ECE 438 Assignment No. 3 Spring 2018
f
f
f
Note that sinc(20f) has zero crossings at f=k/20 for integer k.
An alternate answer for (c)-i is
𝑋𝑐(𝑓) = sin(2πf10) / sin(2𝜋𝑓2) ∙ {𝑠𝑖𝑛𝑐(2(𝑓 − 1/4)) + 𝑠𝑖𝑛𝑐(2(𝑓 + 1/4))}
-8 -6 -4 -2 0 2 4 6 8 n
x[n]
t
x(t)
1/800 2/800 3/800 4/800
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