A bandlimited signal can be reconstructed exactly if it is ...€¦ · Sampling Theorem and its...

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Page 1: A bandlimited signal can be reconstructed exactly if it is ...€¦ · Sampling Theorem and its Importance Sampling Theorem: \A bandlimited signal can be reconstructed exactly if

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Sampling Theorem and its Importance

• Sampling Theorem:

“A bandlimited signal can be reconstructed exactly if it is

sampled at a rate atleast twice the maximum frequency

component in it.”

Figure 1 shows a signal g(t) that is bandlimited.

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0

G( )ω

ω −ω ω m m

Figure 1: Spectrum of bandlimited signal g(t)

• The maximum frequency component of g(t) is fm. To recover

the signal g(t) exactly from its samples it has to be sampled at

a rate fs ≥ 2fm.

• The minimum required sampling rate fs = 2fm is called

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Nyquist rate.

Proof: Let g(t) be a bandlimited signal whose bandwidth is fm

(ωm = 2πfm).

g(t) G( )

0

(a) (b)

− m m

ω

ω ω

Figure 2: (a) Original signal g(t) (b) Spectrum G(ω)

δT (t) is the sampling signal with fs = 1/T > 2fm.

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tδ( )

T

(a)

s

δ(ω)

(b)

ω

Figure 3: (a) sampling signal δT (t) (b) Spectrum δT (ω)

• Let gs(t) be the sampled signal. Its Fourier Transform Gs(ω) is

given by

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F(gs(t)) = F [g(t)δT (t)]

= F

[

g(t)

+∞∑

n=−∞

δ(t − nT )

]

=1

[

G(ω) ∗ ω0

+∞∑

n=−∞

δ(ω − nω0)

]

Gs(ω) =1

T

+∞∑

n=−∞

G(ω) ∗ δ(ω − nω0)

Gs(ω) = F [g(t) + 2g(t) cos(ω0t) + 2g(t) cos(2ω0t) + · · · ]

Gs(ω) =1

T

+∞∑

n=−∞

G(ω − nω0)

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g (t)G ( )ω

ss

0 ωω ω ωs sm m−−

Figure 4: (a) sampled signal gs(t) (b) Spectrum Gs(ω)

• If ωs = 2ωm, i.e., T = 1/2fm. Therefore, Gs(ω) is given by

Gs(ω) = 1

T

+∞∑

n=−∞

G(ω − nωm)

• To recover the original signal G(ω):

1. Filter with a Gate function, H2ωm(ω) of width 2ωm.

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2. Scale it by T .

G(ω) = TGs(ω)H2ωm(ω).

0ω ωm m−

2ωm ωH ( )

Figure 5: Recovery of signal by filtering with a filter of width 2ωm

• Aliasing

– Aliasing is a phenomenon where the high frequency

components of the sampled signal interfere with each other

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because of inadequate sampling ωs < 2ωm.

ωω ω ωmms s

− − 0

Interference of high frequency components

Figure 6: Aliasing due to inadequate sampling

Aliasing leads to distortion in recovered signal. This is the

reason why sampling frequency should be atleast twice the

bandwidth of the signal.

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• Oversampling

– In practice signal are oversampled, where fs is significantly

higher than Nyquist rate to avoid aliasing.

0 ωω ω ω mms s−−

Figure 7: Oversampled signal-avoids aliasing

Problem: Define the frequency domain equivalent of the Sampling

Theorem and prove it.