2d

    0 0 0 Acoustic Resonators:

    A001 A001 A001 Boundary Conditions:

    u = 0 at closed end (of course); p ≠ 0

    p ≅ 0 at open end (abrupt opening for narrow pipe reduces p)

    L21-1

  • HUMAN ACOUSTIC RESONATORS

    Human Vocal Tract:

    f1 = cs/λ1 = cs/4d = 340/(4 × 0.16) = 531 Hz

    Second Resonance: f2 = 1594 Hz

    Third Resonance:

    f3 = 2655 Hz

    0 z

    vocal chords

    z say ~16 cm 0

    0 z

    p(z,t) u(z,t)

    p(z,t) u(z,t)

    p(z,t) u(z,t)

    L21-2

  • L21-3

    ACOUSTIC WAVEGUIDESAcoustic Waveguides—Parallel Plate:

    Acoustic Waveguides—Rectangular Waveguide:

    Power

    x

    b

    y z

    λz

    u

    (

    (( −

    λ= πλ

    =∇ + =

    = ω = π λ + λ

    x

    x

    o2

    2 2 2 2 2 2 2s z x z

    n bkp p

    k p 0k k k 4

    -jk x- jk zxe

    ((

    y

    x

    o2 2 2 2

    s y z

    m an bp pk c k

    λλ

    == ω = + +

    -jk x- jk y - jk zx ze b

    a

    y

    x

    z

    )

    ))−

    =

    =+

    x

    2

    2x

    22

    c

    z

    ))

    22x

    22

    kk

    ==

    y

  • L21-4

    ACOUSTIC RESONATORSAmnp Resonances of a Box:

    Resonant Frequencies of the Amnp Mode in a Box:

    m(ly/2) = an(lx/2) = bp(lz/2) = d

    (

    (

    2

    jk x jk y jk zx zo

    2 2 2 2 2 2 2 2 2s y z x y z

    k p 0e.g., p ek k k k 4

    − −

    − −

    ∇ + ==

    = ω = + + = π λ + λ + λ

    fmnp2 = cs2(λx-2 + λy-2 + λz-2)fmnp = cs(m2a-2 + n2b-2 + p2d-2)0.5/2 [Hz]f000 = 0 Hz (constant pressure)f001 = 340/2d ⇒ 170 Hz for a one-meter closed pipe

    d

    λz

    u z

    x

    b

    y)

    )

    2

    y

    2x

    pc

  • L21-5

    MORE ACOUSTIC RESONATORSModal Density in Rectangular Resonators:

    Example:

    Recall: fmnp = cs(m2a-2 + n2b-2 + p2d-2)0.5/2 ]

    Each cube has volume = cs3/8Vwhere V = abd (volume of resonator)

    Number of modes in ∆f ≅(Volume of shell)/(vol. of cell) ≅4πf2 ∆f/[8(cs3/8V)] ≅

    4πf2V ∆f/cs3 modes in ∆f

    Bathroom 3×3×3 meters ⇒ lowest f100 =cs/2a ≅ 340/6 ≅ 57 Hz Modal density at 1 kHz ≅ 4π × 10002 × 33 × 1/3403 ≅ 9 modes/HzHow can we select just one when we sing (a single note)?

    ncs/2b

    pcs/2d

    mcs/2a

    ∆f

    fmnpp=2

    m=2 3

    [Hz

  • EXCITATION OF TEM RESONATORS

    Emission from TEM Resonators:

    z

    Zo,c

    I(t) Vo V(z,t)

    Zo,c

    d δ

    V(z,t) = Vo cos(ωot) sin(πz/d)

    Escaping wave: Ve = [sin(πδ/d)Vo] cos(ωot – kz)

    (If escaping to a matched load)

    Excitation of TEM Resonators:

    If an external source provides I(t) = Io cos ωot to the terminals where V(z,t) = Vo cos(ωot ) sin(πδ/d), then the power input Pi(t) = v(t)i(t) to the resonator is:

    Pi(t) ≅ IoVo cos2(ωot) sin(πδ/d) [W]

    Note: Resonator impedance

  • EXCITATION OF ACOUSTIC RESONATORS Acoustic Intensity I [Wm-2]:

    [I Wm−2 ] = pu • n̂

    Excitation of TEM Resonators:

    Pk(t) = v(t) i(t) = power into the resonator

    = 0 if vk or ik = 0

    Excitation of Acoustic Resonators:

    For the same reasons we cannot excite acoustic modes:

    with velocity sources at pressure nulls (pk = 0), or with pressure sources at velocity nulls (vk = 0)

    Loudspeakers are roughly velocity sources, so put them at pressure maxima of modes (e.g. corners are pressure maxima for all modes)

    Bathroom Opera:

    Mouth is approximately a velocity source, so place it near pressure maximum of desired mode, with u in right direction.

    L21-7

  • ACOUSTIC ANTENNAS

    Monopole Radiators:

    Wave equation: (∇ 2 + k2)p = 0 where k = ω/cs Spherically (radially) vibrating sound source: ∂/∂θ = ∂/∂φ = 0

    Yields: d2p/dr2 + (2/r)dp/dr + k2p = 0 Equivalent to: d2(rp)/dr2 + k2(rp) = 0

    General solution: rp ∝ e±jkr

    Radiation outward: p(r) = (A/r)e-jkr

    Velocity field u: u(r) = -∇p/j ωρo = (A/ηsr)(1 + [jkr]-1)e-jkr

    kr 2 r= π λ >> 1 if r 2>> λ π

    j(Recall ∇ p = − ωρou(r), u j p ∇ • = − ω γpo ) ∇ = r̂

    ∂ + θ̂1 ∂ + φ̂ 1 ∂ ∂r r ∂θ r sin θ ∂φ L21-8

  • λλλ πππ

    ACOUSTIC ANTENNAS (2)

    Monopole Radiators:

    Radiation outward: p(r) = (A/r)e-jkr

    Velocity field u: u(r) = -∇p/j ωρo = (A/ηsr)(1 + [jkr]-1)e-jkr

    Far-Field—Spherical Waves Become Plane Waves (r>>λ/2π):

    p(r) = (A/r)e-jkr u(r) = (A/rηs)e-jkr = p(r)/ηs

    Near-Field Radiation—Velocity Boosted and Reactive:

    p(r) = (A/r)e-jkr u(r) = (-jA/r2kηs)e-jkr = -jp(r)/ρoωr

    Therefore a velocity microphone held close to the lips (the monopole radiator) will boost low frequencies and need compensation.

    (Recall ηs = ρocs = ρoω/k) L21-9

  • L21-10

    ACOUSTIC ANTENNAS (3)Antenna Gain G(θθθθ,φφφφ) and Effective Area A(θθθθ,φφφφ) [m2]:

    Antenna (Loudspeaker, Microphone) Configurations:

    G(θ,φ) = Pr(θ,φ)/[PT/4πr2]Preceived = I(θ,φ) A(θ,φ) [W]

    MonopoleBaffled monopoleDipoleArray (end-fire or broadside)LenseHornParabolic dish

    - + ⇒

    θnullλ/2