[EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

8
(J 1 ) 1 (J 1 ) 2 I C n 1 n 2 1 n 1 n 2 2 = n 1 n 2 1 I SARE Δ λ Δ I C Δ

Transcript of [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

Page 1: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(J1)1  (J1)2 

IC 

n1n2

1

n1n2

2

=n1n2

1

ISARE 

Δ  λ 

Δ 

IC 

Δ 

Page 2: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(V13)1

(V13)2

30o

Page 3: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(VL)1

IS1

IC

D1

D3

RL

IS2

IS3 €

23IC

13IC

IS1 =23IC

IS2 = −13IC

IS3 = −13IC

(V13)1

23IC

(Is1)1

(Is3)1

−23IC

−13IC €

13IC

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

Page 4: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(Is1)1

(Is3)1

IS1

IC

D1

D3

RL

IS2

IS3

23IC

13IC

IS1 =13IC

IS2 =13IC

IS3 = −23IC

(V23)1

23IC

23IC

13IC

13IC

−13IC

−13IC

−23IC

−23IC

(VL)1

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

Page 5: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(Is1)1

(Is3)1

IS1

IC

D1

D2

RL IS2

IS3 €

23IC

13IC

(V12)1

IS1 =13IC

IS2 = −23IC

IS3 =13IC

23IC

23IC

13IC

13IC

−13IC

−13IC

−23IC

−23IC

(VL)1

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

Page 6: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(Ip3)1

(Ip1)1

(J1)1 = (Ip1)1 - (Ip3)1

30 60 90 120 150 180 210 240 270 300 330 360

Δ

(J1)1

n1n2

1

IC

Δ

23x

23x

13x

13x

−13x

−13x

−23x

−23x

−x

x

Page 7: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

(J1)2 

IC 

λ 

n1n2

2

=n1n2

1

(Is1)2

23IC

13IC

−13IC

−23IC

(VL)2

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

Δ

(V32)1

(J1)2 = (Ip1)2

23x

13x

−13x

−23x

Page 8: [EP] IKASGELAKO PRAKTIKA (2010/03/10) ariketa (ebazpena)

ISARE €

53x

30 60 90 120 150 180 210 240 270 300 330 360

(J1)2

(J1)1

ISARE =12π

⋅ 2 ⋅ 2π3⋅ 2x( )2

=

12π

⋅ 2 ⋅ π3⋅53x

2

+ 2 ⋅ π3⋅43x

2

+ 2 ⋅ π3⋅ x( )2

= x ⋅ 13⋅259

+13⋅169

+13⋅19

= x ⋅ 1

3⋅259

+13⋅169

+13⋅19

= x ⋅ 42

27

ISARE =143

⋅n2n1

1

⋅ IC

−x

x

23x

13x

−13x

−23x

43x

13x