ECE470 HOMEWORK #7 DUE: THURSDAY, MARCH 22, 2018

Problem 7.1 (P5-6 p. 246)

Answer:

Fe = Fe(λ, x) = − bλ2(x− d)

Problem 7.2 (P5-9 p. 247)

Answers:

(a) Fe = −µoa2N2I2dc

(g + b)2

(b) |Fe| = 256.5 N

Problem 7.3 (P5-10 p. 248)

(c) Obtain also an expression for the average steady-state electrical force Fe,avg using Irms = Im/√2.

Partial Answers:

(a) i(t) = Im sin(ωt− φ) =Vm√

R2 + (ωLo)2sin

(ωt− tan−1 ωLo

R

)(c) Fe,avg = −µoa

2N2I2rms

(go + b)2

Problem 7.4 (P5-14 p. 248)

Partial Answer:

(a) Fe = Fe(i, x) = − Ai2

2(B + x)2