Objectives
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Transcript of Objectives
Objectives
- Finish heat exchangers
- Air Distribution Systems - Diffuser selection- Duct design
- fluid dynamics review
Fin Efficiency
• Assume entire fin is at fin base temperature• Maximum possible heat transfer• Perfect fin
• Efficiency is ratio of actual heat transfer to perfect case
• Non-dimensional parameter
Heat exchanger performance (11.3)
• NTU – absolute sizing (# of transfer units)• ε – relative sizing (effectiveness)
Criteria
NTU
ε P RP
cr
hphcpc cmcm ,, hphcpc cmcm ,,
cpc
oocmAU
,
hph
cpc
cmcm
,
,
hph
oocmAU
,
cpc
hph
cmcm
,
,
Example problem
For the problem 9 HW assignment # 2 (process in AHU) calculate:a) Effectiveness of the cooling coilb) UoAo value for the CCInlet water temperature into CC is coil is 45ºF
AHU
M CC
steamRA
OA
Qcc=195600Btu/h
tM=81ºF
tCC=55ºF
CC
(mcp)w
tc,in=45ºF
Summary
• Calculate efficiency of extended surface• Add thermal resistances in series• If you know temperatures
• Calculate R and P to get F, ε, NTU• Might be iterative
• If you know ε, NTU• Calculate R,P and get F, temps
Reading Assignment
• Chapter 11- From 11.1-11.7
Analysis of Moist Coils
1. Redo fin theory 2. Energy balance on fin
surface, water film, airIntroduce Lewis Number
3. Digression – approximate enthalpy
4. Redo fin analysis for cooling/ dehumidification (t → h)
Overall Heat Transfer Coefficients
• Very parallel procedure to dry coil problem• U-values now influenced by condensation• See Example 11.6 for details
Air Distribution System Design
• Describe room distribution basics
• Select diffusers• Supply and return
duct sizing
Forced driven air flowDiffusers
Linear diffusersGrill (side wall)
diffusers
Horizontal one side
Vertical
Diffusers types
swirl diffusers
wall or ceiling
floor
Valve diffuser
ceiling diffuser
Diffusers
http://www.titus-hvac.com/techzone/http://www.halton.com/halton/cms.nsf/www/diffusers
Perforated ceiling diffuser Jet nozzle diffuser Square conical ceiling diffuser Round conical ceiling diffuser
Wall diffuser unit Swirl diffuser Floor diffuser Auditorium diffuser
DV diffuser External louvre Smoke damper Linear slot diffuser
Low mixing Diffusers Displacement ventilation
18.7
Diffuser Selection Procedure
• Select and locate diffusers, divide airflow amongst diffusers
V = maximum volumetric flow rate (m3/s, ft3/min)Qtot = total design load (W, BTU/hr)Qsen = sensible design load (W, BTU/hr)ρ = air density (kg/m3, lbm/ft3)Δt = temperature difference between supply and return air (°C, °F)Δh = enthalpy difference between supply and return air (J/kg, BTU/lbm)
ΔtQ
ΔhQV sentot
Find Characteristic Length (L)
Indicator of Air DistributionQuality
• ADPI = air distribution performance index• Fraction of locations that meet criteria:
• -3 °F < EDT < 2 °F or -1.5 °C < EDT < 1 °C• Where, EDT = effective draft temperature
• Function of V and Δt (Eqn 18.1)
• EDT=(tlocal-taverage)-M(Vlocal-Vaverage) , M=7 °C/(m/s)
ADPI considers ONLY thermal comfort (not IAQ)
Ideal and Reasonable Throws
Select Register
• Pick throw, volumetric flow from register catalog• Check noise, pressure drop
Summary of Diffuser Design Procedure
1) Find Q sensible total for the space
2) Select type and number of diffusers 3) Find V for each diffuser 4) Find characteristic length5) Select the diffuser from the manufacturer data
Example 18.3
• Qtot = 38.4 kBTU/hr
• Δh = 9.5 BTU/lbma
ΔtCQ
ΔhQV
p
sentot
omission in text
Pressures
• Static pressure
• Velocity pressure
• Total pressure – sum of the two above
Relationship Between Static and Total Pressure
2
22
21 VVPP st
• Total and static pressure drops are proportional to square of velocity
• Plot of pressure drop vs. volumetric flow rate (or velocity) is called system characteristic
Duct Design
gDLVf
2
2 sPD
LVfg 2
2
System Characteristic
Electrical Resistance Analogy
Frictional Losses
Non-circular Ducts
• Parallel concept to wetted perimeter
Dynamic losses
• Losses associated with• Changes in velocity• Obstructions• Bends• Fittings and transitions
• Two methods• Equivalent length and loss coefficients
Loss Coefficients 20
1
0
1
VV
CCΔPt = CoPv,0
Example 18.7
• Determine total pressure drop from 0 to 4
Conversion Between Methods
fDCL
gVC
gDVL
f
eq
eq
0
20
2
22
Reading asignement
• Chapter 18• 18.1-18.4 (including 18.4)