p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ]

p : 3946183951 A : 537680305 B : 1059676324 G E : [1152222263 3133703258] N G : 3946206427 ε : 100 : [3539395206 1802765602] Plaintext : Mat Kunci 32 bit lpesan Panjang pesan = 3 (banyaknya karakter bpesan ceil ( (32/8) – 1 ) = 3 (dipotong set ipesan ceil (lpesan / bpesan) = 3/3 = 1 (pemot

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CONTOH PERHITUNGAN. ENKRIPSI. p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ] N G : 3946206427 ε : 100 : [ 3539395206 1802765602 ] Plaintext : Mat. Kunci 32 bit. lpesan  Panjang pesan = 3 (b anyaknya karakter plaintext ) - PowerPoint PPT Presentation

Transcript of p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ]

Page 1: p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ]

p : 3946183951A : 537680305B : 1059676324GE : [1152222263 3133703258]NG : 3946206427ε : 100

: [3539395206 1802765602]Plaintext : Mat

Kunci 32 bit

lpesan Panjang pesan = 3 (banyaknya karakter plaintext)

bpesan ceil ( (32/8) – 1 ) = 3 (dipotong setiap 3 karakter)

ipesan ceil (lpesan / bpesan) = 3/3 = 1 (pemotongan pesan)

Page 2: p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ]

M ASCII 77 Biner 1001101 Biner 8 bit 01001101

a ASCII 97 Biner 1100001 Biner 8 bit 01100001

t ASCII 116 Biner 1110100 Biner 8 bit 01110100

Desimal5071220

pesan: Mat

Page 3: p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ]

pesan: Mat

m = 5071220

xj = m. ε + j , j [0, ε -1] Sj = xj3 + A.xj + B (mod p)

yj = akar dari Sj PM = (xj , yj)

x0 = 5071220(100)+0 = 507122000 S0 = 211020104y0 = akar S0 =Tdk memiliki akar. S0

(p-1)/2 = -1(mod p)x1 = 5071220(100)+1 = 507122001 S1 =3164013225y1 = akar S1 =Tdk memiliki akar. S1

(p-1)/2 = -1(mod p)x2 = 5071220(100)+2 = 507122002 S2 =1267370450y2 = akar S2 =Tdk memiliki akar. S2

(p-1)/2 = -1(mod p)

x3 = 5071220(100)+3 = 507122003 S3 = 2413459687y3 = akar S3 = 3301895794 dan 644288157 Titiknya (507122003 , 3301895794) dan (507122003 , 644288157)………… sampai j= ε -1=99.Dipilih 1 titik ( PM ) ( 507122095 , 1075291432)

Dipilih j [0, ε -1] = [0, 99] j = 95x95 =5071220(100)+82=507122003 S95 =375659790y95 = akar S95 = 1075291432 dan 2870892519 Titiknya (507122095 , 1075291432) dan (507122095 , 2870892519)Dipilih 1 titik ( PM ) ( 507122095 , 1075291432)

Page 4: p: 3946183951 A: 537680305 B: 1059676324 G E : [ 1152222263 3133703258 ]

pesan: Mat

PM = ( 507122082 , 307629979 )

m = 5071220

ENKRIPSI ElGamal ECC

k [1, NG – 1] = [1,3946206426] 912120288P1 = k.GE = (3227285189 , 2965666882)P2 = PM + k. = PM + (736261778 , 2068514041) = (3828826938 , 1504649631)

PC = (P1,P2) = ((3227285189, 2965666882) , (3828826398,1504649631))PC = ( 3227285189 2965666882 3828826398 1504649631 )

N-channel 75 V, 0.0095 , 80 A TO-220, D²PAK, I²PAK ... · D D.U.T. S B G 25 Ω A A B B RG G FAST DIODE D ... ∅P 3.75 3.85 Q 2.65 2.95 0015988_Rev_S. STB76NF75, STI76NF75, STP76NF75

Operating Instructions Air Conditionernordvarme.dk/pdf/d_ne7_9_12gke.pdfQ U I C K U G U I D E / S N A B B G U I D E G U I A R Á P I D O / Á P Q UI C K D E / G U Í A R Á P I D A

BJ REALNA TEKU ĆINA - unizg.hr€¦ · Moodyjev dijagram m UL D Bernoullijeva jednadžba izme đu presjeka uzvodnog i nizvodnog E E E p v p v z z h g g g g p v v L g g g − = =

$N B O G > Y I I M K - cea.org.cy€¦ · ' d k g = \ m d i b h r o m k g h _ b k d j b o x r g h _ a b i r \ m b k z o @ b g = " v o [ p d = k = k b c p g j x k n d @ c k b k z o$