PHYS1901 Physics 1 (Advanced) Formula...
Transcript of PHYS1901 Physics 1 (Advanced) Formula...
CC1531 Semester 1, 2015 Page 1 of 3
PHYS1901 Physics 1 (Advanced) Formula Sheet
Vectors~A = Axi + Ay j + Azk
A =∣∣∣~A∣∣∣ =
√A2
x + A2y + A2
z
~R = ~A + ~B = ~B + ~A
Rx = Ax + Bx, Ry = Ay + By, Rz = Az + Bz
~A · ~B = AB cos φ =∣∣∣~A∣∣∣ ∣∣∣~B∣∣∣ cos φ
~A · ~B = AxBx + AyBy + AzBz
~C = ~A× ~B, C = AB sin φ
Cx = AyBz − AzBy, Cy = AzBx − AzBz,
Cz = AxBy − AyBx
Kinematics~r = xi + yj + zk
~vav =~r2 −~r1
t2 − t1=
∆~r
∆t
~v = lim∆t→0
∆~r
∆t=
d~r
dt
vx =dx
dt, vy =
dy
dt, vz =
dz
dt
~aav =~v2 − ~v1
t2 − t1=
∆~v
∆t
~a = lim∆t→0
∆~v
∆t=
d~v
dt
ax =dvx
dt, ay =
dvy
dt, az =
dvz
dt
Mechanics∑~F = m~a, w = mg, ~FA on B = −~FB on A
fk = µkn, fs 6 µsn
~J = ~p2 − ~p1 =
t2∫t1
∑~F dt, M =
∑i
mi
~p = m~v,∑
~F =d~p
dt,
∑~Fext = M~acm
~P = m1~v1 + m2~v2 + m3~v3 + . . . = M~vcm
~rcm =
∑i
mi~ri∑i
mi
=m1~r1 + m2~r2 + m3~r3 + . . .
m1 + m2 + m3 + . . .
Simple motionsConstant acceleration in one direction:v = v0 + at
x = x0 + v0t +1
2at2
v2 = v20 + 2a(x− x0)
x− x0 =
(v0 + v
2
)t
Projectile motion:x = (v0 cos α0)t
y = (v0 sin α0)t−1
2gt2
v = v0 cos α0
vy = v0 sin α0 − gt
Uniform circular motion:
arad =v2
R= ω2R =
4π2R
T 2
CC1531 Semester 1, 2015 Page 2 of 3
Work and EnergyW = ~F ·~s = Fs cos φ
K =1
2mv2, U = mgy
Wtot = K2 −K1 = ∆K
W =
∫ x2
x1
Fx dx
W =
∫ P2
P1
F cos φ dl =
∫ P2
P1
F‖ dl =
∫ P2
P1
~F · d~l
Pav =∆W
∆t
P = lim∆t→0
∆W
∆t=
dW
dt= ~F · ~v
Wel =1
2kx2
1 −1
2kx2
2 = −∆Uel
Wgrav = mgy1 −mgy2 = −∆Ugrav
E = K + U
Fx(x) = −dUx
dx
~F = −(
∂U
∂xi +
∂U
∂yj +
∂U
∂zk
)
Periodic Motion
ω = 2πf =2π
T, f =
ω
2π=
1
T
ω =
√k
m, ω =
√κ
I
ω =
√g
L, ω =
√mgd
I
Fx = −kx, ax =Fx
mx = A cos(ωt + φ)
E =1
2mv2
x +1
2kx2 =
1
2kA2 = constant
x = Ae−(b/2m)t cos ω′t, ω′ =
√k
m− b2
4m2
bcritical = 2√
k m
A =Fmax√
(k −mω2d)
2+ b2ω2
d
Rotational Motion
ωz = limx→0
∆θ
∆t=
dθ
dt
αz = limx→0
∆ωz
∆t=
dωz
dt=
d2θ
dt2
arad =v2
r= ω2r, atan =
dv
dt= r
dω
dt= rαz
v = rωz, IP = Icm + Md2, vcm = Rω
I = m1r21 + m2r
22 + . . . =
∑i
mir2i
τ = F l = rF sin θ, ~τ = ~r× ~F∑τz = Iαz,
∑~τ =
d~L
dt
K =1
2Mv2
cm +1
2Icmω2
z , P = τzωz
W =
∫ θ2
θ1
τz dθ, Wtot =1
2Iω2
2 −1
2Iω2
1
~L = ~r× ~p = ~r×m~v (particle)~L = I~ω (rigid body)I = MR2 (thin hollow cylinder)
I =1
2MR2 (solid cylinder)
I =2
5MR2 (solid sphere)
Newtonian Gravitation
Fg =Gm1m2
r2, g =
GmE
R2E
w = Fg =GmEm
R2E
, v =
√GmE
r
U = −GmEm
r, RS =
2GM
c2
T =2πr
v=
2πr3/2
√GmE
CC1531 Semester 1, 2015 Page 3 of 3
Thermal physics∆L = αL0∆T, ∆V = βV0∆T
Q = mc∆T, Q = nC∆T, Q = ±mL
pV = nRT = NkT N = nNA
CV =3
2R (ideal monatomic gas)
CV =5
2R (ideal diatomic gas)
CV = 3R (ideal monatomic solid)
CP = CV + R, γ =CP
CV
vrms =
√3RT
M
mtot = nM = nNAm
e =W
QH
= 1 +QC
QH
= 1−∣∣∣∣QC
QH
∣∣∣∣eCarnot = 1− TC
TH
=TH − TC
TH
KCarnot =TC
TH − TC
eOtto = 1− 1
rγ−1
Ktr =3
2nRT,
1
2m(v2)av =
3
2kT
Mechanical waves
v = λf, k =2π
λ
ω = 2πf = vk, v =
√F
µ
y(x, t) = A cos(kx± ωt)
y(x, t) = (ASW sin kx) sin ωt (standing wave)String fixed at both ends:
fn = nv
2L= nf1 (n = 1, 2, 3, . . .)
f1 =1
2L
√F
µ
β = (10 dB) logI
I0
W =
∫ V2
V1
p dV, ∆U = Q−W
dU = dQ− dW (infinitesimal process)
K =|QC ||W |
=|QC |
|QH | − |QC |
∆S =
∫ 2
1
dQ
T(reversible process), S = k ln w
H =dQ
dt= kA
TH − TC
L, Hnet = Aeσ(T 4 − T 4
s )
W = nCV (T1 − T2)
=CV
R(p1V1 − p2V2) (adiabatic process, ideal gas)
=1
γ − 1(p1V1 − p2V2)
W = nRT ln
(V2
V1
)
Reversible Processes for Ideal Gases:Adiabatic (no heat transfer):
Q = 0, pV γ = constantIsochoric (constant volume): W = 0
Isobaric (constant pressure): W = p(V2 − V1)
Isothermal (constant temperature)
Longitudinal sound waves
v =
√B
ρ(fluid), v =
√Y
ρ(solid rod)
v =
√γRT
M(ideal gas)
fn =nv
2L(n = 1, 2, 3, . . .) (open pipe)
fn =nv
4L(n = 1, 3, 5, . . .) (stopped pipe)
fL =v + vL
v + vS
fs, sin α =v
vS
fbeat = |fa − fb|