Phys 218 — Exam III Formulae - Texas A&M...
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Transcript of Phys 218 — Exam III Formulae - Texas A&M...
Gravity:
~Fgrav = −GM1M2
R212
r Ugrav = −GM1M2
R12
T =2πa3/2
√GM
Centre-of-mass:
~rcm =m1~r1 + m2~r2 + . . . + mn~rn
m1 + m2 + . . . + mn
(and similarly for ~v and ~a)
Forces: Newton’s:∑ ~F = m~a, ~FB on A = −~FA on B
Hooke’s: ~Felas = −k(r − requil)r
friction: |~fs| ≤ µs|~n|, |~fk| = µk|~n|
Constants/Conversions:
g = 9.80 m/s2
= 32.15 ft/s2
(on Earth’s surface)
G = 6.674 × 10−11 N · m2/kg2
R⊕ = 6.38 × 106 m M⊕ = 5.98 × 1024 kgR⊙ = 6.96 × 108 m M⊙ = 1.99 × 1030 kg
1 km = 0.6214 mi 1 mi = 1.609 km
1 ft = 0.3048 m 1 m = 3.281 ft
1 hr = 3600 s 1 s = 0.0002778 hr
1 kgms2
= 1 N = 0.2248 lb 1 lb = 4.448 N
1 J = 1 N·m 1 W = 1 J/s
1 rev = 360◦ = 2π radians 1 hp = 745.7 W
Relative velocity: ~vA/C = ~vA/B + ~vB/C
~vA/B = −~vB/A
Circular motion: |~arad| =v2
RT =
2πR
v
s = Rθ vtan = Rω atan = Rα
Forces, Energy and Momenta:
translational rotational
Ktrans = 12Mv2
cm
W =∫
~F · d~r const−−−→force
~F · ∆~r
P = dWdt = ~F · ~v
~pcm = m1~v1 + m2~v2 + . . .
= M~vcm
~J =∫
~Fdt = ∆~p
∑ ~Fext = M~acm =d~pcm
dt∑ ~Fint = 0
~τ = ~r × ~F and |~τ | = F⊥r
Krot = 12Itotω
2
W =∫
τdθconst−−−−→torque
τ ∆θ
P = dWdt = ~τ · ~ω
~L = I1~ω1 + I2~ω2 + . . .
= Itot~ω
= ~r × ~p
∑
~τext = Itot~α =d~L
dt∑
~τint = 0
—– Both translational and rotational —–
W = ∆K = Ktrans,f + Krot,f − Ktrans,i − Krot,i
Etot,f = Etot,i + Wother ⇔ Kf + Uf = Ki + Ui + Wother
U = −∫
~F · d~r ; Ugrav = Mgycm ; Uelas = 12k(r − requil)
2
Fx(x) = −dU(x)/dx ~F = −~∇U = −[
∂U∂x i + ∂U
∂y j + ∂U∂z k
]
Equations of motion:
translational rotational
—– constant (linear/angular) acceleration only —–
~r(t) = ~r◦ + ~v◦t + 12~at2
~v(t) = ~v◦ + ~at
v2x = v2
x,0 + 2ax(x − x0)(and similarly for y and z)
~r(t) = ~r◦ + 12(~vi + ~vf )t
θ(t) = θ◦ + ω◦t + 12αt2
ω(t) = ω◦ + αt
ω2f = ω2
◦ + 2α(θ − θ◦)
θ(t) = θ◦ + 12(ωi + ωf )t
———– always true ———–
〈~v〉 = ~r2−~r1
t2−t1~v = d~r
dt
〈~a〉 = ~v2−~v1
t2−t1~a= d~v
dt = d2~rdt2
~r(t) = ~r◦ +∫ t
0~v(t′) dt′
~v(t) = ~v◦ +∫ t
0~a(t′) dt′
〈ω〉 = θ2−θ1
t2−t1ω = dθ
dt
〈α〉 = ω2−ω1
t2−t1α= dω
dt = d2θdt2
θ(t) = θ◦ +∫ t
0~ω(t) dt
ω(t) = ω◦ +∫ t
0~α(t) dt
General math:
ha
hho
φ
θ
ha = h cos θ = h sin φ
ho = h sin θ = h cos φ
h2 = h2a + h2
o tan θ =ho
ha
~A = Axi + Ay j + Az k
~A · ~B = AxBx + AyBy + AzBz = AB cos θ = A‖B = AB‖
~A × ~B = (AyBz−AzBy )i + (AzBx−AxBz)j + (AxBy−AyBx)k
= AB sin θ = A⊥B = AB⊥
df/dt = natn−1
If f(t) = atn, then
∫ t2t1
f(t)dt = an+1
(tn+12 − tn+1
1 ) (for n 6= −1)∫
f(t)dt = an+1
tn+1 + C (for n 6= −1)
ax2 + bx + c = 0 ⇒ x =−b ±
√b2 − 4ac
2a
Phys 218 — Exam III Formulae
à For a point-like particle of mass M a distance R from the axis of rotation: I = MR2
à Parallel axis theorem: Ip = Icm + Md2