ZAPATA "Z7" ENTRE EJES C-C Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 55 cm γ t1 45.00 cm
t = 65 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 33.58 6.45 40.03Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 1.6 0.43 2.03γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 40.03 TnPu (envol) = 58.09 Tn
Ms = 2.03 Tn - mMu (envol)= 10.43 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 218.28 cm
T ' = Az^.5 + ( t - b ) S ' = 208.28 cm
2 e = 5.07 cm
S ' = Az^.5 - ( t - b )2 S = 218.42 cm
e = Ms Tomar S = 220.00 cm
PsS = S' + 2*e Lvb = 82.5 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 87.5 cm ser iguales (Lvb=Lvt)
2 Reales T = 230.00 cm
T = 2*m + t Tomar T = 240.00 cm
USAR S x T = 220X240 cm²
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
45488.64
60.00 cm
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
DATOS DEL SAP2000
hc =
h t1 =
h t2 =
DATOS DEL SAP2000
b
t
ZAPATA "Z7" ENTRE EJES C-C Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 40 cm > e =
q 1 = 0.85 kg/cm² = qm =q 2 = 0.66 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 17.95 cm
Pu T / 6 = 40.00 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 1.59 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 82.50 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
11049.31 kg OK !!
1.590.06
11049.31
86026.5773122.58
OK !!
0.88 kg/cm² OK !!
17.95 cm
5.07 cm
0.88 kg/cm²
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z7" ENTRE EJES C-C Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 40030 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 115.91 cm
n = 105.91 cm
Vu = kg
β c = 1.18bo = 443.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
1.597.50
20.16
As mín As req = As mín !!
1.98
20.16
0.7348
1190413.13220.0050.91
10.1825
kg OK !!
82.501190413.13
6.87
38570.23
477889.42406206.01 38570.23
ZAPATA "Z7" ENTRE EJES C-C Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 11 Ø 5/8" @ 20 cm
Dirección Menor:
As tranv = As * T As trv. = 23.75 cm²
S USAR As trv. = 23.75As mín = 0.0018 * S * d As mín = 20.16 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 12 Ø 5/8" @ 20 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm < 75.00 cm OK !!
1.277.50
12.43
Lv1 =
1.000.801.008.500.00
7.50
1212
20.31
1.00
cm²
As mín OK !!
1.981.59
10.1911
20.34
ZAPATA "Z2" ENTRE EJES A-A Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 55 cm γ t1 45.00 cm
t = 65 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 42.8 10.65 53.45Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 0.89 0.67 1.56γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 53.45 TnPu (envol) = 78.02 Tn
Ms = 1.56 Tn - mMu (envol)= 10.69 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 251.45 cm
T ' = Az^.5 + ( t - b ) S ' = 241.45 cm
2 e = 2.92 cm
S ' = Az^.5 - ( t - b )2 S = 247.29 cm
e = Ms Tomar S = 250.00 cm
PsS = S' + 2*e Lvb = 97.5 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 100 cm ser iguales (Lvb=Lvt)
2 Reales T = 260.00 cm
T = 2*m + t Tomar T = 265.00 cm
USAR S x T = 250X265 cm²
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
h t1 =
DATOS DEL SAP2000h t2 =
hc = 60.00 cm
DATOS DEL SAP2000
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
60738.64
b
t
ZAPATA "Z2" ENTRE EJES A-A Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 44.17 cm > e =
q 1 = 0.86 kg/cm² = qm =q 2 = 0.75 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 13.70 cm
Pu T / 6 = 44.17 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 1.54 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 97.50 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
OK !!
2.92 cm
0.88 kg/cm²
OK !!
13.70 cm
0.08
17936.19
1.54
0.88 kg/cm²
97757.4783093.85 17936.19 OK !!kg
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z2" ENTRE EJES A-A Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 53450 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 115.91 cm
n = 105.91 cm
Vu = kg
β c = 1.18bo = 443.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
1829953.13
406206.01 59114.06 kg OK !!
97.50
59114.06
477889.42
1829953.13250.0050.91
10.182510.57
22.91
22.91
As mín As req = As mín !!
1.98
0.9948
1.597.50
ZAPATA "Z2" ENTRE EJES A-A Y 4-4,5-5,6-6,7-7 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 12 Ø 5/8" @ 21 cm
Dirección Menor:
As tranv = As * T As trv. = 25.18 cm²
S USAR As trv. = 25.18As mín = 0.0018 * S * d As mín = 22.91 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 13 Ø 5/8" @ 20 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm <
cm²
11.5712
21.22
1.00
As mín OK !!
1.981.597.50
12.7213
20.7
1.001.000.80
8.500.001.277.50
12.43
90.00 cm OK !!Lv1 =
ZAPATA "Z1" ENTRE EJES C-C Y 3-3, C-C Y 8-8 (PAB. ADMINIST.)
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 55 cm γ t1 45.00 cm
t = 60 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 12.74 0.92 13.66Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 0.16 0.08 0.24γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 13.66 TnPu (envol) = 22.30 Tn
Ms = 0.24 Tn - mMu (envol)= 1.50 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 127.09 cm
T ' = Az^.5 + ( t - b ) S ' = 122.09 cm
2 e = 1.76 cm
S ' = Az^.5 - ( t - b )2 S = 125.61 cm
e = Ms Tomar S = 210.00 cm
PsS = S' + 2*e Lvb = 77.5 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 77.5 cm ser iguales (Lvb=Lvt)
2 Reales T = 215.00 cm
T = 2*m + t Tomar T = 215.00 cm
USAR S x T = 210X215 cm²
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
h t1 =
DATOS DEL SAP2000h t2 =
hc = 60.00 cm
DATOS DEL SAP2000
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
15522.73
b
t
ZAPATA "Z1" ENTRE EJES C-C Y 3-3, C-C Y 8-8 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 35.83 cm > e =
q 1 = 0.32 kg/cm² = qm =q 2 = 0.29 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 6.73 cm
Pu T / 6 = 35.83 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 0.59 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 77.50 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
OK !!
1.76 cm
0.88 kg/cm²
OK !!
6.73 cm
0.04
3294.19
0.59
0.88 kg/cm²
82116.2769798.83 3294.19 OK !!kg
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z1" ENTRE EJES C-C Y 3-3, C-C Y 8-8 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 13660 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 110.91 cm
n = 105.91 cm
Vu = kg
β c = 1.09bo = 433.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
372087.19
416086.65 15369.26 kg OK !!
77.50
15369.26
489513.7
372087.19210.0050.91
10.18252.15
19.24
19.24
As mín As req = As mín !!
1.98
0.2409
1.597.50
ZAPATA "Z1" ENTRE EJES C-C Y 3-3, C-C Y 8-8 (PAB. ADMINIST.)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 10 Ø 5/8" @ 20 cm
Dirección Menor:
As tranv = As * T As trv. = 20.26 cm²
S USAR As trv. = 20.26As mín = 0.0018 * S * d As mín = 19.24 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 11 Ø 5/8" @ 19 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm <
cm²
9.7210
21.49
1.00
As mín OK !!
1.981.597.50
10.2411
19.84
1.001.000.80
8.500.001.277.50
12.43
70.00 cm OK !!Lv1 =
ZAPATA "Z5" ENTRE EJES B1 Y 3-3,6-6,8-8 (AULAS)
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 25 cm γ t1 45.00 cm
t = 25 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 9.52 2.09 11.61Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 0.07 0.03 0.1γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 11.61 TnPu (envol) = 16.89 Tn
Ms = 0.10 Tn - mMu (envol)= 0.29 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 114.86 cm
T ' = Az^.5 + ( t - b ) S ' = 114.86 cm
2 e = 0.86 cm
S ' = Az^.5 - ( t - b )2 S = 116.58 cm
e = Ms Tomar S = 145.00 cm
PsS = S' + 2*e Lvb = 60 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 60 cm ser iguales (Lvb=Lvt)
2 Reales T = 145.00 cm
T = 2*m + t Tomar T = 145.00 cm
USAR S x T = 145X145 cm²
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
h t1 =
DATOS DEL SAP2000h t2 =
hc = 60.00 cm
DATOS DEL SAP2000
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
13193.18
b
t
ZAPATA "Z5" ENTRE EJES B1 Y 3-3,6-6,8-8 (AULAS)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 24.17 cm > e =
q 1 = 0.57 kg/cm² = qm =q 2 = 0.53 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 1.72 cm
Pu T / 6 = 24.17 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 0.86 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 60.00 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
OK !!
0.86 cm
0.88 kg/cm²
OK !!
1.72 cm
0.07
1133.21
0.86
0.88 kg/cm²
56699.3348194.43 1133.21 OK !!kg
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z5" ENTRE EJES B1 Y 3-3,6-6,8-8 (AULAS)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 11610 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 75.91 cm
n = 75.91 cm
Vu = kg
β c = 1bo = 303.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
224460
308490.14 11934.07 kg OK !!
60.00
11934.07
362929.58
224460145.0050.91
10.18251.3
13.29
13.29
As mín As req = As mín !!
1.98
0.211
1.597.50
ZAPATA "Z5" ENTRE EJES B1 Y 3-3,6-6,8-8 (AULAS)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 7 Ø 5/8" @ 21 cm
Dirección Menor:
As tranv = As * T As trv. = 13.86 cm²
S USAR As trv. = 13.86As mín = 0.0018 * S * d As mín = 13.29 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 7 Ø 5/8" @ 21 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm <
cm²
6.717
21.4
1.00
As mín OK !!
1.981.597.50
77
21.4
1.001.000.80
8.500.001.277.50
12.43
52.50 cm OK !!Lv1 =
ZAPATA "Z3" ENTRE EJES A-A Y 2-2 (ENTRE PAB ADM. Y CAJA DE ESCALERAS)
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 50 cm γ t1 45.00 cm
t = 90 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 44.56 8.75 53.31Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 1.5 1.5 3γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 53.31 TnPu (envol) = 131.28 Tn
Ms = 3.00 Tn - mMu (envol)= 19.74 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 266.13 cm
T ' = Az^.5 + ( t - b ) S ' = 226.13 cm
2 e = 5.63 cm
S ' = Az^.5 - ( t - b )2 S = 237.39 cm
e = Ms Tomar S = 245.00 cm
PsS = S' + 2*e Lvb = 97.5 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 97.5 cm ser iguales (Lvb=Lvt)
2 Reales T = 285.00 cm
T = 2*m + t Tomar T = 285.00 cm
USAR S x T = 245X285 cm²
hc = 60.00 cm
DATOS DEL SAP2000
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
60579.55
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
h t1 =
DATOS DEL SAP2000h t2 =
b
t
ZAPATA "Z3" ENTRE EJES A-A Y 2-2 (ENTRE PAB ADM. Y CAJA DE ESCALERAS)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 47.5 cm > e =
q 1 = 0.85 kg/cm² = qm =q 2 = 0.67 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 15.04 cm
Pu T / 6 = 47.50 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 2.48 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 97.50 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
95802.3281431.97 28306.57 OK !!kg
OK !!
15.04 cm
0.13
28306.57
2.48
0.88 kg/cm²
OK !!
5.63 cm
0.88 kg/cm²
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z3" ENTRE EJES A-A Y 2-2 (ENTRE PAB ADM. Y CAJA DE ESCALERAS)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 53310 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 140.91 cm
n = 100.91 cm
Vu = kg
β c = 1.8bo = 483.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
22.45
22.45
As mín As req = As mín !!
1.98
1.601
1.597.50
2887998.75245.0050.91
10.182516.67
96014.82
406789.86
2887998.75
345771.38 96014.82 kg OK !!
97.50
ZAPATA "Z3" ENTRE EJES A-A Y 2-2 (ENTRE PAB ADM. Y CAJA DE ESCALERAS)
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 12 Ø 5/8" @ 20 cm
Dirección Menor:
As tranv = As * T As trv. = 27.63 cm²
S USAR As trv. = 27.63As mín = 0.0018 * S * d As mín = 22.45 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 14 Ø 5/8" @ 20 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm < 90.00 cm OK !!Lv1 =
8.500.001.277.50
12.43
1.00
As mín OK !!
1.981.597.50
13.9614
20.65
1.001.000.80
cm²
11.3412
20.76
ZAPATA "Z4" ENTRE EJES A-A Y 1-1 (CAJA DE ESCALERA )
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 25 cm γ t1 45.00 cm
t = 60 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 9.86 1.43 11.29Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 1 1 2γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 11.29 TnPu (envol) = 39.02 Tn
Ms = 2.00 Tn - mMu (envol)= 3.13 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 130.77 cm
T ' = Az^.5 + ( t - b ) S ' = 95.77 cm
2 e = 17.71 cm
S ' = Az^.5 - ( t - b )2 S = 131.19 cm
e = Ms Tomar S = 225.00 cm
PsS = S' + 2*e Lvb = 100 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 102.5 cm ser iguales (Lvb=Lvt)
2 Reales T = 260.00 cm
T = 2*m + t Tomar T = 265.00 cm
USAR S x T = 225X265 cm²
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
h t1 =
DATOS DEL SAP2000h t2 =
hc = 60.00 cm
DATOS DEL SAP2000
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
12829.55
b
t
ZAPATA "Z4" ENTRE EJES A-A Y 1-1 (CAJA DE ESCALERA )
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 44.17 cm > e =
q 1 = 0.27 kg/cm² = qm =q 2 = 0.11 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 8.01 cm
Pu T / 6 = 44.17 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 0.77 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 100.00 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
OK !!
17.71 cm
0.88 kg/cm²
OK !!
8.01 cm
0.05
8504.41
0.77
0.88 kg/cm²
87981.7274784.46 8504.41 OK !!kg
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z4" ENTRE EJES A-A Y 1-1 (CAJA DE ESCALERA )
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 11290 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 110.91 cm
n = 75.91 cm
Vu = kg
β c = 2.4bo = 373.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
866250
231981.41 32536.87 kg OK !!
100.00
32536.87
272919.3
866250225.0050.91
10.18255
20.62
20.62
As mín As req = As mín !!
1.98
0.5229
1.597.50
ZAPATA "Z4" ENTRE EJES A-A Y 1-1 (CAJA DE ESCALERA )
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 11 Ø 5/8" @ 20 cm
Dirección Menor:
As tranv = As * T As trv. = 25.64 cm²
S USAR As trv. = 25.64As mín = 0.0018 * S * d As mín = 20.62 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 13 Ø 5/8" @ 20 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm <
cm²
10.4211
20.84
1.00
As mín OK !!
1.981.597.50
12.9513
20.7
1.001.000.80
8.500.001.277.50
12.43
92.50 cm OK !!Lv1 =
ZAPATA "Z6" ENTRE EJES B-B Y 1-1, B-B Y 2-2
DATOS: MD,ML
Zapata PD, PL
f ' c = 210 kg/cm²Columna s/c = 300.00 kg/m²
f ' c = 210 kg/cm²b = 25 cm γ t1 45.00 cm
t = 60 cmAcero Df = 1.50 m
f y = 4200 kg/cm² Pm Pv Ps γ t2 45.00 cm
Suelo 16.76 3.15 19.91Df = 1.5 m Mm Mv Ms
γ t1 = 1.7 kg/m³ 1 1 2γ t2 = 1.7 kg/m³ Tqa = 1.050 kg/cm²
OtrosS/C = 300 kg/m²
Ps = 19.91 TnPu (envol) = 34.47 Tn
Ms = 2.00 Tn - mMu (envol)= 2.49 Tn - m
T
1.- DIMENSIONAMIENTO DE LA ZAPATA ( Az = S*T )Cálculo del peralte de la zapata (hc )
ld = 0.08 * Øb * Fy Øb ( 3/4" ) = 1.905 cm
f 'c^.5 ld = 44.17 cm
Tomar ld = 44.17 cm Longitud de desarrollo en compresión
r.e = 7.50 cm
hc = ld + r.e + Øb hc = 53.58 cm
ht = Df - hc Tomar hc = 60.00 cm
ht = 60.00 cm
Cálculo de la presión neta del suelo ( qm )
qm = 0.88 kg/cm²
Cálculo del área de la zapata ( Az )
A'z = Ps A'z = cm²
qm T ' = 167.92 cm
T ' = Az^.5 + ( t - b ) S ' = 132.92 cm
2 e = 10.05 cm
S ' = Az^.5 - ( t - b )2 S = 153.02 cm
e = Ms Tomar S = 160.00 cm
PsS = S' + 2*e Lvb = 67.5 cm Lvt y Lvb debenLvb =Lvt = S - b Dimens. Lvt = 67.5 cm ser iguales (Lvb=Lvt)
2 Reales T = 195.00 cm
T = 2*m + t Tomar T = 195.00 cm
USAR S x T = 160X195 cm²
hc = 60.00 cm
DATOS DEL SAP2000
S
qm = qa - γ t1*h t1 - γ t2*h t2 - γc*hc - s/c
22625
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
h t1 =
DATOS DEL SAP2000h t2 =
b
t
ZAPATA "Z6" ENTRE EJES B-B Y 1-1, B-B Y 2-2
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Verificación de las presiones ( q 1,2 )
e < T / 6 q 1, 2 = Ps * 1 ± 6*e = qm OK ! S*T T
T / 6 = 32.5 cm > e =
q 1 = 0.84 kg/cm² = qm =q 2 = 0.44 kg/cm² = qm =
2.- DETERMINACIÓN DE LA REACCIÓN AMPLIFICADA ( qmu )
e = Mu e = 7.22 cm
Pu T / 6 = 32.50 cm > e =T / 6
q 1u = kg/cm² qmu se toma el mayor valore < T / 6 q 2u = kg/cm²q 1u, 2u = Pu * 1 ± 6*e S*T T Tomar qmu = 1.35 kg/cm²
3.- VERIFICACION POR CORTE ( Ø = 0.85 )Por Flexión: d
Lv = ( T - t ) / 2 Lv = 67.50 cm
Vu = qmu * S * ( Lv - d ) r.e = 7.50 cm
Vc = 0.53 * f 'c^.5 * S * d Øb ( 5/8") = 1.59 cm
Vu = Øvc OK ! d = 50.91 cm qmuVu = kg
r.e = 7.5 c.m LvØb Vc = kg
d = hc - r.e - Øb Øvc = kg = Vu =
Por Punzonamiento:
Vu = Pu - qmu * m * n
Vc = 0.27 * 2 + 4 * f 'c^.5 * bo * d = 1.10 * f 'c^.5 * bo * d β c
β c = lado mayor columna ( t ) lado menor columna ( b )
m = t + dn = t + bbo = 2*m + 2*nVu = Øvc OK !
62564.7853180.06 3582.9 OK !!kg
OK !!
7.22 cm
0.09
3582.9
1.35
0.88 kg/cm²
OK !!
10.05 cm
0.88 kg/cm²
d/2
d/2
m = t+d
n =
b+
d
t
b
T
S
ZAPATA "Z6" ENTRE EJES B-B Y 1-1, B-B Y 2-2
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
Ps= PD+PL= 19910 Kg
-
n
qm = 0.88 kg/m²
m - = Kg
m = 110.91 cm
n = 75.91 cm
Vu = kg
β c = 2.4bo = 373.65 cm
Vc = 1.04 * f 'c^.5 * bo * d = kg
Øvc = kg = Vu =
4.- CALCULO DEL REFUERZO LONGITUDINAL ( Ø = 0.90 )Dirección Mayor:
Lv = ( T - t ) / 2 Lv = cm
Mu = qmu * S * Lv² Mu = kg - cm
2As = Mu / ( Ø * fy * ( d - a/2 ))a = As * fy / ( 0.85 * f 'c * S )
qmu
As mín = 0.0018 * S * d LvAs > As mín OK !!
Mu = kg - cm
Aøb S = cm
# Varilla ( n ) = As d = cm
Aøb a = cm (primera aprox.)As = cm²
Espaciam = S - 2*r.e - Øb a = cm
n -1USAR As mín = cm²
As req = cm²
As >Aøb ( 5/8" ) = cm²
Øb ( 5/8" ) = cm
r.e = cm
14.66
14.66
As mín As req = As mín !!
1.98
0.4176
1.597.50
492075160.0050.91
10.18252.84
23103.48
272919.3
492075
231981.41 23103.48 kg OK !!
67.50
ZAPATA "Z6" ENTRE EJES B-B Y 1-1, B-B Y 2-2
DISEÑO DE ZAPATA AISLADA EXCENTRICA CON CARGA CENTRADA
# Varilla ( n ) = Varillas# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 8 Ø 5/8" @ 20 cm
Dirección Menor:
As tranv = As * T As trv. = 19.3 cm²
S USAR As trv. = 19.3As mín = 0.0018 * S * d As mín = 14.66 cm²
As > As mín OK !!As trv >
Aøb# Varilla ( n ) = As Aøb ( 5/8" ) = cm²
Aøb Øb ( 5/8" ) = cm
r.e = cm
Espaciam = S - 2*r.e - Øb n -1 # Varilla ( n ) = Varillas
# Varilla ( n ) = Varillas
Espaciam. = cm
USAR 10 Ø 5/8" @ 19 cm
α =ld = Øb * fy * α ∗ β ∗ γ ∗ λ < Lv1 β = 3.54 * f 'c^.5 * C + Kr γ =
Øb λ =C =
Lv1 = Lv - r.e Kr =Øb (5/8") =
r.e = cm
ld = cm Longitud de desarrollo en tracción
ld = 12.43 cm < 60.00 cm OK !!Lv1 =
8.500.001.277.50
12.43
1.00
As mín OK !!
1.981.597.50
9.7510
19.82
1.001.000.80
cm²
7.418
20.49
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