10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the...

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10 Solve the equation (i) lg(2x) – lg(x – 3) = 1, [3] (ii) log 3 y + 4log y 3 = 4. [4] 9 Solve (i) log 4 2 ! log 9 (2x ! 5) # log 8 64, [4] (ii) 9 y ! 5(3 y 0 10) # 0. [4] 8 Solve (i) log 3 (2x ! 1) # 2 ! log 3 (3x 0 11), [4] (ii) log 4 y ! log 2 y # 9. [4] 7 (a) Variables l and t are related by the equation l = l 0 (1 + α) t where l 0 and α are constants. Given that l 0 = 0.64 and α = 2.5 × 10 –3 , find the value of t for which l = 0.66. [3] (b) Solve the equation 1 + lg (8 – x) = lg (3x + 2). [4] 9 (a) Given that u = log 4 x, find, in simplest form in terms of u, (i) x, (ii) log 4 , (iii) log x 8. [5] (b) Solve the equation (log 3 y) 2 + log 3 ( y 2 ) = 8. [4] 16 –– x 5 (i) Express 32 as a power of 2. [1] (ii) Express ( ) 64 1 x as a power of 2. [1] (iii) Hence solve the equation ( ) 64 2 1 32 1 x x = . [3] 8 (i) Given that log 9 x = a log 3 x, find a. [1] (ii) Given that log 27 y = b log 3 y, find b. [1] (iii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4]

Transcript of 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the...

Page 1: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve

10 Solve the equation

(i) lg(2x) – lg(x – 3) = 1, [3]

(ii) log3 y + 4logy 3 = 4. [4]

9 Solve

(i) log�4 2 ! log�9 (2x ! 5) # log�8 64, [4]

(ii) 9�y ! 5(3�y 0 10) # 0. [4]

8 Solve

(i) log�3(2x ! 1) # 2 ! log�3(3x 0 11), [4]

(ii) log�4 y ! log�2 y # 9. [4]

7 (a) Variables l and t are related by the equation l = l0(1 + α)t where l0 and α are constants.

Given that l0 = 0.64 and α = 2.5 × 10–3, find the value of t for which l = 0.66. [3]

(b) Solve the equation 1 + lg(8 – x) = lg(3x + 2). [4]

9 (a) Given that u = log4 x, find, in simplest form in terms of u,

(i) x,

(ii) log4� �,(iii) logx 8.

[5]

(b) Solve the equation (log3 y)2 + log3(y2) = 8. [4]

16––x

5 (i) Express 32

as a power of 2. [1]

(ii) Express ( )641x as a power of 2. [1]

(iii) Hence solve the equation ( )64

2

132

1x

x = . [3]

8 (i) Given that log9 x = a log3 x, find a. [1]

(ii) Given that log27 y = b log3 y, find b. [1]

(iii) Hence solve, for x and y, the simultaneous equations

6log9 x + 3 log27 y = 8,

log3 x + 2 log9 y = 2. [4]

Page 2: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve

8 Solve the equation

(i) 22x + 1 = 20, [3]

(ii) 5

25

125

25

4 1 3

2

y

y

y

y

− +

−= . [4]

5 (a) Solve the equation 92x – 1 = 27x. [3]

(b) Given that

a b– 12

23

a b3 – 23

= a pbq, find the value of p and of q. [2]

10 (a) Given that logp X = 6 and logp Y = 4, find the value of

(i) logp � X2–––Y �, [2]

(ii) logY X. [2]

(b) Find the value of 2z, where z = 5 + log23. [3]

(c) Express 512 as a power of 4. [2]

Page 3: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve

7 Given that logp X = 9 and logpY = 6, find

(i) logp X , [1]

(ii) logp ( 1X ) , [1]

(iii) logp (XY ), [2]

(iv) logY X. [2]

6 Given that log8 p = x and log8 q = y, express in terms of x and/or y

(i) log8 p + log8 q2, [2]

(ii) log8 �q–8�, [2]

(iii) log2 (64p). [3]

8 (a) Solve the equation (23 – 4x) (4x + 4) = 2. [3]

(b) (i) Simplify 108 – 12–– 3

, giving your answer in the form k 3 , where k is an integer. [2]

(ii) Simplify 5 + 3––––– 5 – 2

, giving your answer in the form a 5 + b, where a and b are integers. [3]

Page 4: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 5: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 6: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 7: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 8: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 9: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 10: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 11: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve
Page 12: 10 (i) x –3)=1, [3] - WELCOME IGCSE | Dr. Tayeb's Websiteiii) Hence solve, for x and y, the simultaneous equations 6log 9 x + 3 log 27 y = 8, log 3 x + 2 log 9 y = 2. [4] 8 Solve

0606/1/M/J/02

where n is a positive integer and = .n!(n – r)!r!)r(