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Page 1: Time Series Analysis: Vector Error Correction Model …motegi/figs_ch6_VECM_kobe_v1.pdfFigure 1: Vector Error Correction Model (VECM) 2 Created Date 11/24/2016 2:22:36 AM ...

Time Series Analysis:

Vector Error Correction Model (VECM)

Kaiji Motegi∗

Fall 2016, Kobe University

1 Descriptions of Figure 1

Let ϵy1, . . . , ϵy100, ϵx1, . . . , ϵx100i.i.d.∼ N(0, 1). Consider a simple VECM:[

∆yt

∆xt

]=

[αy

αx

][1,−0.8]

[yt−1

xt−1

]+

[uyt

uxt

],

where uyt = ϵyt + 0.8ϵxt and uxt = ϵxt.

Panel 1: (αy, αx) = (−1, 0). {yt, xt} are cointegrated.

Panel 2: (αy, αx) = (0, 1). {yt, xt} are cointegrated.

Panel 3: (αy, αx) = (−1, 1). {yt, xt} are cointegrated.

Panel 4: (αy, αx) = (−1,−0.5). {yt, xt} are cointegrated.

Panel 5: (αy, αx) = (0, 0). {yt, xt} are not cointegrated.

Panel 6: (αy, αx) = (0.01,−0.01). {yt, xt} are not cointegrated.

∗Lecturer, Graduate School of Economics, Kobe University. E-mail: [email protected] Website:http://www2.kobe-u.ac.jp/˜motegi/

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Page 2: Time Series Analysis: Vector Error Correction Model …motegi/figs_ch6_VECM_kobe_v1.pdfFigure 1: Vector Error Correction Model (VECM) 2 Created Date 11/24/2016 2:22:36 AM ...

0 50 100-15

-10

-5

0

5

y x

1. (αy, αx) = (−1, 0)

0 50 100-10

0

10

20

30

y x

2. (αy, αx) = (0, 1)

0 50 100-10

0

10

20

y x

3. (αy, αx) = (−1, 1)

0 50 100-30

-20

-10

0

10

y x

4. (αy, αx) = (−1,−0.5)

0 50 100-20

-10

0

10

20

y x

5. (αy, αx) = (0, 0)

0 50 100-40

-20

0

20

40

y x

6. (αy, αx) = (0.01,−0.01)

Figure 1: Vector Error Correction Model (VECM)

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