M20 BOYLXXXX 20 IM CH20 - usna.edu _Textbook_Sol/HW21 Powe… · CHAPTER 20 Chapter 20 19. a. P T =...

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Transcript of M20 BOYLXXXX 20 IM CH20 - usna.edu _Textbook_Sol/HW21 Powe… · CHAPTER 20 Chapter 20 19. a. P T =...

Page 1: M20 BOYLXXXX 20 IM CH20 - usna.edu _Textbook_Sol/HW21 Powe… · CHAPTER 20 Chapter 20 19. a. P T = 5 kW, Q T = 6 kVAR(L) S T = = 7.81 kVA b. F ... Title: M20_BOYLXXXX_20_IM_CH20

CHAPTER 20

Chapter 20

19. a. PT = 5 kW, QT = 6 kVAR(L)

ST = = 7.81 kVA

b. Fp = = 0.640 (lagging)

c. Is = = 65.08 A

d. XC =1

2 pfC, QC = I2XC =

and XC = = 2.4 Ω

C = = 1105 µF

e. ST = EIs = PT

Is = = 41.67 A